Query to get columns metadata, key and index - sql-server

How to get column metadata for a table or view in following format
column_name column_data_type column_data_length index key
-----------------------------------------------------------------------------
column1 int 4 CLUSTERED PRIMARYKEY
column2 int 4 NONCLUSTERED FOREIGNKEY
column3 varchar 20 NULL NULL

SELECT
C.TABLE_SCHEMA+'.'+ C.TABLE_NAME as TableName,
C.COLUMN_NAME as ColumnName,
C.DATA_TYPE as ColumnDataType,
C.CHARACTER_MAXIMUM_LENGTH as ColumnDataTypeLength,
(CASE
WHEN K.CONSTRAINT_NAME like 'PK_%' then 'PRIMARYKEY'
WHEN K.CONSTRAINT_NAME like 'FK_%' then 'FOREIGNKEY'
ELSE NULL
END) as [Keys],
(SELECT
i.[type_desc]
FROM
[sys].[indexes] AS i
INNER JOIN
[sys].[index_columns] AS ic
ON i.[object_id] = ic.[object_id]
AND i.index_id = ic.index_id
INNER JOIN
[sys].[columns] co
ON ic.column_id = co.column_id
AND ic.[object_id] = co.[object_id]
WHERE
i.[object_id] = OBJECT_ID(C.TABLE_SCHEMA+'.'+ C.TABLE_NAME)
AND co.name=C.COLUMN_NAME
) AS [Indexes]
FROM
INFORMATION_SCHEMA.COLUMNS C LEFT JOIN INFORMATION_SCHEMA.KEY_COLUMN_USAGE K
ON C.COLUMN_NAME=k.COLUMN_NAME
AND C.TABLE_NAME=K.TABLE_NAME
WHERE C.TABLE_SCHEMA+'.'+ C.TABLE_NAME =#tableName
ORDER BY C.ORDINAL_POSITION ASC

Related

Optimize long query to find database schema with foreign keys and tables

I am writing a query to get all the tables in the db with their properties but also foreign keys and table that each reference to. I have a following query but it is taking 60 min to complete. Not sure what am I doing wrong?
SELECT
ist.table_name,
isc.column_name,
data_type,
character_maximum_length,
Columnproperty(Object_id(isc.table_name),
isc.column_name, 'IsIdentity') AS identityFlag,
is_nullable,
character_maximum_length,
numeric_scale,
(SELECT 1
FROM information_schema.table_constraints AS C
JOIN information_schema.key_column_usage AS K ON C.table_name = K.table_name
AND C.constraint_catalog = K.constraint_catalog
AND C.constraint_schema = K.constraint_schema
AND C.constraint_name = K.constraint_name
WHERE C.constraint_type = 'PRIMARY KEY'
AND C.table_name = isc.table_name
AND K.column_name = isc.column_name) AS primarykey,
(SELECT TOP 1 1
FROM information_schema.table_constraints AS C
JOIN information_schema.key_column_usage AS K ON C.table_name = K.table_name
AND C.constraint_catalog = K.constraint_catalog
AND C.constraint_schema = K.constraint_schema
AND C.constraint_name = K.constraint_name
WHERE C.constraint_type = 'FOREIGN KEY'
AND C.table_name = isc.table_name
AND K.column_name = isc.column_name) AS foreignKey,
a.parenttablename AS foreignTableName,
a.colname AS foreignColumnName
FROM
information_schema.tables ist
INNER JOIN
information_schema.columns isc ON ist.table_name = isc.table_name
LEFT OUTER JOIN
(SELECT
t.NAME AS parentTableName,
Object_name(f.parent_object_id) TableName,
Col_name(fc.parent_object_id, fc.parent_column_id) ColName
FROM
sys.foreign_keys AS f
INNER JOIN
sys.foreign_key_columns AS fc ON f.object_id = fc.constraint_object_id
INNER JOIN
sys.tables t ON t.object_id = fc.referenced_object_id) a ON a.tablename = ist.table_name
AND a.colname = isc.column_name
It is taking time to find the foreign table names. What is the best way to get db table schema
Firstly, you should stick to the sys schema, as these catalog views are more efficient, and INFORMATION_SCHEMA is only for compatibility
You are over-complicating it. You don't need to query the foreign key twice, you can just check if the LEFT JOIN succeeded by checking for NULL
SELECT
t.name AS table_name,
c.name AS column_name,
typ.name AS data_type,
c.max_length,
c.is_identity AS identityFlag,
c.is_nullable,
c.precision,
c.scale,
CASE WHEN EXISTS (SELECT 1
FROM sys.indexes AS i
JOIN sys.index_columns AS ic
ON ic.object_id = i.object_id
AND ic.index_id = i.index_id
WHERE i.object_id = t.object_id
AND ic.column_id = c.column_id
) THEN 1 ELSE 0 END AS primarykey,
CASE WHEN t_f.name IS NOT NULL THEN 1 ELSE 0 END AS foreignKey,
t_f.name AS foreignTableName,
c_f.name AS foreignColumnName
FROM
sys.tables t
INNER JOIN
sys.columns c ON c.object_id = t.object_id
INNER JOIN
sys.types typ ON typ.user_type_id = c.user_type_id
LEFT OUTER JOIN
sys.foreign_key_columns AS fc
INNER JOIN
sys.tables t_f ON t_f.object_id = fc.referenced_object_id
INNER JOIN
sys.columns c_f ON c_f.object_id = t_f.object_id
AND c_f.column_id = fc.referenced_column_id
ON fc.parent_object_id = t.object_id
AND fc.parent_column_id = c.column_id;

