String compare in C for a password - c

Question

void main()
{
Password();
}
int Password()
{
// Declare local variables//
char cPassCode[] = "String";
int iFlag, iComparison = 0;
// Run the code to check the password//
while (iFlag = 0)
{
printf("Please enter the password: ");
scanf("%s", cPassCode);
iComparison = strcmp(cPassCode, "A23bc5");
if (iComparison = 0)
{
ArrayPrinter(Array);
iFlag = 1;
}
else
{
printf("Wrong password");
iFlag = 0;
}
return(iFlag);
}
}
I edited the section of code and as far as I can tell it should run properly when the password A23bc5 is entered. However it is always returning a wrong password. Any ideas?

Answer 1

strcmp function returns 0 if the strings are equal. You should edit the condition block.
Edit:
Actually you have also very basic syntax problems.
int Password()
{
//declare local variables//
char cPassCode[] = "String";
int iFlag=0, iComparison = 0;
//Run the code to check the password//
while (iFlag == 0)
{
printf("Please enter the password: ");
scanf("%s", cPassCode);
iComparison = strcmp(cPassCode,"A23bc5");
if (iComparison == 0)
{
printf("\n Accepted");
iFlag = 1;
}
else
{
printf("Wrong password");
iFlag = 0;
}
return(iFlag);
}
}
int main()
{
Password();
return 0;
}
This will work

Answer 2

if (iComparison = 0)
Is assigning 0 to the variable and then testing it, and 0 evaluates to false.
if (iComparison == 0)
Is checking if the variable is 0, which is probably what you meant

Answer 3

//String compare in C for a password Until 5 try//
#include<stdio.h>
#include<string.h>
int main(){
int i,value;
char pass[10],id[10],key[]="1234";
printf("enter your id: ");
scanf("%s", id);
for(i=5;i>=0;i--){
printf("\nenter your password: ");
scanf("%s",pass);
value=strcmp(pass,key);
if(value==0){
printf("matched");
return 0 ;
}
else{
printf("not matched you have %d try left", i);
}
}
return 0;
}