I am using a basic command line program to convert .xml files to .csv. I have it performing the action on all .xml files in the directory using
FOR %I in (..\xmlinput\*.xml) DO XmlToCsv.Console.exe -xml %I -dir ..\csvoutput\
This works fine but all output files are named r.csv, so each time it loops the previous r.csv is overwritten. How can I incrementally rename the output (r1.csv, r2.csv, etc.) before the next loop runs and overwrites the previous output? (the XmlToCsv.Console.exe has no additional parameters to use). Many thanks.
In a batch-file, you can try this:
#echo off
setlocal EnableDelayedExpansion
set "counter=1"
FOR %%I in (..\xmlinput\*.xml) DO (
XmlToCsv.Console.exe -xml %%I -dir ..\csvoutput\
ren "..\csvoutput\r.csv" "r!counter!.csv"
set /a "counter+=1"
)
Note that because this is a batch-file and not a single command you need to use %%I instead of %I. You might also need to change the paths for the rename command.
Related
I didn't find so far a similar question, so I try to explain the problem:
I have large number of files that are in subfolders inside "C:\images"
I have a list of names in two columns, so that 1st column is old filename and 2nd is a new filename. I want to change that list into a batch file.
Names are pretty unique so I want to make batch file - so that will be one command for every file to be renamed.
RENAME "C:\images\768e11ab.jpg" "4ca5d042.jpg"
RENAME "C:\images\5402c708.jpg" "b802820b.jpg"
RENAME "C:\images\1c039e0e.jpg" "80ce9797.jpg"
etc...
It is rather simple, only, files are scattered across subfolders. Is there any way to make a command so it will look for that specific file in all subfolders in "C:\images" and rename it.
Following some similar questions tried this, with no result:
for /r "C:\images\" "%%~G" (768e11ab.jpg) do "4ca5d042.jpg"
Also, tried to use some renaming application for this but they freeze when I try to rename big list of files, so I would avoid them and use batch file. Also, I would like to use this way where there is one line in batch file for every file because it is simpler for me to use it (and change it later). I appreciate your help.
Approach the problem from the other side. Instead of looping over the image files, loop over the text file.
Assuming your textfile to be something like
"768e11ab.jpg" "4ca5d042.jpg"
"5402c708.jpg" "b802820b.jpg"
"1c039e0e.jpg" "80ce9797.jpg"
Then the code could look like:
#echo off
REM read each line; %%A is the first column, %%B is the second one
for /f "tokens=1,2" %%A in (list.txt) do (
REM search the image file %%A
for /R "C:\Images\" %%C in ("%%~A") do (
REM %%C now holds the full path of %%A
ECHO ren "%%~C" "%%B~%%~xC"
)
)
If your list looks different, the tokens and perhaps the delims for the for /f loop have to be adapted.
NOTE: the ren command is just echoed for security reasons. Once you verified it does exactly what you want, remove the ECHO to enable the * ren` command.
I have a good command over cmd commands, but this may require a variable or a loop which is where I fail in batch commands. Please help if you can!
-- Have about 100 subdirectories each has 1-20 HTML files in it. There are about 100 HTML files in the root directory too.
-- Need to replace all HTML files in the above directories with the same HTML source (copy over existing file and keep the name the same). Basically trying to replace all existing files with a redirect script to a new server for direct bookmarked people. We are running a plain webserver without access to server-side redirects so trying to do this just by renaming the files (locked down corp environment).
Seems pretty simple. I can't get it to work with wildcards by copying the same file over to replace. I only get the first file replaced, but the rest of the files will fail. Any one with any advice?
This should do it from the command prompt. Replace % with %% for use in a batch file.
for /r "c:\base\folder" %a in (*.html) do copy /y "d:\redirect.html" "%a"
Without knowing more precisely how you want to update the file content I suggest the following rough approach.
To re-create your example, I had to create some folders. Run this command to do that:
for /l %i in (1,1,20) do mkdir fold%i
I then used this script to create some example files:
#echo off
set number=0
for /d %%i in (c:\Logs\htmltest\*) do call :makefiles %%i
goto :EOF
:makefiles
set /a number+=1
touch %1\file%number%.txt
echo %number% >%1\file%number%.txt
I then used this script to append the text changed to the file. Not sure if that is what you wanted - probably you need something more sophisticated.
#echo off
set number=0
for /d %%i in (c:\Logs\htmltest\*) do #for %%f in ("%%i\*.txt") do call :changetext %%f
goto :EOF
:changetext
echo changing file contents to ^"changed^" for file: %1
echo changed>>%1
I'm a beginner with .bat files, and I'm attempting to rename multiple drawing (.dwg) files using a list generated in notepad. The notepad list contains a list of drawing numbers that look like this:
01013-13000p001
06301-12550p001
etc..
There is hundreds of them, and I want to take those numbers from the text and put it into a blank series of dwg files that are generic named for now (drawing.dwg, drawing(2).dwg, drawing(3).dwg etc..) I've only come up with a way to read a text file, but cant figure out how to take from the text file and rename multiple drawing files with it. Below is as far as I have gotten, after failed attempts of trying to take whats read from a text file and put it into the .dwg files. I plan on working this out in all the same directory, and any suggestions will be greatly appreciated. Thanks.
#echo off
for /f "tokens=* delims=" %%x in (dwgNumbers.txt.txt) do echo %%x
pause
would
for /f "delims=" %%x in (dwgNumbers.txt.txt) do echo copy /b "blank generic drawing.dwg" "%%x.dwg"
(as a batch line) do what you want? - note that the ECHO keyword is there to show what would be done. The echo keyword needs to be removed to actually execute the copy.
