Is there a way to help me on counting the chair that had appear on Monday,Tuesday, and Wednesday instead of the number of the chairs appear in the table?
I expect to get the count of the chair depends on the Order Column instead of the whole table, so the answer will be 3(the chair had appear in monday,tuesday and wednesday) instead of the total number of the chair had appear in the table
use count (distinct column name)
SELECT COUNT ( DISTINCT Order )
FROM yourtable
WHERE Stuff = 'Chair'
EDIT :
I have another question, can it show which Order it has been appear?
like the out put is 3 times follow by (Monday,Tuesday,Wednesday) , is
it possible to show the Order follow by the total count number? or in
other line
is this what you wanted ?
SELECT Order, COUNT (*)
FROM yourtable
WHERE Stuff = 'Chair'
GROUP BY Order
or perhaps this ?
SELECT COUNT ( DISTINCT Order ),
STUFF ((SELECT ',' + Order
FROM yourtable
WHERE Stuff = 'Chair'
GROUP BY Order
FOR XML PATH ('')),
1, 1, '')
FROM yourtable
WHERE Stuff = 'Chair'
Related
I have a table in report like
I want to show the records in three tables on every page, each table contains only 20 records.
Page1:
Page2:
How can I achieve this type of pattern?
I can think of 2 ways to do this, as a MATRIX style report where the column group is your columns, and as a normal table where you JOIN the data to produce 3 copies of name, ID, and any other fields you want. The MATRIX style is definitely more elegant and flexible, but the normal table might be easier for customers to modify if you're turning the report over to power users.
Both solutions start with tagging the data with PAGE, ROW, and COLUMN information. Note that I'm sorting on NAME, but you could sort on any field. Also note that this solution does not depend on your ID being sequential and in the order you want, it generates it's own sequence numbers based on NAME or whatever else you choose.
In this demo I'm setting RowsPerPage and NumberofColumns as hard coded constants, but they could easily be user selected parameters if you use the MATRIX format.
DECLARE #RowsPerPage INT = 20
DECLARE #Cols INT = 3
;with
--Fake data generation BEGIN
cteSampleSize as (SELECT TOP 70 ROW_NUMBER () OVER (ORDER BY O.name) as ID
FROM sys.objects as O
), cteFakeData as (
SELECT N.ID, CONCAT(CHAR(65 + N.ID / 26), CHAR(65 + ((N.ID -1) % 26))
--, CHAR(65 + ((N.ID ) % 26))
) as Name
FROM cteSampleSize as N
),
--Fake data generation END, real processing begins below
cteNumbered as ( -- We can't count on ID being sequential and in the order we want!
SELECT D.*, ROW_NUMBER () OVER (ORDER BY D.Name) as SeqNum
--Replace ORDER BY D.Name with ORDER BY D.{Whatever field}
FROM cteFakeData as D --Replace cteFakeData with your real data source
), ctePaged as (
SELECT D.*
, 1+ FLOOR((D.SeqNum -1) / (#RowsPerPage*#Cols)) as PageNum
, 1+ ((D.SeqNum -1) % #RowsPerPage) as RowNum
, 1+ FLOOR(((D.SeqNum-1) % (#RowsPerPage*#Cols) ) / #RowsPerPage) as ColNum
FROM cteNumbered as D
)
--FINAL - use this for MATRIX reports (best)
SELECT * FROM ctePaged ORDER BY SeqNum
If you want to use the JOIN method to allow this in a normal table, replace the --FINAL query above with this one. Note that it's pretty finicky, so test it with several degrees of fullness in the final report. I tested with 70 and 90 rows of sample data so I had a partial first column and a full first and partial second.
