;with cte as (
select Domain_Id, Starting_Date, End_Date
from Que_Date
union all
select t.Domain_Id, cte.Starting_Date, t.End_Date
from cte
join Que_Date t on cte.Domain_Id = t.Domain_Id and cte.End_Date = t.Starting_Date),
cte2 as (
select *, rn = row_number() over (partition by Domain_Id, End_Date order by Domain_Id)
from cte
)
select DISTINCT Domain_Id, Starting_Date, max(End_Date) enddate
from cte2
where rn=1
group by Domain_Id, Starting_Date
order by Domain_Id, Starting_Date;
select * from Que_Date
This is the code that I have wrote but i am getting an extra row i.e 2nd row is extra, the expected output should have only 1st, 3rd and 4th row as output so please help me with it.
I have attached an image showing Input, Excepted Output, and the output that I am getting.
You've got so many results in your first cte. Your first cte has consisting domains. So you cannot filter domains based on your cte. So you query has unnecessary rows.
Try this solution. Cte ConsistentDomains has just consistent domains. So based on this cte, we can get not overlapped results.
Create and fill data:
CREATE TABLE FooTable
(
Domain_ID INT,
Starting_Date DATE,
End_Date Date
)
INSERT INTO dbo.FooTable
(
Domain_ID,
Starting_Date,
End_Date
)
VALUES
( 1, -- Domain_ID - int
CONVERT(datetime,'01-01-2011',103), -- Starting_Date - date
CONVERT(datetime,'05-01-2011',103) -- End_Date - date
)
, (1, CONVERT(datetime,'05-01-2011',103), CONVERT(datetime,'07-01-2011',103))
, (1, CONVERT(datetime,'07-01-2011',103), CONVERT(datetime,'15-01-2011',103))
, (2, CONVERT(datetime,'11-05-2011',103), CONVERT(datetime,'12-05-2011',103))
, (2, CONVERT(datetime,'13-05-2011',103), CONVERT(datetime,'14-05-2011',103))
Query to find not overlapping results:
DECLARE #startDate varchar(50) = '2011-01-01';
WITH ConsistentDomains AS
(
SELECT
f.Domain_ID
, f.Starting_Date
, f.End_Date
FROM FooTable f
WHERE f.Starting_Date = #startDate
UNION ALL
SELECT
s.Domain_ID
, s.Starting_Date
, s.End_Date
FROM FooTable s
INNER JOIN ConsistentDomains cd
ON s.Domain_ID = cd.Domain_ID
AND s.Starting_Date = cd.End_Date
), ConsistentDomainsRownumber AS
(
SELECT
cd.Domain_ID
, cd.Starting_Date
, cd.End_Date
, ROW_NUMBER() OVER (PARTITION BY cd.Domain_ID ORDER BY cd.Starting_Date,
cd.End_Date) RN
FROM ConsistentDomains cd
)
SELECT cd.Domain_ID
, convert(varchar, cd.Starting_Date, 105) Starting_Date
, convert(varchar, cd.End_Date, 105) End_Date
FROM ConsistentDomainsRownumber cd WHERE cd.RN = 1
UNION ALL
SELECT
ft.Domain_ID
, convert(varchar, ft.Starting_Date, 105) Starting_Date
, convert(varchar, ft.End_Date, 105) End_Date
FROM dbo.FooTable ft WHERE ft.Domain_ID NOT IN (SELECT cd.Domain_ID FROM
ConsistentDomainsRownumber cd)
Output:
I used the same table creating script as provided by #stepup, but you can also get your outcome in this way.