how to find out the column dependencies of a table

I have written a query to find out column names of tables in the database.
SELECT
t.NAME AS TABLEName,
SCHEMA_NAME(schema_id) + '.' + c.name AS ColumnName
FROM
sys.tables t
INNER JOIN sys.columns c
ON c.object_id = t.object_id
WHERE OBJECT_NAME(c.object_id) LIKE '%Message%'
ORDER BY t.NAME
So far I've got the expected result, but whatever column I am looking I want to find out the dependency of column related tables. By executing the above query I am getting table names and column names.
How can I get the column related dependent tables?
Try this:
SELECT KCU1.TABLE_CATALOG,
KCU1.TABLE_SCHEMA,
KCU1.TABLE_NAME,
KCU1.COLUMN_NAME,
KCU2.TABLE_NAME AS REFERENCED_TABLE_NAME,
KCU2.COLUMN_NAME AS REFERENCED_COLUMN_NAME
FROM INFORMATION_SCHEMA.KEY_COLUMN_USAGE AS KCU1
JOIN INFORMATION_SCHEMA.REFERENTIAL_CONSTRAINTS AS RC
ON KCU1.CONSTRAINT_CATALOG = RC.CONSTRAINT_CATALOG
AND KCU1.CONSTRAINT_SCHEMA = RC.CONSTRAINT_SCHEMA
AND KCU1.CONSTRAINT_NAME = RC.CONSTRAINT_NAME
JOIN INFORMATION_SCHEMA.KEY_COLUMN_USAGE AS KCU2
ON KCU2.CONSTRAINT_CATALOG = RC.UNIQUE_CONSTRAINT_CATALOG
AND KCU2.CONSTRAINT_SCHEMA = RC.UNIQUE_CONSTRAINT_SCHEMA
AND KCU2.CONSTRAINT_NAME = RC.UNIQUE_CONSTRAINT_NAME
AND KCU2.ORDINAL_POSITION = KCU1.ORDINAL_POSITION
WHERE KCU1.TABLE_NAME LIKE '%Message%'
ORDER BY
KCU1.TABLE_NAME,
KCU1.COLUMN_NAME
This might help. You will however need to tweak it a bit to suit your specific need:
SELECT OBJECT_NAME(referenced_major_id) AS ReferingObject,
(SELECT o.type_Desc FROM sys.objects o
WHERE o.object_id = d.referenced_major_id) AS ReferingObjType,
CASE WHEN referenced_minor_id <> 0 THEN COL_NAME(referenced_major_id, referenced_minor_id)
ELSE '' END AS RefColumnName,
OBJECT_NAME(object_ID) AS ReferencedObject,
(SELECT o.type_Desc FROM sys.objects o
WHERE o.object_id = d.object_id) AS ReferedObjType
fROM sys.sql_dependencies d
If you're looking for all tables/columns that reference a column in the table whose name contains token Message, you can use this:
;WITH PT AS (
SELECT
tc1.TABLE_NAME,
tc2.COLUMN_NAME
FROM
INFORMATION_SCHEMA.TABLE_CONSTRAINTS tc1
JOIN INFORMATION_SCHEMA.KEY_COLUMN_USAGE tc2
ON tc1.CONSTRAINT_NAME = tc2.CONSTRAINT_NAME
WHERE tc1.CONSTRAINT_TYPE = 'PRIMARY KEY')
SELECT
FK_Table = FK.TABLE_NAME,
FK_Column = CU.COLUMN_NAME,
PK_Table = PK.TABLE_NAME,
PK_Column = PT.COLUMN_NAME,
Constraint_Name = C.CONSTRAINT_NAME
FROM
INFORMATION_SCHEMA.REFERENTIAL_CONSTRAINTS C
JOIN INFORMATION_SCHEMA.TABLE_CONSTRAINTS FK
ON C.CONSTRAINT_NAME = FK.CONSTRAINT_NAME
JOIN INFORMATION_SCHEMA.TABLE_CONSTRAINTS PK
ON C.UNIQUE_CONSTRAINT_NAME = PK.CONSTRAINT_NAME
JOIN INFORMATION_SCHEMA.KEY_COLUMN_USAGE CU
ON C.CONSTRAINT_NAME = CU.CONSTRAINT_NAME
JOIN PT
ON PT.TABLE_NAME = PK.TABLE_NAME
WHERE PK.TABLE_NAME LIKE '%Message%'
ORDER BY
FK.TABLE_NAME,
CU.COLUMN_NAME,
PK.TABLE_NAME,
PT.COLUMN_NAME

