C - Delete spaces around specific char in string - c

Question

I have a string of 80 chars (line from .txt file)
Somewhere at the end of the string I have numbers or strings or chars and "," (comma) between them. I need to delete these spaces around "," so I will be able to get them by strtok().
Any ideas ?
For example :
String : " name: today 12 ,r ,ab, 5 , seven"<br>
I need : " name: today 12,r,ab,5,seven"

Answer 1

You can apply this algorithm ::
Find the element , in this case a space.
Replace the element with an element of your choice, in this case an empty character.
This function might come handy for replacing any character to a string. You might add the char *replace function as a snippet and use it later for similar purposes.
char *replace(const char *the_input_string, char the_character,
const char *replacing_string)
{
int count = 0;
const char *t;
for(t=the_input_string; *t; t++)
count += (*t == the_character);
size_t rlen = strlen(replacing_string);
char *res = (char*)malloc(strlen(the_input_string) + (rlen-1)*count + 1);
char *ptr = res;
for(t=the_input_string; *t; t++)
{
if(*t == the_character)
{
memcpy(ptr, replacing_string, rlen);
ptr += rlen;
}
else
*ptr++ = *t;
}
*ptr = 0;
return res;
}
Driver Program ::
int main(int argc, char const *argv[])
{
const char *s = replace("name: today 12 ,r ,ab, 5 , seven", ' ', "");
printf("%s\n", s);
return 0;
}
Please refer to this link and the code might be verisimilar but use the above code as the solution mentioned there might throw some errors or warnings.

Answer 2

Because the resulting string will be shorter then the original string, you can do the replacement in place: When you find a comma, copy it and skip the following space. To treat the space before the comma, keep track of the first space after the last non-space character and skip that, too if necessary:
#include <stdlib.h>
#include <stdio.h>
#include <ctype.h>
void remspc(char *str)
{
char *first = str; // dest. char after last non-space
char *q = str; // destination pointer
// skip leading white space
while (isspace((unsigned char) *str)) str++;
while (*str) {
if (*str == ',') {
q = first; // skip space before comma
*q++ = *str++;
first = q;
// skip space after comma
while (isspace((unsigned char) *str)) str++;
} else {
// remember last non-space
if (!isspace((unsigned char) *str)) first = q + 1;
*q++ = *str++;
}
}
*first = '\0';
}
int main(void)
{
char str[] = " name: today 12, r ,ab, , 5 , seven";
remspc(str);
puts(str);
return 0;
}
This solution will run commas that are separated by white space together, which may lead to problems with strtok, because it will consider stretches of commas as a single delimiter.

Answer 3

You may give this a try!
Replace with your code where necessary.
#include <stdio.h>
#include <stdlib.h>
int main()
{ int i;
char line[] = "name: today 12 ,r ,ab, 5 , seven";
int length = strlen(line);
char line2[length];
for(i = 0; i<length; i++) {
if(!isspace(line[i])) {
line2[i] = line[i];
}
}
for(i = 0; i<length; i++){
printf("%c", line2[i]);
}
return 0;
}