CREATE TABLE testtbl
(
Domain_ID INT,
Starting_Date DATE,
End_Date Date
)
INSERT INTO testtbl
VALUES
(1, convert(date, '01-01-2011' ,103), convert(date, '05-01-2011',103) )
,(1, convert(date, '05-01-2011' ,103), convert(date, '07-01-2011',103) )
,(1, convert(date, '07-01-2011' ,103), convert(date, '15-01-2011',103) )
,(2, convert(date, '11-05-2011' ,103), convert(date, '12-05-2011',103) )
,(2, convert(date, '13-05-2011' ,103), convert(date, '14-05-2011',103) )
You can make use of self join and Firs_value and last value within the group to make sure that you are comparing within the same ID and overlapping dates.
select distinct t.Domain_ID,
case when lag(t1.starting_date)over (partition by t.Domain_id order by
t.starting_date) is not null
then first_value(t.Starting_Date) over (partition by t.domain_id order by
t.starting_date)
else t.Starting_Date end StartingDate,
case when lead(t.domain_id) over (partition by t.domain_id order by t.starting_date) =
t1.Domain_ID then isnull(last_value(t.End_Date) over (partition by t.domain_id order by t.end_date rows between unbounded preceding and unbounded following),t.End_Date)
else t.End_Date end end_date
from testtbl t
left join testtbl t1 on t.Domain_ID = t1.Domain_ID
and t.End_Date = t1.Starting_Date
and t.Starting_Date < t1.Starting_Date
Output:
Domain_ID StartingDate end_date
1 2011-01-01 2011-01-15
2 2011-05-11 2011-05-12
2 2011-05-13 2011-05-14
I have my database table ABC as shown below :
ItemId Month Year Sales
1 1 2013 333
1 2 2013 454
2 1 2013 434
and so on .
I would like to write a query to find the top 3 items that have had the highest increase in sales from last month to this month , so that I see somethinglike this in the output.
Output :
ItemId IncreaseInSales
1 +121
9 +33
6 +16
I came up to here :
select
(select Sum(Sales) from ABC where [MONTH] = 11 )
-
(select Sum(Sales) from ABC where [MONTH] = 10)
I cannot use a group by as it is giving an error . Can anyone point me how I can
proceed further ?
Assuming that you want the increase for a given month, you can also do this with an aggregation query:
select top 3 a.ItemId,
((sum(case when year = #YEAR and month = #MONTH then 1.0*sales end) /
sum(case when year = #YEAR and month = #MONTH - 1 or
year = #YEAR - 1 and #Month = 1 and month = 12
then sales end)
) - 1
) * 100 as pct_increase
from ABC a
group by a.ItemId
order by pct_increase desc;
You would put the year/month combination you care about in the variables #YEAR and #MONTH.
EDIT:
If you just want the increase, then do a difference:
select top 3 a.ItemId,
(sum(case when year = #YEAR and month = #MONTH then 1.0*sales end) -
sum(case when year = #YEAR and month = #MONTH - 1 or
year = #YEAR - 1 and #Month = 1 and month = 12
then sales
end)
) as difference
from ABC a
group by a.ItemId
order by difference desc;
Here is the SQL Fiddle that demonstrates the below query:
SELECT TOP(3) NewMonth.ItemId,
NewMonth.Month11Sales - OldMonth.Month10Sales AS IncreaseInSales
FROM
(
SELECT s1.ItemId, Sum(s1.Sales) AS Month11Sales
FROM ABC AS s1
WHERE s1.MONTH = 11
AND s1.YEAR = 2013
GROUP BY s1.ItemId
) AS NewMonth
INNER JOIN
(
SELECT s2.ItemId, Sum(s2.Sales) AS Month10Sales
FROM ABC AS s2
WHERE s2.MONTH = 10
AND s2.YEAR = 2013
GROUP BY s2.ItemId
) AS OldMonth
ON NewMonth.ItemId = OldMonth.ItemId
ORDER BY NewMonth.Month11Sales - OldMonth.Month10Sales DESC
You never mentioned if you could have more than one record for an ItemId with the same Month, so I made the query to handle it either way. Obviously you were lacking the year = 2013 in your query. Once you get past this year you will need that.
