A simple program for splitting numbers does not display zeroes - c

Question

I wrote a simple program in c that accepts two numbers and then splits the first number considering the digits of the second number like this:
Input:
362903157 2313
Output:
36
290
3
157
Everything works just fine, except when there are zeroes in the first number, my program skips them. For instance the upper example gives me this output:
36 293 1 570
And that is mycode:
#include <stdio.h>
int nDigits(unsigned i) {
int n = 1;
while (i > 9) {
n++;
i /= 10;
}
return n;
}
// find the highest multiple of 10
int multipleOfTen(int num){
int multiple = 1;
while(multiple <= num){
multiple *= 10;
if(multiple > num){
multiple /= 10;
break;
}
}
return multiple;
}
int main(){
int n, m, digit;
scanf("%d %d", &n, &m);
int lengthOfM = nDigits(m);
for (int i = 0; i < lengthOfM; i++){
digit = m / multipleOfTen(m); //2
for(int j = 1; j <= digit; j++){
printf("%d", n/multipleOfTen(n));
n = n% multipleOfTen(n);
}
printf("\n");
m = m % multipleOfTen(m);
}
return 0;
}
What should I change in my program so that the zeroes won't be ignored?

Answer 1

Instead of calling multipleOfTen() in each loop, call it once and save the result for both n and m. Then in each loop divide those results by 10
#include <stdio.h>
int nDigits(unsigned i) {
int n = 1;
while (i > 9) {
n++;
i /= 10;
}
return n;
}
// find the highest multiple of 10
int multipleOfTen(int num){
int multiple = 1;
while(multiple <= num){
multiple *= 10;
if(multiple > num){
multiple /= 10;
break;
}
}
return multiple;
}
int main(){
int n, m, digit;
int i, j;
int n10, m10;
scanf("%d %d", &n, &m);
int lengthOfM = nDigits(m);
n10 = multipleOfTen(n); //get the multiple of ten once
m10 = multipleOfTen(m);
for ( i = 0; i < lengthOfM; i++){
digit = m / m10;
m10 /= 10;
for( j = 0; j < digit; j++){
printf("%d", n/n10);
n = n% n10;
n10 /= 10;// divide by 10
}
printf("\n");
m = m % multipleOfTen(m);
}
return 0;
}

Answer 2

I suppose an approach like this is inadmissible?
#include <stdio.h>
#include <string.h>
int main ( void ) {
char n[64];
char m[64];
char * p = n;
int i = 0;
int c;
scanf("%63[0-9] %63[0-9]", n, m);
while ((c = m[i++]) != '\0') {
int j = c - '0';
while (j-- > 0) if (*p) putchar(*p++);
putchar(' ');
}
putchar('\n');
return 0;
}

Answer 3

when n=903157 and after n = n% multipleOfTen(n); n becomes 3157 not 03157 so when u dividing again in line printf("%d", n/multipleOfTen(n)); it prints 3 not 0 what you want!!
Fix your code to produce right output.