How may I find all primary keys in a database and their identity and seed values?

The following query returns a listing of all my database primary keys and additional columns.
SELECT *
FROM sysobjects AS s
WHERE xtype='pk'
None of the aforementioned additional columns are related to a primary key's identity, seed value, increment value, etc.
What query should I use, or how may I find all primary keys in a database and their identity and seed values?
UPDATED
(now uses identity_columns table instead of the IDENT_... functions)
SELECT object_name(i.object_id) tableName,
i.name indexName,
c.name columnName,
c.is_identity,
idc.seed_value,
idc.increment_value,
idc.last_value
FROM sys.indexes i
INNER JOIN sys.index_columns ic ON ic.object_id = i.object_id AND ic.index_id = i.index_id
INNER JOIN sys.columns c ON c.object_id = ic.object_id AND c.column_id = ic.column_id
LEFT OUTER JOIN sys.identity_columns idc ON idc.object_id = c.object_id AND idc.column_id = c.column_id
WHERE i.is_primary_key = 1
Here is an alternate answer b/c I combined selects and added create and modified dates for sorting and schema name for possible dupes between schemas b/c key names are unique:
SELECT schema_name = ( SELECT top 1 pk.CONSTRAINT_SCHEMA FROM information_schema.table_constraints pk INNER JOIN information_schema.key_column_usage c ON c.TABLE_NAME = pk.TABLE_NAME WHERE pk.CONSTRAINT_NAME like '%' + i.name + '%')
,object_name(i.object_id) tableName, i.name indexName, c.name columnName, c.is_identity
,ident_seed(object_name(i.object_id)) seed
,ident_incr(object_name(i.object_id)) increment
,ident_current(object_name(i.object_id)) lastAssignedId
,CreateDate = ( SELECT s.crdate FROM sysobjects s INNER JOIN (SELECT COUNT(1) cnt, xtype FROM sysobjects group by xtype) c ON s.xtype = c.xtype WHERE s.name = i.name)
,ModifiedDate = (SELECT s.refdate FROM sysobjects s INNER JOIN (SELECT COUNT(1) cnt, xtype FROM sysobjects group by xtype) c on s.xtype = c.xtype WHERE s.name = i.name)
FROM sys.indexes i
INNER JOIN sys.index_columns ic ON ic.object_id = i.object_id AND ic.index_id = i.index_id
INNER JOIN sys.columns c ON c.object_id = ic.object_id AND c.column_id = ic.column_id
WHERE i.is_primary_key = 1
ORDER BY ModifiedDate, CreateDate DESC