Another option could be something on these lines:
SELECT top 3 a.itemid, asales-bsales increase FROM
(
(select itemid, month, sum(sales) over(partition by itemid) asales from ABC where month=2
and year=2013) a
INNER JOIN
(select itemid, month, sum(sales) over(partition by itemid) bsales from ABC where month=1
and year=2013) b
ON a.itemid=b.itemid
)
ORDER BY increase desc
if you need to cater for months without sales then you can do a FULL JOIN and calculate increase as isnull(asales,0) - isnull(bsales,0)
You could adapt this solution based on PIVOT operator:
SET NOCOUNT ON;
DECLARE #Sales TABLE
(
ItemID INT NOT NULL,
SalesDate DATE NOT NULL,
Amount MONEY NOT NULL
);
INSERT #Sales (ItemID, SalesDate, Amount)
VALUES
(1, '2013-01-15', 333), (1, '2013-01-14', 111), (1, '2012-12-13', 100), (1, '2012-11-12', 150),
(2, '2013-01-11', 200), (2, '2012-12-10', 150), (3, '2013-01-09', 900);
-- Parameters (current year & month)
DECLARE #pYear SMALLINT = 2013,
#pMonth TINYINT = 1;
DECLARE #FirstDayOfCurrentMonth DATE = CONVERT(DATE, CONVERT(CHAR(4), #pYear) + '-' + CONVERT(CHAR(2), #pMonth) + '-01');
DECLARE #StartDate DATE = DATEADD(MONTH, -1, #FirstDayOfCurrentMonth), -- Begining of the previous month
#EndDate DATE = DATEADD(DAY, -1, DATEADD(MONTH, 1, #FirstDayOfCurrentMonth)) -- End of the current month
SELECT TOP(3) t.ItemID,
t.[2]-t.[1] AS IncreaseAmount
FROM
(
SELECT y.ItemID, y.Amount,
DENSE_RANK() OVER(ORDER BY y.FirstDayOfSalesMonth ASC) AS MonthNum -- 1=Previous Month, 2=Current Month
FROM
(
SELECT x.ItemID, x.Amount,
DATEADD(MONTH, DATEDIFF(MONTH, 0, x.SalesDate), 0) AS FirstDayOfSalesMonth
FROM #Sales x
WHERE x.SalesDate BETWEEN #StartDate AND #EndDate
) y
) z
PIVOT( SUM(z.Amount) FOR z.MonthNum IN ([1], [2]) ) t
ORDER BY IncreaseAmount DESC;
SQLFiddle demo
Your sample data seems to be incomplete, however, here is my try. I assume that you want to know the three items with the greatest sales-difference from one month to the next:
WITH Increases AS
(
SELECT a1.itemid,
a1.sales - (SELECT a2.sales
FROM dbo.abc a2
WHERE a1.itemid = a2.itemid
AND ( ( a1.year = a2.year
AND a1.month > 1
AND a1.month = a2.month + 1 )
OR ( a1.year = a2.year + 1
AND a1.month = 1
AND a2.month = 12 ) ))AS IncreaseInSales
FROM dbo.abc a1
)
SELECT TOP 3 ItemID, MAX(IncreaseInSales) AS IncreaseInSales
FROM Increases
GROUP BY ItemID
ORDER BY MAX(IncreaseInSales) DESC
Demo
SELECT
cur.[ItemId]
MAX(nxt.[Sales] - cur.[Sales]) AS [IncreaseInSales]
FROM ABC cur
INNER JOIN ABC nxt ON (
nxt.[Year] = cur.[Year] + cur.[month]/12 AND
nxt.[Month] = cur.[Month]%12 + 1
)
GROUP BY cur.[ItemId]
I'd do this this way. It should work in all the tagged versions of SQL Server:
SELECT TOP 3 [ItemId],
MAX(CASE WHEN [Month] = 2 THEN [Sales] END) -
MAX(CASE WHEN [Month] = 1 THEN [Sales] END) [Diff]
FROM t
WHERE [Month] IN (1, 2) AND [Year] = 2013
GROUP BY [ItemId]
HAVING COUNT(*) = 2
ORDER BY [Diff] DESC
Fiddle here.
The reason why I'm adding the HAVING clause is that if any item is added in only one of the months then the numbers will be all wrong. So I'm only comparing items that are only present in both months.
The reason of the WHERE clause would be to filter in advance only the needed months and improve the efficiency of the query.
