2d array struct giving a segmentation fault - c

This program fragment should be reading in information in structs which are stored in a 2d way.
But this program fragment gives a segmentation fault after "printf("lel4\n");".
I have the feeling it is in my memory allocation, but I don't know. I looked for answers on the internet and I am doing exactly the same thing as the given answers, but it isn't working.
typedef struct coordinates{
int xposition;
int ypositiony;
char token;
int discovered;
} coordinates
typedef coordinates *coord;
coord **allocMemory(int row, int col){
int i;
coord **city = malloc(sizeof(coord)*col);
assert(city != NULL);
for(i=0; i<col; i++){
city[i] = malloc(sizeof(struct coordinates)*row);
assert(city[i] != NULL);
}
return city;
}
coord **readInfo(int row, int col){
int i, j;
char c;
coord **city = allocMemory(row, col);
for(i=0; i<col;i++){
c = getchar();
for(j = 0; j<ros; j++){
c = getchar();
if(c == '#' || c == '.'){
printf("lel4\n");
(*city)[i][j].xposition = i;
printf("lel5\n");
(*city)[i][j].yposition = j;
(*city)[i][j].token = c;
(*city)[i][j].discovered = 0;
}
}
}
return city;
}

coord **
to
coord *
and
city[i][j].xposition = i;
city[i][j].yposition = j;
city[i][j].token = c;
city[i][j].discovered = 0;

Related

Converting Static 2D Array to Dynamic Array in C

We were asked to convert 2D static array to dynamic array. So I will need to create an array of pointers in which every pointer points to a different row. I have written this code but my code breaks when i=1 on line *(dynamicStr[i] + v) = rowStr[v]; Additionally, if I enable free(ptr); section my debugger gets stuck there for 6 or 7 times and then contiunes.
EDIT: In the end, I solved the problem with appying the answers #dodooft and #Viktor Terziev gave.
#include <stdio.h>
#include <stdlib.h>
void toDynamic(int x,int y, char toDyna[x][y]);
void toDynamic2(int x,int y, char toDyna[x][y]);
int main()
{
char toDyna[7][12] = {
"JOHN",
"MARK",
"PIERCEPIERCE",
"20",
"ROSIE",
"ALEX",
"MARLYN"
};
int x = 7;
int y = 12;
toDynamic2(x, y, toDyna);
return 0;
}
void toDynamic2(int x,int y, char toDyna[x][y]){
char *dynamicStr[x];
int rowToCheck = 0;
int size;
char *ptr;
int c;
for(int i = 0; i < x; i++){
printf("i: %d\n",i);
c = 0;
size = strlen(toDyna[rowToCheck]);
ptr = (char*) malloc(size * sizeof(char));
for(int j = 0; j < y; j++){
if(toDyna[i][j] != '\0'){
*(ptr+c) = toDyna[i][j];
c++;
} else{
break;
}
}
*(ptr+size) = '\0';
printf(" ");
char rowStr[size];
for(int v = 0; v < size; v++){
rowStr[v] = *(ptr+v);
printf("Added Char: %c\n", rowStr[v]);
*(dynamicStr[i] + v) = rowStr[v];
}
//free(ptr);
//printf("\n%s\n", rowStr);
//dynamicStr[i] = &rowStr;
rowToCheck++;
}
for(int i = 0; i < x; i++){
printf("%s\n", dynamicStr[i]);
}
}
EDIT: This is the working verion of the code:
#include <stdio.h>
#include <stdlib.h>
char** toDynamic(int x,int y, char toDyna[x][y]);
void free2DArray(int x, char **dynamicStr);
int main()
{
char toDyna[7][12] = {
"JOHN",
"MARK",
"PIERCEPIERCE",
"20",
"ROSIE",
"ALEX",
"MARLYN"
};
int x = 7;
int y = 12;
char **dynamicArr;
dynamicArr = toDynamic(x, y, toDyna);
free2DArray(x, dynamicArr);
return 0;
}
char** toDynamic(int x,int y, char toDyna[x][y]){
printf("Q2\n");
char **dynamicStr;
int rowToCheck = 0;
int size;
int c;
dynamicStr = (char*)malloc(x * sizeof(char*));
for(int i = 0; i < x; i++){
dynamicStr[i] = (char*)malloc(y * sizeof(char));
c = 0;
size = strlen(toDyna[rowToCheck]);
char *ptr = (char*) malloc((size + 1) * sizeof(char));
for(int j = 0; j < y; j++){
if(toDyna[i][j] != '\0'){
*(ptr+c) = toDyna[i][j];
c++;
} else{
break;
}
}
*(ptr+size) = '\0';
dynamicStr[i] = ptr;
rowToCheck++;
}
for(int i = 0; i < x; i++){
printf("%s\n", dynamicStr[i]);
}
printf("----------------------------\n");
return dynamicStr;
}
void free2DArray(int x, char **dynamicStr){
printf("Q3\n");
for(int i = 0; i < x; i++){
free(dynamicStr[i]);
printf("dynamicStr %d freed\n", i);
}
free(dynamicStr);
printf("dynamicStr array freed\n");
printf("----------------------------\n");
}
You define dynamicStr as an array of char pointers, when you are trying to assign a value to it with *(dynamicStr[i] + v) = rowStr[v]; you are basically copying the value of rowStr[v] to the address that is pointed by dynamicStr[i] + v. That address is not defined in your code, so you got a segfault.
If you are trying to fill dynamicStr with pointers to new arrays with dynamic memory, you should try something like
dynamicStr[i] = ptr;
where ptr is the pointer returned by the malloc call to the i-th row. Also, as you are working with strings you can use strcpy to copy the data from the static array to the dynamic one.
Its much easier than you think, please refer to strcpy documentation and strlen documentation, and (if you use my code) don't forget to free your memory.
char * * toDynamic2(size_t n, size_t m, char strings[n][m])
{
char * * arr = malloc(n * sizeof(char*));
for(size_t i = 0; i < n; ++i)
{
size_t size = strlen(strings[i]);
arr[i] = malloc((size + 1) * sizeof(char));
strcpy(arr[i], strings[i]);
}
for(size_t i = 0; i < n; ++i)
{
printf("%s\n", arr[i]);
}
return arr;
}