Finding targeted columns in an FK

If I have a pair of SQL tables, one of these tables has a pk on one column and a unique index on another (maybe a guid and id or some other unique key).
The other table has an fk to the unique index, not the pk. Is there a way I can query information schema to find the column targeted by the fk?
If I get you right, you want to use metadatabase:
SELECT
K_Table = FK.TABLE_NAME,
FK_Column = CU.COLUMN_NAME,
PK_Table = PK.TABLE_NAME,
PK_Column = PT.COLUMN_NAME,
Constraint_Name = C.CONSTRAINT_NAME
FROM INFORMATION_SCHEMA.REFERENTIAL_CONSTRAINTS C
INNER JOIN INFORMATION_SCHEMA.TABLE_CONSTRAINTS FK ON C.CONSTRAINT_NAME = FK.CONSTRAINT_NAME
INNER JOIN INFORMATION_SCHEMA.TABLE_CONSTRAINTS PK ON C.UNIQUE_CONSTRAINT_NAME = PK.CONSTRAINT_NAME
INNER JOIN INFORMATION_SCHEMA.KEY_COLUMN_USAGE CU ON C.CONSTRAINT_NAME = CU.CONSTRAINT_NAME
INNER JOIN (
SELECT i1.TABLE_NAME, i2.COLUMN_NAME
FROM INFORMATION_SCHEMA.TABLE_CONSTRAINTS i1
INNER JOIN INFORMATION_SCHEMA.KEY_COLUMN_USAGE i2 ON i1.CONSTRAINT_NAME = i2.CONSTRAINT_NAME
WHERE i1.CONSTRAINT_TYPE = 'PRIMARY KEY'
) PT ON PT.TABLE_NAME = PK.TABLE_NAME
Source: http://blog.sqlauthority.com/2006/11/01/sql-server-query-to-display-foreign-key-relationships-and-name-of-the-constraint-for-each-table-in-database/
Try this one -
SELECT
column_name = c.name
, table_name = OBJECT_NAME(k.parent_object_id)
, referenced_column_name = rc.name
, referenced_table_name = OBJECT_NAME(k.referenced_object_id)
FROM sys.foreign_key_columns k
JOIN sys.columns c ON c.[object_id] = k.parent_object_id AND c.column_id = k.parent_column_id
JOIN sys.columns rc ON rc.[object_id] = k.referenced_object_id AND rc.column_id = k.referenced_column_id
select object_name(fk.REFERENCED_OBJECT_ID) object_name,
i.name index_name,
ic.index_column_id sequence,
c.name column_name
from sys.foreign_keys fk
join sys.indexes i on i.object_id = fk.REFERENCED_OBJECT_ID
and i.index_id = fk.KEY_INDEX_ID
join sys.index_columns ic on ic.object_id = fk.REFERENCED_OBJECT_ID
and ic.index_id = fk.KEY_INDEX_ID
join sys.columns c on c.object_id = fk.REFERENCED_OBJECT_ID
and c.column_id = ic.column_id
where fk.name = 'fk_tbl2_to_tbl1';
e.g.
Setup:
create table tbl1 (
a int constraint pk_tbl1 primary key,
b int constraint uq_tbl1 unique,
c int);
create table tbl2 (
b int constraint fk_tbl2_to_tbl1 references tbl1(b),
d int);
Results:
| OBJECT_NAME | INDEX_NAME | SEQUENCE | COLUMN_NAME |
-----------------------------------------------------
| tbl1 | uq_tbl1 | 1 | b |
SQL Fiddle Demo
--FIND COLUMNS THAT ARE PRIMARY KEY AS WELL AS FOREIGN KEY - SQL SERVER 2008
SELECT
CU.TABLE_NAME, CU.COLUMN_NAME
FROM INFORMATION_SCHEMA.KEY_COLUMN_USAGE CU
WHERE CU.CONSTRAINT_NAME IN (SELECT CONSTRAINT_NAME FROM INFORMATION_SCHEMA.TABLE_CONSTRAINTS
WHERE CONSTRAINT_TYPE = 'PRIMARY KEY') AND
COLUMN_NAME IN (SELECT COLUMN_NAME FROM INFORMATION_SCHEMA.KEY_COLUMN_USAGE
WHERE TABLE_NAME = CU.TABLE_NAME AND
COLUMN_NAME = CU.COLUMN_NAME AND
CONSTRAINT_NAME IN (SELECT CONSTRAINT_NAME FROM INFORMATION_SCHEMA.TABLE_CONSTRAINTS
WHERE CONSTRAINT_TYPE = 'FOREIGN KEY'))
Source: here