--FINAL - use this for TABLE reports (simpler)
SELECT C1.PageNum , C1.RowNum , C1.ID as C1_ID, C1.Name as C1_Name
, C2.ID as C2_ID, C2.Name as C2_Name
, C3.ID as C3_ID, C3.Name as C3_Name
FROM ctePaged as C1 LEFT OUTER JOIN ctePaged as C2
ON C1.PageNum = C2.PageNum AND C1.RowNum = C2.RowNum
AND C1.ColNum = 1 AND (C2.ColNum = 2 OR C2.ColNum IS NULL)
LEFT OUTER JOIN ctePaged as C3 ON C1.PageNum = C3.PageNum
AND C1.RowNum = C3.RowNum AND (C3.ColNum = 3 OR C3.ColNum IS NULL)
WHERE C1.ColNum = 1
1) Add the dataset with the below query to get Page number and Table number. You can change the number 20 and 60 as per requirement. In my case, I need 20 records per section and having 3 sections, so total records per page are 60.
Select *,(ROW_NUMBER ( ) OVER ( partition by PageNumber order by Id )-1)/20 AS TableNumber from (
Select (ROW_NUMBER ( ) OVER ( order by Id )-1)/60 AS PageNumber
,* from Numbers
)Src
2)Add the table of one column and select the prepared dataset.
3)Add PageNumber in Group expression for Details group.
4)Add the Column parent group by right-clicking on detail row. Select Group by TableNumber.
5) Delete the first two rows. Select Delete rows only.
6) Add one more table and select the ID and Name.
7) Drag this newly created table into the cell of the previously created table. And increase the size of the table.
Result:
Each table section contains 20 records. and it will continue in next pages also.
Given the following result sets, sorted in descending order on column Date.
I want to use Top clause like:
select top 4 *
from donation d
order by d.Date desc;
Which give me the following result:
Even though I limit my result with top 4, I want to be able to include the last row, because it is tie with the last record (id : 5) based on the Name.
This query first selects the names of the people in the top 4 dates (in a Common Table Expression), then uses these names to shown all their data. I guess that is what you want.
;WITH Top4Names AS
(
SELECT TOP 4 [Name]
FROM donation
ORDER BY [Date] DESC
)
SELECT d.id, d.[Name], d.Amount, d.[Date]
FROM donation d
INNER JOIN Top4Names t
ON t.[Name] = d.[Name]
ORDER BY d.[Date] DESC;
So I'm trying to create a report that ranks a duplicate record, the idea behind this is that the customer wants to merge a whole lot of duplicate records that came about from a migration.
I need the ranking so that my report can show which record should be the "main" record, i.e. the record that will have missing data pulled into it.
The duplicate definition is pretty simple:
If the email addresses are the same then it is always a duplicate, if
the emails do not match, then the first name, surname, and mobile must
match.
The ranking will be based on a whole bunch of columns in the table, so:
email address isn't NULL = 50
phone number isn't NULL = 20
etc.. whichever gets the highest number in the duplicate group becomes the main record. This is where I am having issues, I can't seem to find a way to get an incremental number for each duplicate set. This is some of the code I have so far:
( I took out some of the rank columns in the temp table and CTE expression to shorten it )
DECLARE #tmp_Duplicates TABLE (
tmp_personID INT
, tmp_Firstname NVARCHAR(100)
, tmp_Surname NVARCHAR(100)
, tmp_HomeEmail NVARCHAR(300)
, tmp_MobileNumber NVARCHAR(100)
--- Ratings
, tmp_HomeEmail_Rating INT
--- Groupings
, tmp_GroupNumber INT
)
;WITH cteDupes AS
(
SELECT ROW_NUMBER() OVER(PARTITION BY personHomeEmail ORDER BY personID DESC) AS RND,
ROW_NUMBER() OVER(PARTITION BY personHomeEmail ORDER BY personId) AS RNA,
p.personID, p.PersonFirstName, p.PersonSurname, p.PersonHomeEMail
, personMobileTelephone
FROM tblCandidate c INNER JOIN tblPerson p ON c.candidateID = p.personID
)
INSERT INTO #tmp_Duplicates
SELECT PersonID, PersonFirstName, PersonSurname, PersonHomeEMail, personMobileTelephone
, 10, RND
FROM cteDupes
WHERE RNA + RND > 2
ORDER BY personID, PersonFirstName, PersonSurname
SELECT * FROM #tmp_Duplicates
This gives me the results I want, but the group number isn't showing how I need it:
What I need is for each group to be an incremental value:
I'm still fairly new to SQL. This is a stripped down version of the query I'm trying to run. This query is suppose to find those customers with more than 3 cases and display either the top 1 case or all cases but still show the overall count of cases per customer in each row in addition to all the case numbers.