An SQL Server 2012 solution could also be:
SELECT TOP 3 [ItemId], [Diff] FROM (
SELECT [ItemId],
LEAD([Sales]) OVER (PARTITION BY [ItemId] ORDER BY [Month]) - [Sales] Diff
FROM t
WHERE [Month] IN (1, 2) AND [Year] = 2013
) s
WHERE [Diff] IS NOT NULL
ORDER BY [Diff] DESC
I need to concatenate rows with a date and a code into a date range
Table with two columns that are a composite primary key (date and a code )
Date Code
1/1/2011 A
1/2/2011 A
1/3/2011 A
1/1/2011 B
1/2/2011 B
2/1/2011 A
2/2/2011 A
2/27/2011 A
2/28/2011 A
3/1/2011 A
3/2/2011 A
3/3/2011 A
3/4/2011 A
Needs to be converted to
Start Date End Date Code
1/1/2011 1/3/2011 A
2/1/2011 2/2/2011 A
1/1/2011 1/2/2011 B
2/27/2011 3/4/2011 A
Is there any other way or is a cursor loop the only way?
declare #T table
(
[Date] date,
Code char(1)
)
insert into #T values
('1/1/2011','A'),
('1/2/2011','A'),
('1/3/2011','A'),
('1/1/2011','B'),
('1/2/2011','B'),
('3/1/2011','A'),
('3/2/2011','A'),
('3/3/2011','A'),
('3/4/2011','A')
;with C as
(
select *,
datediff(day, 0, [Date]) - row_number() over(partition by Code
order by [Date]) as rn
from #T
)
select min([Date]) as StartDate,
max([Date]) as EndDate,
Code
from C
group by Code, rn
sql server 2000 has it limitations. Rewrote the solution to make it more readable.
declare #t table
(
[Date] datetime,
Code char(1)
)
insert into #T values
('1/1/2011','A'),
('1/2/2011','A'),
('1/3/2011','A'),
('1/1/2011','B'),
('1/2/2011','B'),
('3/1/2011','A'),
('3/2/2011','A'),
('3/3/2011','A'),
('3/4/2011','A')
select a.code, a.date, min(b.date)
from
(
select *
from #t t
where not exists (select 1 from #t where t.code = code and t.date -1 = date)
) a
join
(
select *
from #t t
where not exists (select 1 from #t where t.code = code and t.date = date -1)
) b
on a.code = b.code and a.date <= b.date
group by a.code, a.date
Using a DatePart function for month will get you the "groups" you want
SELECT Min(Date) as StartDate, Max(Date) as EndDate, Code
FROM ThisTable Group By DatePart(m, Date), Code
My question is similar to this MySQL question, but intended for SQL Server:
Is there a function or a query that will return a list of days between two dates? For example, lets say there is a function called ExplodeDates:
SELECT ExplodeDates('2010-01-01', '2010-01-13');
This would return a single column table with the values:
2010-01-01
2010-01-02
2010-01-03
2010-01-04
2010-01-05
2010-01-06
2010-01-07
2010-01-08
2010-01-09
2010-01-10
2010-01-11
2010-01-12
2010-01-13
I'm thinking that a calendar/numbers table might be able to help me here.
Update
I decided to have a look at the three code answers provided, and the results of the execution - as a % of the total batch - are:
Rob Farley's answer : 18%
StingyJack's answer : 41%
KM's answer : 41%
Lower is better
I have accepted Rob Farley's answer, as it was the fastest, even though numbers table solutions (used by both KM and StingyJack in their answers) are something of a favourite of mine. Rob Farley's was two-thirds faster.
Update 2
Alivia's answer is much more succinct. I have changed the accepted answer.
this few lines are the simple answer for this question in sql server.