Declaration in for gives segmentation fault

I'm doing a homework for learning graphs. For that, I'm taking a csv file and I keep that information in a Sensor structure.
#define sensor_amount 70
typedef struct Sensor {
int id;
float x,y,z;
}Sensor;
For getting this struct from file I'm using the following function:
Sensor* get_sensors(char* file_name){
FILE* file = fopen(file_name,"r");
//Skip first line
char* c;
fscanf(file,"%[^\n]",c);
int id = 0;
float x,y,z;
Sensor* sensor_arr = malloc(sizeof(Sensor));
fscanf(file,"%i,%f,%f,%f",&id,&x,&y,&z);
sensor_arr[0].id = id;
sensor_arr[0].x = x;
sensor_arr[0].y = y;
sensor_arr[0].z = z;
int counter = 1;
while(!feof(file)){
fscanf(file,"%i,%f,%f,%f\n",&id,&x,&y,&z);
++counter;
sensor_arr = realloc(sensor_arr,counter*sizeof(Sensor));
sensor_arr[counter-1].id = id;
sensor_arr[counter-1].x = x;
sensor_arr[counter-1].y = y;
sensor_arr[counter-1].z = z;
}
fclose(file);
return sensor_arr;
}
I'm calculating distances between each sensor with following code:
float** get_distances(Sensor* s){
float** a = malloc(sensor_amount*sizeof(float*));
for(int i = 0; i < sensor_amount;i++)
a[i] = malloc(sensor_amount*sizeof(float));
for(int i = 0; i < sensor_amount;i++){
for(int j = 0; j < sensor_amount; j++){
float dis = distance(s[i].x,s[i].y,s[j].x,s[j].y);
a[i][j] = dis;
}
}
return a;
}
Finally in my main i print those values like this:
int i,j;
int main(){
char file_name[] = "sensor_locations.csv";
Sensor* sensors;
sensors = get_sensors(file_name);
float**ar=get_distances(sensors);
for(i=0;i < 70; ++i)
for(j=0;j<70;++j){
printf("(%i,%i)->%f\n",i,j,ar[i][j]);
}
return 0;
}
In main, if I move the declarations of i and j to the for loops, it throws a segmentation fault. But why?
This is designed for array out of bounds bugs:
int counter = 1;
...
++counter;
...
[counter-1]
Instead do
for(int i=0; more_data; i++)
{
sensor_arr[i] = ...;
sensor_arr = realloc(sensor_arr,(i+2)*sizeof(Sensor));
}
Please note Why is “while ( !feof (file) )” always wrong?.
And your use of realloc is wrong, use a tmp pointer for storing the result and check it against NULL before assigning it back to the sensor_arr pointer.

