Calendar Programming Project in C. Too complicated for this newbie [closed] - c

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#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <math.h>
void main()
{
int numdays, month, day, year = 1;
while (year > 0)`enter code here`
{
printf("Enter Month: ");
scanf("%d", &month);
printf("Enter Day: ");
scanf("%d", &day);
printf("Enter Year: ");
scanf("%d", &year);
numdays = ((year - 1) * 365 + ((year - 1) / 4) - ((year - 1) / 100) + ((year - 1) / 400)); // how many days including exceptions
if (((year % 4 == 0) && (year % 100 != 0)) || (year % 400 == 0)) //check if leapyear
{
if (month = 1) // January
numdays = numdays;
if (month = 2) // February
numdays = numdays + 31;
if (month = 3) // March
numdays = numdays + 28 + 31 + 1;
if (month = 4) // April
numdays = numdays + 31 + 28 + 31 + 1;
if (month = 5) // May
numdays = numdays + 30 + 31 + 28 + 31 + 1;
if (month = 6) // June
numdays = numdays + 31 + 30 + 31 + 28 + 31 + 1;
if (month = 7) // July
numdays = numdays + 30 + 31 + 30 + 31 + 28 + 31 + 1;
if (month = 8) // August
numdays = numdays + 31 + 30 + 31 + 30 + 31 + 28 + 31 + 1;
if (month = 9) // September
numdays = numdays + 31 + 31 + 30 + 31 + 30 + 31 + 28 + 31 + 1;
if (month = 10) // October
numdays = numdays + 30 + 31 + 31 + 30 + 31 + 30 + 31 + 28 + 31 + 1;
if (month = 11) // November
numdays = numdays + 31 + 30 + 31 + 31 + 30 + 31 + 30 + 31 + 28 + 31 + 1;
if (month = 12) // December
numdays = numdays + 30 + 31 + 30 + 31 + 31 + 30 + 31 + 30 + 31 + 28 + 31 + 1;
}
else
{
if (month = 1) // January
numdays = numdays;
if (month = 2) // February
numdays = numdays + 31;
if (month = 3) // March
numdays = numdays + 28 + 31;
if (month = 4) // April
numdays = numdays + 31 + 28 + 31;
if (month = 5) // May
numdays = numdays + 30 + 31 + 28 + 31;
if (month = 6) // June
numdays = numdays + 31 + 30 + 31 + 28 + 31;
if (month = 7) // July
numdays = numdays + 30 + 31 + 30 + 31 + 28 + 31;
if (month = 8) // August
numdays = numdays + 31 + 30 + 31 + 30 + 31 + 28 + 31;
if (month = 9) // September
numdays = numdays + 31 + 31 + 30 + 31 + 30 + 31 + 28 + 31;
if (month = 10) // October
numdays = numdays + 30 + 31 + 31 + 30 + 31 + 30 + 31 + 28 + 31;
if (month = 11) // November
numdays = numdays + 31 + 30 + 31 + 31 + 30 + 31 + 30 + 31 + 28 + 31;
if (month = 12) // December
numdays = numdays + 30 + 31 + 30 + 31 + 31 + 30 + 31 + 30 + 31 + 28 + 31;
{
printf("%d %d %d\n", month, day, year);
}
int daycode = numdays % 7;
switch (daycode)
{
case 0:
printf("Sunday\n");
break;
case 1:
printf("Monday\n");
break;
case 2:
printf("Tuesday\n");
break;
case 3:
printf("Wednesday\n");
break;
case 4:
printf("Thursday\n");
break;
case 5:
printf("Friday\n");
break;
case 6:
printf("Saturday\n");
break;
default: printf("unexpected error (daycode case) daycode = %d", daycode);
break;`enter code here`
}
}
}
}
What I need to do is get the output to read what the day would be on the given date input by the user. However, I don't understand why my month is being locked at 12 for input. Any help is appreciated.

Answer 1

As mentioned in a comment by MrPickles, the main problem is that you are mixing up the assignment operator = with the comparison operator ==. The former (=) sets the variable on the left to whatever is on the right, while == checks if the right hand and left hand sides are equal. Your last if statement is setting month to 12 instead of checking if it's 12.
Another big problem is that your code to print out the solution is inside your else statement, so it doesn't run at all if it's a leap year. Make sure to move it out.
Finally, you never actually use the day of the month in your code. You need to put in something like numdays+=day;.
Other than that, you could make the code much shorter, but I think it's right besides that.