Converting XML data to SQL table - sql-server

Question

I have the following XML data with me. I need to convert this to SQL table.
<SalesDetails>
<Customer Name="Johny" DateofBirth="1990-01-02T00:00:00">
<OrderInfo>
<OrderDate>1993-02-03T00:00:00</OrderDate>
<OrderAmount>1000</OrderAmount>
</OrderInfo>
</Customer>
</SalesDetails>
Can anyone help me with a SQL query that gives the above XML file as output?
In my initial attempt, I have created two tables #TI and #T2. I had then inserted different values into it. I had then queried it as :
SELECT
(SELECT * FROM #T1 FOR XML RAW('Sales') , TYPE),
(SELECT * FROM #T2 FOR XML PATH('OrderInfo') , TYPE)
FOR XML PATH('') , ROOT('SalesDetails')
But I need the output in the first XML format based on SQL tables and corresponding joins. That is, when the name of a customer is displayed, his corresponding order information needs to be displayed. I do not want it in a grouped format.

Answer 1

Sorry, in my first attempt I completely misread your question and thought you'd like to get the data out of your XML. This is the approach to create such an XML out of table's data:
DECLARE #cust TABLE(ID INT, CustomerName VARCHAR(100),DateOfBirth DATE);
INSERT INTO #cust VALUES(1,'Jonny','1990-01-02T00:00:00')
,(2,'Jimmy','1980-01-02T00:00:00');
DECLARE #ord TABLE(ID INT,CustomerID INT,OrderDate DATE, OrderAmount INT);
INSERT INTO #ord VALUES(1,1,'1993-02-03T00:00:00',1000)
,(2,1,'1994-02-03T00:00:00',500)
,(3,2,'1994-02-03T00:00:00',200);
SELECT c.CustomerName AS [#Name]
,c.DateOfBirth AS [#DateofBirth]
,(
SELECT o.OrderDate
,o.OrderAmount
FROM #ord AS o
WHERE o.CustomerID=c.ID
FOR XML PATH('OrderInfo'),TYPE
)
FROM #cust AS c
FOR XML PATH('Customer'),ROOT('SalesDetails')
And this is the created XML
<SalesDetails>
<Customer Name="Jonny" DateofBirth="1990-01-02">
<OrderInfo>
<OrderDate>1993-02-03</OrderDate>
<OrderAmount>1000</OrderAmount>
</OrderInfo>
<OrderInfo>
<OrderDate>1994-02-03</OrderDate>
<OrderAmount>500</OrderAmount>
</OrderInfo>
</Customer>
<Customer Name="Jimmy" DateofBirth="1980-01-02">
<OrderInfo>
<OrderDate>1994-02-03</OrderDate>
<OrderAmount>200</OrderAmount>
</OrderInfo>
</Customer>
</SalesDetails>
Just for the case you want to read your XML, I let this appended
You can retrieve all the information like this:
The generated Index columns are IDs you can use to insert this into relational tables. The problem with your XML is, that the information about your target tabels is missing. But the rest should be easy for you.
Btw: I declared some more similar nodes to make the relational structure visible
DECLARE #x XML=
'<SalesDetails>
<Customer Name="Johny" DateofBirth="1990-01-02T00:00:00">
<OrderInfo>
<OrderDate>1993-02-03T00:00:00</OrderDate>
<OrderAmount>1000</OrderAmount>
</OrderInfo>
<OrderInfo>
<OrderDate>1994-02-03T00:00:00</OrderDate>
<OrderAmount>500</OrderAmount>
</OrderInfo>
</Customer>
<Customer Name="Jimmy" DateofBirth="1980-01-02T00:00:00">
<OrderInfo>
<OrderDate>1994-02-03T00:00:00</OrderDate>
<OrderAmount>200</OrderAmount>
</OrderInfo>
<OrderInfo>
<OrderDate>1993-02-03T00:00:00</OrderDate>
<OrderAmount>100</OrderAmount>
</OrderInfo>
</Customer>
</SalesDetails>';
WITH CustomerNodes AS
(
SELECT ROW_NUMBER() OVER(ORDER BY (SELECT NULL)) AS CustomerIndex
,Customer.value('#Name','varchar(max)') AS CustomerName
,Customer.value('#DateofBirth','date') AS CustomerDateOfBirth
,One.Customer.query('.') AS CustomerNode
FROM #x.nodes('SalesDetails/Customer') AS One(Customer)
)
SELECT cn.*
,ROW_NUMBER() OVER(PARTITION BY cn.CustomerIndex ORDER BY (SELECT NULL)) AS OrderIndex
,OrderInfo.value('OrderDate[1]','date') AS OrderDate
,OrderInfo.value('OrderAmount[1]','int') AS OrderAmount
FROM CustomerNodes AS cn
CROSS APPLY cn.CustomerNode.nodes('Customer/OrderInfo') As The(OrderInfo)
The result:
Customer Order
ID Name DateOfBirth ID OrderDate OrderAmount
1 Johny 1990-01-02 1 1993-02-03 1000
1 Johny 1990-01-02 2 1994-02-03 500
2 Jimmy 1980-01-02 1 1994-02-03 200
2 Jimmy 1980-01-02 2 1993-02-03 100