WITH mycte AS
(
SELECT CAST('2011-01-01' AS DATETIME) DateValue
UNION ALL
SELECT DateValue + 1
FROM mycte
WHERE DateValue + 1 < '2021-12-31'
)
SELECT DateValue
FROM mycte
OPTION (MAXRECURSION 0)
Try something like this:
CREATE FUNCTION dbo.ExplodeDates(#startdate datetime, #enddate datetime)
returns table as
return (
with
N0 as (SELECT 1 as n UNION ALL SELECT 1)
,N1 as (SELECT 1 as n FROM N0 t1, N0 t2)
,N2 as (SELECT 1 as n FROM N1 t1, N1 t2)
,N3 as (SELECT 1 as n FROM N2 t1, N2 t2)
,N4 as (SELECT 1 as n FROM N3 t1, N3 t2)
,N5 as (SELECT 1 as n FROM N4 t1, N4 t2)
,N6 as (SELECT 1 as n FROM N5 t1, N5 t2)
,nums as (SELECT ROW_NUMBER() OVER (ORDER BY (SELECT 1)) as num FROM N6)
SELECT DATEADD(day,num-1,#startdate) as thedate
FROM nums
WHERE num <= DATEDIFF(day,#startdate,#enddate) + 1
);
You then use:
SELECT *
FROM dbo.ExplodeDates('20090401','20090531') as d;
Edited (after the acceptance):
Please note... if you already have a sufficiently large nums table then you should use:
CREATE FUNCTION dbo.ExplodeDates(#startdate datetime, #enddate datetime)
returns table as
return (
SELECT DATEADD(day,num-1,#startdate) as thedate
FROM nums
WHERE num <= DATEDIFF(day,#startdate,#enddate) + 1
);
And you can create such a table using:
CREATE TABLE dbo.nums (num int PRIMARY KEY);
INSERT dbo.nums values (1);
GO
INSERT dbo.nums SELECT num + (SELECT COUNT(*) FROM nums) FROM nums
GO 20
These lines will create a table of numbers containing 1M rows... and far quicker than inserting them one by one.
You should NOT create your ExplodeDates function using a function that involves BEGIN and END, as the Query Optimizer becomes unable to simplify the query at all.
This does exactly what you want, modified from Will's earlier post. No need for helper tables or loops.
WITH date_range (calc_date) AS (
SELECT DATEADD(DAY, DATEDIFF(DAY, 0, '2010-01-13') - DATEDIFF(DAY, '2010-01-01', '2010-01-13'), 0)
UNION ALL SELECT DATEADD(DAY, 1, calc_date)
FROM date_range
WHERE DATEADD(DAY, 1, calc_date) <= '2010-01-13')
SELECT calc_date
FROM date_range;
DECLARE #MinDate DATETIME = '2012-09-23 00:02:00.000',
#MaxDate DATETIME = '2012-09-25 00:00:00.000';
SELECT TOP (DATEDIFF(DAY, #MinDate, #MaxDate) + 1) Dates = DATEADD(DAY, ROW_NUMBER() OVER(ORDER BY a.object_id) - 1, #MinDate)
FROM sys.all_objects a CROSS JOIN sys.all_objects b;
I'm an oracle guy, but I believe MS SQL Server has support for the connect by clause:
select sysdate + level
from dual
connect by level <= 10 ;
The output is:
SYSDATE+LEVEL
05-SEP-09
06-SEP-09
07-SEP-09
08-SEP-09
09-SEP-09
10-SEP-09
11-SEP-09
12-SEP-09
13-SEP-09
14-SEP-09
Dual is just a 'dummy' table that comes with oracle (it contains 1 row and the word 'dummy' as the value of the single column).
A few ideas:
If you need the list dates in order to loop through them, you could have a Start Date and Day Count parameters and do a while loop whilst creating the date and using it?