Returning merged arrays from function in C

I have the following code:
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
typedef struct _item {
int v, w;
} item;
void printItems(item *t, int n) {
int i;
for(i= 0; i < n; i++)
printf("%4i",t[i].v);
printf("\n");
}
item * newItemSet(int n) {
int i;
item *t = (item*)malloc(sizeof(item));
for (i = 0; i < n; i++){
(t+i)->v = rand()%100;
(t+i)->w = rand()%100;
}
return t;
}
item * mer(item*a, int n, item*b, int m) {
int size = m+n;
item*q = (item*)malloc(sizeof(item)*size);
int i, c;
c = 0;
printf("a----\n");
printItems(a,n);
printf("b----\n");
printItems(b,m);
for(i = 0; i<n; i++) {
q[c] = a[i];
c++;
}
for(i = 0; i<m; i++) {
q[c] = b[i];
c++;
}
printItems(q,size);
return q;
}
int main(void) {
srand(time(NULL));
item * a = newItemSet(6);
item *b = newItemSet(6);
item *c = mer(a,6,b,6);
printItems(c,12);
return 0;
}
At every execution, the first part of c is correct, up to the last two elements of b. What did I miss?
The allocation for newItemSet does not appear correct. It should be:
item *t = malloc(sizeof(item) * n);
item *t = (item*)malloc(sizeof(item));
Should be:
item *t = malloc(n * sizeof(item));
You are allocating space for n items, not one item. Also, there is no need to cast the return value of malloc and it can hide errors.

Why this C programming can not run crrectly?