T-SQL for finding Redundant Indexes

Is anyone aware of a T-SQL script that can detect redundant indexes across an entire database? An example of a redundant index in a table would be as follows:
Index 1: 'ColumnA', 'ColumnB', 'ColumnC'
Index 2: 'ColumnA', 'ColumnB'
Ignoring other considerations, such as the width of columns and covering indexes, Index 2 would be redundant.
Thanks.
There are situations where the redundancy doesn't hold. For example, say ColumnC was a huuge field, but you'd sometimes have to retrieve it quickly. Your index 1 would not require a key lookup for:
select ColumnC from YourTable where ColumnnA = 12
On the other hand index 2 is much smaller, so it can be read in memory for queries that require an index scan:
select * from YourTable where ColumnnA like '%hello%'
So they're not really redundant.
If you're not convinced by my above argument, you can find "redundant" indexes like:
;with ind as (
select a.object_id
, a.index_id
, cast(col_list.list as varchar(max)) as list
from (
select distinct object_id
, index_id
from sys.index_columns
) a
cross apply
(
select cast(column_id as varchar(16)) + ',' as [text()]
from sys.index_columns b
where a.object_id = b.object_id
and a.index_id = b.index_id
for xml path(''), type
) col_list (list)
)
select object_name(a.object_id) as TableName
, asi.name as FatherIndex
, bsi.name as RedundantIndex
from ind a
join sys.sysindexes asi
on asi.id = a.object_id
and asi.indid = a.index_id
join ind b
on a.object_id = b.object_id
and a.object_id = b.object_id
and len(a.list) > len(b.list)
and left(a.list, LEN(b.list)) = b.list
join sys.sysindexes bsi
on bsi.id = b.object_id
and bsi.indid = b.index_id
Bring cake for your users in case performance decreases "unexpectedly" :-)
Inspired by Paul Nielsen, I wrote this query to find/distinguish:
Duplicates (ignoring include order)
Redundant (different include columns)
Overlapping (different index columns)
And also record their usage
(One might also want to use is_descending_key, but I don't need it.)
WITH IndexColumns AS
(
SELECT I.object_id AS TableObjectId, OBJECT_SCHEMA_NAME(I.object_id) + '.' + OBJECT_NAME(I.object_id) AS TableName, I.index_id AS IndexId, I.name AS IndexName
, (IndexUsage.user_seeks + IndexUsage.user_scans + IndexUsage.user_lookups) AS IndexUsage
, IndexUsage.user_updates AS IndexUpdates
, (SELECT CASE is_included_column WHEN 1 THEN NULL ELSE column_id END AS [data()]
FROM sys.index_columns AS IndexColumns
WHERE IndexColumns.object_id = I.object_id
AND IndexColumns.index_id = I.index_id
ORDER BY index_column_id, column_id
FOR XML PATH('')
) AS ConcIndexColumnNrs
,(SELECT CASE is_included_column WHEN 1 THEN NULL ELSE COL_NAME(I.object_id, column_id) END AS [data()]
FROM sys.index_columns AS IndexColumns
WHERE IndexColumns.object_id = I.object_id
AND IndexColumns.index_id = I.index_id
ORDER BY index_column_id, column_id
FOR XML PATH('')
) AS ConcIndexColumnNames
,(SELECT CASE is_included_column WHEN 1 THEN column_id ELSE NULL END AS [data()]
FROM sys.index_columns AS IndexColumns
WHERE IndexColumns.object_id = I.object_id
AND IndexColumns.index_id = I.index_id