Use C# CLR Stored Procedures and write the code in C#
Do this outside the database in code
Would all these dates be in the database already or do you just want to know the days between the two dates? If it's the first you could use the BETWEEN or <= >= to find the dates between
EXAMPLE:
SELECT column_name(s)
FROM table_name
WHERE column_name
BETWEEN value1 AND value2
OR
SELECT column_name(s)
FROM table_name
WHERE column_name
value1 >= column_name
AND column_name =< value2
All you have to do is just change the hard coded value in the code provided below
DECLARE #firstDate datetime
DECLARE #secondDate datetime
DECLARE #totalDays INT
SELECT #firstDate = getDate() - 30
SELECT #secondDate = getDate()
DECLARE #index INT
SELECT #index = 0
SELECT #totalDays = datediff(day, #firstDate, #secondDate)
CREATE TABLE #temp
(
ID INT NOT NULL IDENTITY(1,1)
,CommonDate DATETIME NULL
)
WHILE #index < #totalDays
BEGIN
INSERT INTO #temp (CommonDate) VALUES (DATEADD(Day, #index, #firstDate))
SELECT #index = #index + 1
END
SELECT CONVERT(VARCHAR(10), CommonDate, 102) as [Date Between] FROM #temp
DROP TABLE #temp
A Bit late to the party, but I like this solution quite a bit.
CREATE FUNCTION ExplodeDates(#startDate DateTime, #endDate DateTime)
RETURNS table as
return (
SELECT TOP (DATEDIFF(DAY, #startDate, #endDate) + 1)
DATEADD(DAY, ROW_NUMBER() OVER(ORDER BY a.object_id) - 1, #startDate) AS DATE
FROM sys.all_objects a
CROSS JOIN sys.all_objects b
)
Before you use my function, you need to set up a "helper" table, you only need to do this one time per database:
CREATE TABLE Numbers
(Number int NOT NULL,
CONSTRAINT PK_Numbers PRIMARY KEY CLUSTERED (Number ASC)WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]
) ON [PRIMARY]
DECLARE #x int
SET #x=0
WHILE #x<8000
BEGIN
SET #x=#x+1
INSERT INTO Numbers VALUES (#x)
END
here is the function:
CREATE FUNCTION dbo.ListDates
(
#StartDate char(10)
,#EndDate char(10)
)
RETURNS
#DateList table
(
Date datetime
)
AS
BEGIN
IF ISDATE(#StartDate)!=1 OR ISDATE(#EndDate)!=1
BEGIN
RETURN
END
INSERT INTO #DateList
(Date)
SELECT
CONVERT(datetime,#StartDate)+n.Number-1
FROM Numbers n
WHERE Number<=DATEDIFF(day,#StartDate,CONVERT(datetime,#EndDate)+1)
RETURN
END --Function
use this:
select * from dbo.ListDates('2010-01-01', '2010-01-13')
output:
Date
-----------------------
2010-01-01 00:00:00.000
2010-01-02 00:00:00.000
2010-01-03 00:00:00.000
2010-01-04 00:00:00.000
2010-01-05 00:00:00.000
2010-01-06 00:00:00.000
2010-01-07 00:00:00.000
2010-01-08 00:00:00.000
2010-01-09 00:00:00.000
2010-01-10 00:00:00.000
2010-01-11 00:00:00.000
2010-01-12 00:00:00.000
2010-01-13 00:00:00.000
(13 row(s) affected)
Perhaps if you wish to go an easier way, this should do it.
WITH date_range (calc_date) AS (
SELECT DATEADD(DAY, DATEDIFF(DAY, 0, CURRENT_TIMESTAMP) - 6, 0)
UNION ALL SELECT DATEADD(DAY, 1, calc_date)
FROM date_range
WHERE DATEADD(DAY, 1, calc_date) < CURRENT_TIMESTAMP)
SELECT calc_date
FROM date_range;
But the temporary table is a very good approach also. Perhaps shall you also consider a populated calendar table.
Definately a numbers table, though tyou may want to use Mark Redman's idea of a CLR proc/assembly if you really need the performance.
