C - Read a file line by line - c

Question

I'm trying to read a file line by line with any value to BUFF_SIZE, but it doesn't work.
The returned value:
3
1 - #include <stdio.h>
#
1 - include <stdlib.h>
#
1 - include <fcntl.h>
#i
1 - nclude "libft/libft.h"
Why they missing chars in my strings ?
My source code (main.c):
#include <stdio.h>
#include <stdlib.h>
#include <fcntl.h>
#include "libft/libft.h"
# define BUFF_SIZE 3
int get_next_line(int const fd, char **line)
{
static char *buffer;
char *tmp;
int ret;
char *endl;
if (!buffer && !(buffer = ft_memalloc(BUFF_SIZE + 1)))
return (-1);
tmp = ft_strnew(0);
endl = ft_strchr(buffer, '\n');
while (endl == NULL)
{
if ((ret = read(fd, buffer, BUFF_SIZE)) > 0)
{
buffer[ret] = '\0';
endl = ft_strchr(buffer, '\n');
tmp = ft_strjoin(tmp, buffer);
}
else if (ret < 0)
return (-1);
else if (ret == 0)
{
if ((endl = ft_strchr(buffer, '\0')) == buffer)
return (0);
}
}
*line = ft_strdup(tmp);
ft_memmove(buffer, endl + 1, ft_strlen(endl + 1) + 1);
return (1);
}
int main(void)
{
int fd;
int ret;
char *line;
if ((fd = open("main.c", O_RDONLY)) < 3 && fd != 0)
return (-1);
printf("%d\n", fd);
ret = get_next_line(fd, &line);
printf("%d - %s\n", ret, line);
ret = get_next_line(fd, &line);
printf("%d - %s\n", ret, line);
ret = get_next_line(fd, &line);
printf("%d - %s\n", ret, line);
ret = get_next_line(fd, &line);
printf("%d - %s\n", ret, line);
return (0);
}
Someone can help me to resole this ?