web-proxy for angularjs application - angularjs

Question

I have to create a web-proxy script for my angularjs files because I got the error of CORS(Cross Origin Request Method) and I dont have any options to use Access Control Allow Origin because I cant make any changes to my server end.
My backend data is in java. So please someone tell me how to make a web-proxy for my angularjs application.
Or is there anyway to bypass the cors request from my browser.

Answer 1

A quick work around using foreach and json_decode.
If your print_r($json) comes in this format:
Array
(
[0] => Array
(
[studentid] => 5
[firstame] => jagdjasgd
[lastname] => kjdgakjd
[gender] => 1
[email] => dgahsdg#em.com
[fathername] => hashsdh
[mothername] => djhavshd
[birthday] => 2016-03-21
[address] => gafdhfadhs
[tenth] => 45.235
[twelfth] => 56.25
)
)
This will do the trick:
if ($_SERVER['REQUEST_METHOD'] == 'POST')
{
$json = json_decode(file_get_contents("php://input"), true);
//print_r($json);
$data =array();//Open blank array for student data
$num = array();//Open Blank array for number of student
foreach($json as $k => $v):
$num [] = $v; //number of student
if(is_array($v)){
foreach($v as $key=>$val):
$data[$key] = $val;//Student data
endforeach;
}
endforeach;
$row= count($num);//Put number of student in $row
for($i=1; $i<=$row; $i++){
$q = 'INSERT INTO table (`col1`)
VALUES($data['studentid'])';//Looping through sql statement
}
Hope this will help.

Answer 2

User json_decode with true params
$data = "{"studentid":"5","firstame":"jagdjasgd","lastname":"kjdgakjd","email":"dgahsdg#em.com"}";
$d = json_decode($data,true); // true means it will result in aaray
print_r($d);
$stdId = $d['studentid'];
$fname = $d['firstname'];
$lname = $d['lastname'];
$mail = $d['email'];
EDIT:
For multiple json data:
$data = '[
{
"0": "1",
"studentid": "1",
"1": "David",
"firstname": "David",
"2": "Beckham",
"lastname": "Beckham",
"3": "1",
"gender": "1",
"4": "david123#gmail.com",
"email": "david123#gmail.com",
"5": "Beckham",
"fathername": "Beckham",
"6": "Beckhamii",
"mothername": "Beckhamii",
"7": "2016-03-13",
"birthday": "2016-03-13",
"8": "dgasdhghasd\nkajsdgjaksdh\nkahdgjaksgdas",
"address": "dgasdhghasd\nkajsdgjaksdh\nkahdgjaksgdas",
"9": "58.25",
"tenth": "58.25",
"10": "62.25",
"twelfth": "62.25"
},
{
"0": "3",
"studentid": "3",
"1": "Chris",
"firstname": "Chris",
"2": "Gayle",
"lastname": "Gayle",
"3": "1",
"gender": "1",
"4": "chrisgayle#email.com",
"email": "chrisgayle#email.com",
"5": "Chris Potters",
"fathername": "Chris Potters",
"6": "Christine",
"mothername": "Christine",
"7": "2016-04-20",
"birthday": "2016-04-20",
"8": "adhafsdh\njgadahksgdkjas\njagdjahsdlkajsld\nkajsgdjlahsdlkas",
"address": "adhafsdh\njgadahksgdkjas\njagdjahsdlkajsld\nkajsgdjlahsdlkas",
"9": "87.587",
"tenth": "87.587",
"10": "98.256",
"twelfth": "98.256"
},
{
"0": "5",
"studentid": "5",
"1": "jagdjasgd",
"firstname": "jagdjasgd",
"2": "kjdgakjd",
"lastname": "kjdgakjd",
"3": "1",
"gender": "1",
"4": "dgahsdg#em.com",
"email": "dgahsdg#em.com",
"5": "hashsdh",
"fathername": "hashsdh",
"6": "djhavshd",
"mothername": "djhavshd",
"7": "2016-03-21",
"birthday": "2016-03-21",
"8": "gafdhfadhs\nagdkjashdas\ndjkahsdklsaj",
"address": "gafdhfadhs\nagdkjashdas\ndjkahsdklsaj",
"9": "45.235",
"tenth": "45.235",
"10": "56.25",
"twelfth": "56.25"
}
]';
$json = json_decode($data, true);
echo '<pre>';
foreach ($json as $key => $value) {
echo "StudentID: ".$value['studentid']."<br>";
}
Output:
StudentID: 1
StudentID: 3
StudentID: 5

Answer 3

Decode ur array like below..
$newarr= json_decode('urjsonstring');
extract($newarr);
$query="insert into stud values($studentid, $firstname,$lastname...)";