It's just a sample test that I want to unite the list Lb and La without repeat element. It didn't work, and returned -1073741510, I think maybe the array overflow, but I can't find where the problem is
This is my code:
#include <stdio.h>
void Union(char *La, char *Lb);
int ListLength(char *L);
void GetElem(char *L, int i, char *e);
int LocateElem(char *L, char *e, int (*comp)(char a, char b));
int compare(char a, char b);
void ListInsert(char *, int, char *);
int main(){
char *La;
char *Lb;
int i;
for(i = 0; i <= 10; ++i){
La[i] = i;
Lb[i] = i + 5;
}
La[i] = '\0';
Lb[i] = '\0';
Union(La, Lb);
for(i = 0; La[i] != '\0'; ++i){
printf("%c\n", La[i]);
}
return 0;
}
//unite La and Lb without repeat elements
void Union(char *La, char *Lb){
int La_length = ListLength(La);
int Lb_length = ListLength(Lb);
int i = 0;
char *e;
for(i; i<= Lb_length; ++i){
GetElem(Lb, i, e);
if(!LocateElem(La, e, compare))
ListInsert(La, ++La_length, e);
}
}
//caculate the length of L
int ListLength(char *L){
int i;
for(i = 0; *(L + i) != '\0'; ++i);
return i;
}
void GetElem(char *L, int i, char *e){
*e = *(L + i);
}
//search the element e in L, if exist return the location, else return 0
int LocateElem(char *L, char *e, int (*comp)(char a, char b)){
int i;
for(i = 0; *(L + i) != '\0'; ++i){
if(comp(*(L + i), *e)) return i + 1;
}
return 0;
}
//compare the element a and b
int compare(char a, char b){
if(a == b) return 1;
return 0;
}
//if e doesn't exit in L, insert the e in L
void ListInsert(char *L, int i, char *e){
int j;
for(j = ListLength(L) - 1; j >= i; --j){
*(L + j + 1) = *(L + j);
}
L[ListLength(L)] = '\0';
*(L + i - 2) = *e;
}
First, this is wrong:
char *La;
char *Lb;
int i;
for(i = 0; i <= 10; ++i){
La[i] = i;
Lb[i] = i + 5;
}
You need to reserve memory for La and Lb, for instance, by declaring them as:
char La[12];
char Lb[12];
An then this:
char *e;
for(i; i<= Lb_length; ++i){
GetElem(Lb, i, e);
should read:
char e;
for(; i<= Lb_length; ++i){
GetElem(Lb, i, &e); /* better yet: e=Lb[i] */
Finally, you're most likely looping one time too many by using <= instead of < as the for exit condition.
You have several issues. I think you need to read more about what are raw pointers, fixed length arrays, variable length arras and dynamic arrays. If you need your array to grow you can make it dynamic with malloc and realloc. Alternatively you can use a "big" array you know never will overflow.
int La[12]; // 0 to 10, plus '\0'
But this is fixed and cannt grow. You could use
int La[1000]; // if it solve yours problems
But in general you will need dynamic arrays.
Also, you need to deside if your array can hold 0 or it is used as terminator. '\0' and 0, in the form you use it are equal. Many of your for cycle dont run because the first elemnt is 0.

