Nested Loop for C Programming - c

Question

I have some problem about Nested Loop on C programming
I tried to print the list like this:
| |0|1|2|3|4|5|6|7|8|9|
|0| | | | | | | | | | |
|1| | | | | | | | | | |
|2| | | | | | | | | | |
|3| | | | | | | | | | |
|4| | | | | | | | | | |
|5| | | | | | | | | | |
|6| | | | | | | | | | |
|7| | | | | | | | | | |
|8| | | | | | | | | | |
|9| | | | | | | | | | |
but there are something problem when i type my code and display:
| |0|1|2|3|4|5|6|7|8|9|
|0|0|0|0|0|0|0|0|0|0|0|
|1|0|1|1|1|1|1|1|1|1|1|
|2|0|2|2|2|2|2|2|2|2|2|
|3|0|3|3|3|3|3|3|3|3|3|
|4|0|4|4|4|4|4|4|4|4|4|
|5|0|5|5|5|5|5|5|5|5|5|
|6|0|6|6|6|6|6|6|6|6|6|
|7|0|7|7|7|7|7|7|7|7|7|
|8|0|8|8|8|8|8|8|8|8|8|
|9|0|9|9|9|9|9|9|9|9|9|
There is my code :
void displayBoard(Cell board[BOARD_HEIGHT][BOARD_WIDTH], Player * player)
{
int i, j;
printf("| ");
for (j = 0; j < BOARD_WIDTH; j++)
{
printf("|%d",j);
}
printf("|\n");
for (i = 0; i < BOARD_HEIGHT; i++)
{
for (j = 0; j < BOARD_WIDTH; j++)
{
printf("|%d",i);
if (j == 0)
{
printf("|%d",j);
}
}
printf("|\n");
}
printf("\n");
}
Have someone can help for this condition: only one row and one column, other is empty.

Answer 1

At no point in the body of the inner loop are you printing spaces. You're instead printing the value of i, which is the column number.
printf("|%d",i);
if (j == 0)
{
printf("|%d",j);
}
Instead, print i only on the first iteration and print the space each time:
if (j == 0) {
printf("|%d",i);
}
printf("| ");
Output:
| |0|1|2|3|4|5|6|7|8|
|0| | | | | | | | | |
|1| | | | | | | | | |
|2| | | | | | | | | |
|3| | | | | | | | | |
|4| | | | | | | | | |
|5| | | | | | | | | |
|6| | | | | | | | | |
|7| | | | | | | | | |
|8| | | | | | | | | |

Answer 2

The key to getting this done correct is enclosing the repeating logic (the blank cells) in the loop while confining the specialized logic to be outside the loop:
void displayBoard(int height, int width)
{
int i, j;
printf("| ");
for (j = 0; j < width; j++) {
printf("|%d", j);
}
printf("|\n");
for (i = 0; i < height; i++) {
printf("|%d", i);
for (j = 0; j < width; j++) {
printf("| ");
}
printf("|\n");
}
}
Look mom! no ifs

Answer 3

This is how you should code it:
void displayBoard(Cell board[BOARD_HEIGHT][BOARD_WIDTH], Player * player)
{
int i, j;
printf("| ");
for (j = 0; j < BOARD_WIDTH; j++)
{
printf("|%d",j);
}
printf("|\n");
for (i = 0; i < BOARD_HEIGHT; i++)
{
for (j = 0; j < BOARD_WIDTH; j++)
{
if (j == 0)
{
printf("|%d",i);
}
printf("| ");
}
printf("|\n");
}
printf("\n");
}
There are couple of issues with your current code:
You printf("|%d",i); in the inner loop for every j while what you really want is just to print it when j == 0 once. The rests, you want to printf("| "):
printf("| "); //you want to make this blank
if (j == 0)
{
printf("|%d",i); //you want to print i here, not j
}
between the print of number when j == 0 and the print of blank should be reversed:
if (j == 0)
{
printf("|%d",i); //you want to print i here, not j
}
printf("| "); //put the blank printing after the number

Answer 4

You are printing the number i in every line, when you want a blank or the array data. you also need to get rid of printing a zero every row, which is what you have coded in. Here is that part of the code corrected:
for (i = 0; i < BOARD_HEIGHT; i++)
{
for (j = 0; j < BOARD_WIDTH; j++)
{
if (j == 0)
{
printf("|%d",i);
}
printf("| "); ///or printf("|%d",board[i][j]) if you are after stored data
}
printf("|\n");
}
hope this helps.

Answer 5

Try this:
#define BOARD_HEIGHT 10
#define BOARD_WIDTH 10
void displayBoard()
{
int i, j;
printf("| ");
for (j = 0; j < BOARD_WIDTH; j++)
{
printf("|%d", j);
}
printf("|\n");
for (i = 0; i < BOARD_HEIGHT; i++)
{
printf("|%d", i);
for (j = 1; j < BOARD_WIDTH; j++)
{
printf("| ");
}
printf("| |\n");
}
}
BTW, there is no need to pass any arguments to this function.