The TOP 1 subquery approach didn't work but is there another way to get the results I need? Hope that makes sense.
Here's the code:
SELECT t1.StoreID, t1.CustomerID, t2.LastName, t2.FirstName
,COUNT(t1.CaseNo) AS CasesCount
,(SELECT TOP 1 t1.CaseNo)
FROM MainDatabase t1
INNER JOIN CustomerDatabase t2
ON t1.StoreID = t2.StoreID
WHERE t1.SubmittedDate >= '01/01/2017' AND t1.SubmittedDate <= '05/31/2017'
GROUP BY t1.StoreID, t1.CustomerID, t2.LastName, t2.FirstName
HAVING COUNT (t1.CaseNo) >= 3
ORDER BY t1.StoreID, t1.PatronID
I would like it to look something like this, either one row with just the most recent case and detail or several rows showing all details of each case in addition to the store id, customer id, last name, first name, and case count.
Data Example
For these I usually like to make a temp table of aggregates:
DROP TABLE IF EXISTS #tmp;
CREATE TABLE #tmp (
CustomerlD int NOT NULL DEFAULT 0,
case_count int NOT NULL DEFAULT 0,
case_max int NOT NULL DEFAULT 0,
);
INSERT INTO #tmp
(CustomerlD, case_count, case_max)
SELECT CustomerlD, COUNT(tl.CaseNo), MAX(tl.CaseNo)
FROM MainDatabase
GROUP BY CustomerlD;
Then you can join this "tmp" table back to any other table you want to display the number of cases on, or the max case number on. And you can limit it to customers that have more than 3 cases with WHERE case_count > 3
If I have a SQL statement such as:
SELECT TOP 5
*
FROM Person
WHERE Name LIKE 'Sm%'
ORDER BY ID DESC
PRINT ##ROWCOUNT
-- shows '5'
Is there anyway to get a value like ##ROWCOUNT that is the actual count of all of the rows that match the query without re-issuing the query again sans the TOP 5?
The actual problem is a much more complex and intensive query that performs beautifully since we can use TOP n or SET ROWCOUNT n but then we cannot get a total count which is required to display paging information in the UI correctly. Presently we have to re-issue the query with a #Count = COUNT(ID) instead of *.
Whilst this doesn't exactly meet your requirement (in that the total count isn't returned as a variable), it can be done in a single statement:
;WITH rowCTE
AS
(
SELECT *
,ROW_NUMBER() OVER (ORDER BY ID DESC) AS rn1
,ROW_NUMBER() OVER (ORDER BY ID ASC) AS rn2
FROM Person
WHERE Name LIKE 'Sm%'
)
SELECT *
,(rn1 + rn2) - 1 as totalCount
FROM rowCTE
WHERE rn1 <=5
The totalCount column will have the total number of rows matching the where filter.
It would be interesting to see how this stacks up performance-wise against two queries on a decent-sized data-set.
you'll have to run another COUNT() query:
SELECT TOP 5
*
FROM Person
WHERE Name LIKE 'Sm%'
ORDER BY ID DESC
DECLARE #r int
SELECT
#r=COUNT(*)
FROM Person
WHERE Name LIKE 'Sm%'
select #r
Something like this may do it:
SELECT TOP 5
*
FROM Person
cross join (select count(*) HowMany
from Person
WHERE Name LIKE 'Sm%') tot
WHERE Name LIKE 'Sm%'
ORDER BY ID DESC
The subquery returns one row with one column containing the full count; the cross join includes it with all rows returned by the "main" query"; and "SELECT *" would include new column HowMany.
Depending on your needs, the next step might be to filter out that column from your return set. One way would be to load the data from the query into a temp table, and then return just the desired columns, and get rowcount from the HowMany column from any row.