Dynamic array in struct calloc or pointers failing, C

I'm attempting to complete an assignment on sparse matrices in C. I have a sparse matrix held as a list of values and coordinates and am converting it to Yale format.
I have run into a strange memory allocation issue that no one seems to have seen before. My code is:
yale* convertMatrix(matrix_list* input){
int matrix_elements = input->elements;
int matrix_rows = input->m;
yale* yale = (struct y*)calloc(1, sizeof(yale));
int* A = (int*)calloc(matrix_elements, sizeof(int));
int* IA = (int*)calloc(matrix_rows + 1, sizeof(int));
int* JA = (int*)calloc(matrix_elements, sizeof(int));
printf("%d elements\n",matrix_elements);
yale->A = A; // Value
yale->IA = IA; // Row (X)
yale->JA = JA; // Column (Y)
yale->elements = matrix_elements;
yale->m = matrix_rows;
yale->n = input->n;
list* tmp_list = input->first;
for(int i = 0, j = 0, tmp_y = 0; i < matrix_elements && tmp_list!=NULL; i++){
printf("Input Value: %d \n",tmp_list->point.value);
A[i] = tmp_list->point.value;
// Initialise the first row
if(i == 0) IA[0] = tmp_list->point.x;
else{
// Add a new row index
if(tmp_y != tmp_list->point.x){
j++;
IA[j] = i;
tmp_y = tmp_list->point.x;
}
}
JA[i] = tmp_list->point.y;
tmp_list = tmp_list->next;
}
for(int i = 0; i < matrix_elements; i++)
printf("%d,",yale->A[i]);
printf("\n");
for(int i = 0; i < matrix_rows + 1; i++)
printf("%d,",yale->IA[i]);
printf("\n");
for(int i = 0; i < matrix_elements; i++)
printf("%d,",yale->JA[i]);
return yale;
}
And here is the struct for yale:
typedef struct y{
int n;
int m;
int elements;
int *IA;
int *JA;
int *A;
} yale;
But the program segfaults at the first relevant printf on the first iteration of the loop.
printf("%d,",yale->A[i]);
I'm positive:
matrix_elements is an integer (9 in my test case)
matrix_rows is an integer
A / IA / JA are all filled with correct values (if you swap yale->A for A in the printf, it works fine).
Directly callocing the array to the struct pointers doesn't affect the result.
Mallocing, callocing, not typecasting, all no effect.
Thanks to Xcode and gdb I can also see that at the point of the segfault. The structure pointers do NOT seem to point to the arrays
I suggest you run your code under Valgrind. This should report the buffer overflow error. (A buffer overflow is where you write past the end of an array).
I also recommend you write some unit tests for your code. They can be very helpful detecting bugs. In particular, I suggest you write a test with a 3x3 input matrix with a value in every position. Check that the values you get out are what you expect.
To get it compiled, I need to prepend this to the snippet:
#include <stdlib.h>
#include <stdio.h>
typedef struct y{
int n;
int m;
int elements;
int *IA;
int *JA;
int *A;
} yale;
typedef struct list {
struct list *next;
struct point { int x,y,value; } point;
} list;
typedef struct matrix_list {
int elements;
int m;
int n;
struct list *first;
int *point;
} matrix_list;
UPDATE: I transformed the program into something more readable (IMHO). I don't have the faintest idea what the IA and JA are supposed to do, but the below fragment should be equivalent to the OP.
#include <stdlib.h>
#include <stdio.h>
#include <assert.h>
struct y {
unsigned int n;
unsigned int m;
unsigned int elements;
unsigned int *IA;
unsigned int *JA;
int *A;
} ;
struct list {
struct list *next;
struct point { unsigned int x,y; int value; } point;
} ;
struct matrix_list {
unsigned int elements;
unsigned int m;
unsigned int n;
struct list *first;
} ;
struct y *convertMatrix(struct matrix_list* input)
{
unsigned int matrix_elements = input->elements;
unsigned int matrix_rows = input->m;
unsigned int ii,jj,tmp_y;
struct y *yale ;
struct list *tmp_list ;
yale = calloc(1, sizeof *yale);
assert (yale != NULL);
printf("%u elements\n",matrix_elements);
yale->A = calloc(matrix_elements, sizeof *yale->A);
assert (yale->A != NULL);
yale->IA = calloc(matrix_rows + 1, sizeof *yale->IA);
assert (yale->IA != NULL);
yale->JA = calloc(matrix_elements, sizeof *yale->JA);
assert (yale->JA != NULL);
yale->elements = matrix_elements;
yale->m = matrix_rows;
yale->n = input->n;
// Initialise the first row, set start condition
// FIXME: this ignores the empty list or size=0 cases
yale->IA[0] = tmp_y = input->first->point.x;
ii = jj = 0;
for(tmp_list = input->first ;tmp_list; tmp_list = tmp_list->next) {
printf("Input Value: %d \n",tmp_list->point.value);
yale->A[ii] = tmp_list->point.value;
// Add a new row index
if(tmp_y != tmp_list->point.x){
jj++;
yale->IA[jj] = ii;
tmp_y = tmp_list->point.x;
}
yale->JA[ii] = tmp_list->point.y;
if (++ii >= matrix_elements ) break;
}
for(int i = 0; i < matrix_elements; i++)
printf("%d,",yale->A[i]);
printf("\n");
for(int i = 0; i < matrix_rows + 1; i++)
printf("%u,",yale->IA[i]);
printf("\n");
for(int i = 0; i < matrix_elements; i++)
printf("%u,",yale->JA[i]);
return yale;
}
Note: I moved the (ii == 0) {} condition out of the loop, and replaced the one-letter indices by there two-letter equivalents. Also: all the indices are unsigned (as they should be)

Resources