Remove elements from an array in bash - arrays

Question

So I just need to remove matching pairs in an array. My array consists of a deck of cards. If an element is a pair, for example if the array $sortedHand is: SA DA C9 C8
Because their is a pair of aces in spades and diamonds. I need to remove it from the array $sortedHand
So then the new variable maybe $removedHand would only contain C9 C8. Hope you understand
#!/bin/bash
declare -a cards=(null SA HA DA CA SK HK DK CK SQ HQ DQ CQ SJ HJ DJ CJ ST HT DT CT S9 H9 D9 C9 S8 H8 D8 C8 S7 $
declare -a sortedHand
for i
do
hand+=' '${cards[i]}
done
set -- $(printf "%d\n" "$#" | sort -n)
for i
do
sortedHand+=' '${cards[i]}
done
echo The hand is $hand
echo Sorted hand $sortedHand
Edit I have added code
#!/bin/bash
declare -a cards=(null SA HA DA CA SK HK DK CK SQ HQ DQ CQ SJ HJ DJ CJ ST HT DT CT S9 H9 D9 C9 S8 H8 D8 C8 S7 $
for i
do
hand+=' '${cards[i]}
done
set -- $(printf "%d\n" "$#" | sort -n)
for i
do
sortedHand+=' '${cards[i]}
done
echo The hand is $hand
echo Sorted hand $sortedHand
for((i=0; i -le ${#hand}; ++i))
do
for((j=0; j -le ${#hand}; ++j))
do
if [ $i == $j ]
then continue
fi
if [ ${hand[i]:1:1} == ${hand[j]:1:1} ]
then continue 2
fi
done
sortedHand+=' '${hand[i]}
done
echo Remaining cards $sortedHand
This is the output I get
turtle.sh 1 2 5 10
The hand is SA HA SK HQ
Sorted hand SA HA SK HQ
./turtle.sh: line 23: ((: i -le 12: syntax error in expression (error token is "12")
Remaining cards SA HA SK HQ
Help please
Another Edit
#!/bin/bash
declare -a cards=(null SA HA DA CA SK HK DK CK SQ HQ DQ CQ SJ HJ DJ CJ ST HT DT CT S9 H9 D9 C9 S8 H8 D8 C8 S7 $
for i
do
hand+=' '${cards[i]}
done
set -- $(printf "%d\n" "$#" | sort -n)
for i
do
sortedHand+=' '${cards[i]}
done
echo The hand is $hand
echo Sorted hand $sortedHand
for((i=0; i-le${#sortedHand}; ++i))
do
for((j=0; j-le${#sortedHand}; ++j))
do
if [ $i == $j ]
then continue
fi
if [ ${sortedHand[i]:1:1} == ${sortedHand[j]:1:1} ]
then continue 2
fi
done
remainingHand+=${hand[i]}
done
echo Remaining cards $remainingHand
The outcome of above code
turtle.sh 1 2 5 10
The hand is SA HA SK HQ
Sorted hand SA HA SK HQ
Remaining cards
Thanks for all your help
Also tried your exact code
turtle.sh 1 2 5 10
The hand is SA HA SK HQ
Sorted hand SA HA SK HQ
Remaining cards SA HA SK HQ

Answer 1

Loop through hand and loop through hand again from the current index of the outer loop.
Compare the second letter of the elements and add index to sortedHand if no matches were found.
That would look like this:
cards=(null SA HA DA CA SK HK DK CK SQ HQ DQ CQ SJ HJ DJ CJ ST HT DT CT S9 H9 D9 C9 S8 H8 D8 C8 S7)
for i in $# # $# are all passed arguments, if this gives issues try putting quotes around it
do hand+=(cards[i])
done
for((i=0; i < ${#hand[#]}; ++i)) # C style loop, uses i and <, not $i and -le.
do
for((j=0; j < ${#hand[#]}; ++j)) # ${#hand[#]} is the number of elements in the array hand.
do
if [ $i == $j ]
then continue
fi
if [ ${hand[i]:1:1} == ${hand[j]:1:1} ]
then continue 2
fi
done
sortedHand+=(${hand[i]})
done
echo ${hand[#]} # ${hand[#]} is the array in string representation.
echo ${sortedHand[#]}

Answer 2

To delete an element from an array, use the unset command (with quotes to avoid pathname expansion):
#!/bin/bash
declare -a cards=(null SA HA DA CA SK HK DK CK SQ HQ DQ CQ SJ HJ DJ CJ ST HT DT CT S9 H9 D9 C9 S8 H8 D8 C8 S7 $)
echo "${cards[#]}" # null SA HA DA CA SK HK DK CK SQ HQ DQ CQ SJ HJ DJ CJ ST HT DT CT S9 H9 D9 C9 S8 H8 D8 C8 S7 $
unset 'cards[1]'
echo "{cards[#]}" # null HA DA CA SK HK DK CK SQ HQ DQ CQ SJ HJ DJ CJ ST HT DT CT S9 H9 D9 C9 S8 H8 D8 C8 S7 $