How to create the table of dates (and a super fast way to create a numbers table)
/*Gets a list of integers into a temp table (Jeff Moden's idea from SqlServerCentral.com)*/
SELECT TOP 10950 /*30 years of days*/
IDENTITY(INT,1,1) as N
INTO #Numbers
FROM Master.dbo.SysColumns sc1,
Master.dbo.SysColumns sc2
/*Create the dates table*/
CREATE TABLE [TableOfDates](
[fld_date] [datetime] NOT NULL,
CONSTRAINT [PK_TableOfDates] PRIMARY KEY CLUSTERED
(
[fld_date] ASC
)WITH FILLFACTOR = 99 ON [PRIMARY]
) ON [PRIMARY]
/*fill the table with dates*/
DECLARE #daysFromFirstDateInTheTable int
DECLARE #firstDateInTheTable DATETIME
SET #firstDateInTheTable = '01/01/1998'
SET #daysFromFirstDateInTheTable = (SELECT (DATEDIFF(dd, #firstDateInTheTable ,GETDATE()) + 1))
INSERT INTO
TableOfDates
SELECT
DATEADD(dd,nums.n - #daysFromFirstDateInTheTable, CAST(FLOOR(CAST(GETDATE() as FLOAT)) as DateTime)) as FLD_Date
FROM #Numbers nums
Now that you have a table of dates, you can use a function (NOT A PROC) like KM's to get the table of them.
CREATE FUNCTION dbo.ListDates
(
#StartDate DATETIME
,#EndDate DATETIME
)
RETURNS
#DateList table
(
Date datetime
)
AS
BEGIN
/*add some validation logic of your own to make sure that the inputs are sound.Adjust the rest as needed*/
INSERT INTO
#DateList
SELECT FLD_Date FROM TableOfDates (NOLOCK) WHERE FLD_Date >= #StartDate AND FLD_Date <= #EndDate
RETURN
END
Declare #date1 date = '2016-01-01'
,#date2 date = '2016-03-31'
,#date_index date
Declare #calender table (D date)
SET #date_index = #date1
WHILE #date_index<=#date2
BEGIN
INSERT INTO #calender
SELECT #date_index
SET #date_index = dateadd(day,1,#date_index)
IF #date_index>#date2
Break
ELSE
Continue
END
-- ### Six of one half dozen of another. Another method assuming MsSql
Declare #MonthStart datetime = convert(DateTime,'07/01/2016')
Declare #MonthEnd datetime = convert(DateTime,'07/31/2016')
Declare #DayCount_int Int = 0
Declare #WhileCount_int Int = 0
set #DayCount_int = DATEDIFF(DAY, #MonthStart, #MonthEnd)
select #WhileCount_int
WHILE #WhileCount_int < #DayCount_int + 1
BEGIN
print convert(Varchar(24),DateAdd(day,#WhileCount_int,#MonthStart),101)
SET #WhileCount_int = #WhileCount_int + 1;
END;
In case you want to print years starting from a particular year till current date. Just altered the accepted answer.
WITH mycte AS
(
SELECT YEAR(CONVERT(DATE, '2006-01-01',102)) DateValue
UNION ALL
SELECT DateValue + 1
FROM mycte
WHERE DateValue + 1 < = YEAR(GETDATE())
)
SELECT DateValue
FROM mycte
OPTION (MAXRECURSION 0)
This query works on Microsoft SQL Server.
select distinct format( cast('2010-01-01' as datetime) + ( a.v / 10 ), 'yyyy-MM-dd' ) as aDate
from (
SELECT ones.n + 10 * tens.n + 100 * hundreds.n + 1000 * thousands.n as v
FROM (VALUES(0),(1),(2),(3),(4),(5),(6),(7),(8),(9)) ones(n),
(VALUES(0),(1),(2),(3),(4),(5),(6),(7),(8),(9)) tens(n),
(VALUES(0),(1),(2),(3),(4),(5),(6),(7),(8),(9)) hundreds(n),
(VALUES(0),(1),(2),(3),(4),(5),(6),(7),(8),(9)) thousands(n)
) a
where format( cast('2010-01-01' as datetime) + ( a.v / 10 ), 'yyyy-MM-dd' ) < cast('2010-01-13' as datetime)
order by aDate asc;
Now let's look at how it works.
The inner query merely returns a list of integers from 0 to 9999. It will give us a range of 10,000 values for calculating dates. You can get more dates by adding rows for ten_thousands and hundred_thousands and so forth.