This will take the numbers from .txt, renaming the existing .dwg files with the data readed. If there are more files that numbers in .txt, it will rename until number exhaustion, no more.
for loop is using a dir command to get the list of files to avoid the case of files that after being renamed falls under the filter of the for and gets reprocessed.
This code has a echo command included in rename line to prevent data loss in case of malfunction. When the output to console is what is needed, remove the echo command from the rename line.
#echo off
rem Prepare environment
setlocal enableextensions enabledelayedexpansion
rem Read input file for numbers
< dwgNumbers.txt (
rem Process dwg files in directory
for /f "tokens=*" %%f in ('dir /b *.dwg') do (
rem Get number from input file
set "number="
set /p "number="
rem If there is a number, rename the file
if defined number echo ren "%%~f" "!number!.dwg"
)
)
rem Clean
endlocal
I'm having trouble trying to copy and rename a file using only dos commands. I have a file of the format myfile20130218 and want to copy and rename it to some_other_file_20130218.
I know I can use copy source dest but I'm having trouble with how to isolate the date and preserve it. I cannot guarantee that he date will be today's date so that is ruled out, the source file will always be the same name.
I can run either a series of commands or a batch script, but thing that that I am currently having trouble with, is after I find a match that I need to copy, using myfile????????, how can I now get those file names to pull the dates off them?
EDIT: for clarification I will be looking at files in a known directory, as above, I will know the format of the file name, and will only be checking a specific directory for it. The process that checks the directory is a ConnectDirect file watcher, so when a file is found matching myfile20130218 I can fire off some commands, but don't know how to check the directory and get the name of the file present.
Something like this should work:
%oldname:~-8% extracts the last 8 characters from %oldname% which are then appended to the new filename.
Update: If you can identify the file with an external program and then call the batch script with the file name
copyfile.cmd C:\path\to\myfile20130218
you could do something like this:
set oldname=%~nx1
set newname=%~dp1some_other_file_%oldname:~-8%
copy "%~f1" "%newname%"
Update 2: If you know folder and the format you could call the script with the folder
copyfile.cmd C:\folder
and do something like this:
#echo off
setlocal EnableDelayedExpansion
for /f %%f in (
'dir /b "%~f1" ^| findstr /r "myfile[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]$"'
) do (
set oldname=%~f1\%%f
set newname=%~f1\my_other_name_!oldname:~-8!
copy "!oldname!" "!newname!"
)
endlocal
Edit: Script breakdown.
setlocal EnableDelayedExpansion enables variable expansion inside loops and conditionals.
for /f %%f in ('...') executes the command between the single quotes and then loops over the output of that command.
dir /b "%~f1" lists the content of the given directory (%~f1 expands to the full path of the first argument passed to the script) in simple mode (no header, no summary).
findstr /r "myfile[0-9]...[0-9]$" filters the input for strings that end with the substring "myfile" followed by 8 digits. The circumflex before the pipe (^|) escapes the pipe, because otherwise it would take precedence over the for command, which would effectively split the for command in half, resulting in an invalid command-line.
set oldname=%~f1\%%f assign the full path to a matching file to the variable oldname.
set newname=%~f1\my_other_name_!oldname:~-8! assign the full path to the new filename ("my_other_name_" followed by the trailing 8 digits from oldname) to the variable newname.
copy "!oldname!" "!newname!" I don't need to explain this, do I?
I have a directory full of files output from some software as below:
Pending.001
Pending.002
Pending.003
etc.
I would like to use a .bat to rename them as below:
Pending001.csv
Pending002.csv
Pending003.csv
etc.
Any suggestions?
You could rename your files in a loop, using the modifiers ~n and ~x on the loop variable to extract, respectively, the name and the extension of each file to concatenate them in the new name. As the extension would be extracted together with the leading ., you would also need a variable to temporarily store the extension before removing the ..
Here's an example of how the above could be implemented:
#ECHO OFF
FOR %%I IN (Pending.*) DO (
SET "ext=%%~xI"
SETLOCAL EnableDelayedExpansion
RENAME "%%I" "%%~nI!ext:~1!.csv"
ENDLOCAL
)
The delayed expansion is enabled because it is needed for the evaluation of ext. "Normal" expansion, which uses %, wouldn't work here because that way the variable would be expanded just once before the loop started, when the variable was still empty. In contrast, with the delayed expansion, the variable will be expanded every time the particular command containing it is executed, i.e. on every iteration of the loop too.
The above batch file would process files in the current directory, i.e. you would first need to change to the directory where the files need to be processed, then call the batch. Or, if you would be doing that in e.g. Windows Explorer, you would likely need to copy that batch to the directory with the files to process and call it from there.
Alternatively, though, you might want to call it with a parameter specifying the directory to process. To use the parameter, change the script like this:
#ECHO OFF
FOR %%I IN ("%~1\Pending.*") DO (
SET "ext=%%~xI"
SETLOCAL EnableDelayedExpansion
RENAME "%%I" "%%~nI!ext:~1!.csv"
ENDLOCAL
)
Of course, you could also just specify a fixed path to the files if they are always in the same directory:
#ECHO OFF
FOR %%I IN ("D:\path\to\files\Pending.*") DO (
SET "ext=%%~xI"
SETLOCAL EnableDelayedExpansion
RENAME "%%I" "%%~nI!ext:~1!.csv"
ENDLOCAL
)
That way you would be able to call the batch from wherever you stored it.
Why don't you refer to these posts:
How can I mass rename files from the command line or using a 3rd party tool?
Bulk Rename Command
Bulk Rename Utility
Using batch files