SELECT ones.n + 10 * tens.n + 100 * hundreds.n + 1000 * thousands.n as v
FROM (VALUES(0),(1),(2),(3),(4),(5),(6),(7),(8),(9)) ones(n),
(VALUES(0),(1),(2),(3),(4),(5),(6),(7),(8),(9)) tens(n),
(VALUES(0),(1),(2),(3),(4),(5),(6),(7),(8),(9)) hundreds(n),
(VALUES(0),(1),(2),(3),(4),(5),(6),(7),(8),(9)) thousands(n)
) a;
This part converts the string to a date and adds a number to it from the inner query.
cast('2010-01-01' as datetime) + ( a.v / 10 )
Then we convert the result into the format you want. This is also the column name!
format( cast('2010-01-01' as datetime) + ( a.v / 10 ), 'yyyy-MM-dd' )
Next we extract only the distinct values and give the column name an alias of aDate.
distinct format( cast('2010-01-01' as datetime) + ( a.v / 10 ), 'yyyy-MM-dd' ) as aDate
We use the where clause to filter in only dates within the range you want. Notice that we use the column name here since SQL Server does not accept the column alias, aDate, within the where clause.
where format( cast('2010-01-01' as datetime) + ( a.v / 10 ), 'yyyy-MM-dd' ) < cast('2010-01-13' as datetime)
Lastly, we sort the results.
order by aDate asc;
if you're in a situation like me where procedures and functions are prohibited, and your sql user does not have permissions for insert, therefore insert not allowed, also "set/declare temporary variables like #c is not allowed", but you want to generate a list of dates in a specific period, say current year to do some aggregation, use this
select * from
(select adddate('1970-01-01',t4*10000 + t3*1000 + t2*100 + t1*10 + t0) gen_date from
(select 0 t0 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t0,
(select 0 t1 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t1,
(select 0 t2 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t2,
(select 0 t3 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t3,
(select 0 t4 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t4) v
where gen_date between '2017-01-01' and '2017-12-31'
WITH TEMP (DIA, SIGUIENTE_DIA ) AS
(SELECT
1,
CAST(#FECHAINI AS DATE)
FROM
DUAL
UNION ALL
SELECT
DIA,
DATEADD(DAY, DIA, SIGUIENTE_DIA)
FROM
TEMP
WHERE
DIA < DATEDIFF(DAY, #FECHAINI, #FECHAFIN)
AND DATEADD(DAY, 1, SIGUIENTE_DIA) <= CAST(#FECHAFIN AS DATE)
)
SELECT
SIGUIENTE_DIA AS CALENDARIO
FROM
TEMP
ORDER BY
SIGUIENTE_DIA
The detail is on the table DUAL but if your exchange this table for a dummy table this works.
SELECT dateadd(dd,DAYS,'2013-09-07 00:00:00') DATES
INTO #TEMP1
FROM
(SELECT TOP 365 colorder - 1 AS DAYS from master..syscolumns
WHERE id = -519536829 order by colorder) a
WHERE datediff(dd,dateadd(dd,DAYS,'2013-09-07 00:00:00'),'2013-09-13 00:00:00' ) >= 0
AND dateadd(dd,DAYS,'2013-09-07 00:00:00') <= '2013-09-13 00:00:00'
SELECT * FROM #TEMP1
Answer is avialbe here
How to list all dates between two dates
Create Procedure SelectDates(#fromDate Date, #toDate Date)
AS
BEGIN
SELECT DATEADD(DAY,number,#fromDate) [Date]
FROM master..spt_values
WHERE type = 'P'
AND DATEADD(DAY,number,#fromDate) < #toDate
END
DECLARE #StartDate DATE = '2017-09-13', #EndDate DATE = '2017-09-16'
SELECT date FROM ( SELECT DATE = DATEADD(DAY, rn - 1, #StartDate) FROM (
SELECT TOP (DATEDIFF(DAY, #StartDate, DATEADD(DAY,1,#EndDate)))
rn = ROW_NUMBER() OVER (ORDER BY s1.[object_id])
FROM sys.all_objects AS s1
CROSS JOIN sys.all_objects AS s2
ORDER BY s1.[object_id] ) AS x ) AS y
Result:
2017-09-13
2017-09-14
2017-09-15
2017-09-16