ORDER BY column_id
FOR XML PATH('')
) AS ConcIncludeColumnNrs
,(SELECT CASE is_included_column WHEN 1 THEN COL_NAME(I.object_id, column_id) ELSE NULL END AS [data()]
FROM sys.index_columns AS IndexColumns
WHERE IndexColumns.object_id = I.object_id
AND IndexColumns.index_id = I.index_id
ORDER BY column_id
FOR XML PATH('')
) AS ConcIncludeColumnNames
FROM sys.indexes AS I
LEFT OUTER JOIN sys.dm_db_index_usage_stats AS IndexUsage
ON IndexUsage.object_id = I.object_id
AND IndexUsage.index_id = I.index_id
AND IndexUsage.Database_id = db_id()
)
SELECT
C1.TableName
, C1.IndexName AS 'Index1'
, C2.IndexName AS 'Index2'
, CASE WHEN (C1.ConcIndexColumnNrs = C2.ConcIndexColumnNrs) AND (C1.ConcIncludeColumnNrs = C2.ConcIncludeColumnNrs) THEN 'Exact duplicate'
WHEN (C1.ConcIndexColumnNrs = C2.ConcIndexColumnNrs) THEN 'Different includes'
ELSE 'Overlapping columns' END
-- , C1.ConcIndexColumnNrs
-- , C2.ConcIndexColumnNrs
, C1.ConcIndexColumnNames
, C2.ConcIndexColumnNames
-- , C1.ConcIncludeColumnNrs
-- , C2.ConcIncludeColumnNrs
, C1.ConcIncludeColumnNames
, C2.ConcIncludeColumnNames
, C1.IndexUsage
, C2.IndexUsage
, C1.IndexUpdates
, C2.IndexUpdates
, 'DROP INDEX ' + C2.IndexName + ' ON ' + C2.TableName AS Drop2
, 'DROP INDEX ' + C1.IndexName + ' ON ' + C1.TableName AS Drop1
FROM IndexColumns AS C1
INNER JOIN IndexColumns AS C2
ON (C1.TableObjectId = C2.TableObjectId)
AND (
-- exact: show lower IndexId as 1
(C1.IndexId < C2.IndexId
AND C1.ConcIndexColumnNrs = C2.ConcIndexColumnNrs
AND C1.ConcIncludeColumnNrs = C2.ConcIncludeColumnNrs)
-- different includes: show longer include as 1
OR (C1.ConcIndexColumnNrs = C2.ConcIndexColumnNrs
AND LEN(C1.ConcIncludeColumnNrs) > LEN(C2.ConcIncludeColumnNrs))
-- overlapping: show longer index as 1
OR (C1.IndexId <> C2.IndexId
AND C1.ConcIndexColumnNrs <> C2.ConcIndexColumnNrs
AND C1.ConcIndexColumnNrs like C2.ConcIndexColumnNrs + ' %')
)
ORDER BY C1.TableName, C1.ConcIndexColumnNrs
I created the following query that gives me a lot of good information to identify duplicate and near-duplicate indexes. It also includes other information like how many pages of memory an index takes, which allows me to give a higher priority to larger indexes. It shows what columns are indexed and what columns are included, so I can see if there are two indexes that are almost identical with only slight variations in the included columns.
WITH IndexSummary AS
(
SELECT DISTINCT sys.objects.name AS [Table Name],
sys.indexes.name AS [Index Name],
SUBSTRING((SELECT ', ' + sys.columns.Name as [text()]
FROM sys.columns
INNER JOIN sys.index_columns
ON sys.index_columns.column_id = sys.columns.column_id
AND sys.index_columns.object_id = sys.columns.object_id
WHERE sys.index_columns.index_id = sys.indexes.index_id
AND sys.index_columns.object_id = sys.indexes.object_id
AND sys.index_columns.is_included_column = 0
ORDER BY sys.columns.name
FOR XML Path('')), 2, 10000) AS [Indexed Column Names],
ISNULL(SUBSTRING((SELECT ', ' + sys.columns.Name as [text()]
FROM sys.columns
INNER JOIN sys.index_columns
ON sys.index_columns.column_id = sys.columns.column_id
AND sys.index_columns.object_id = sys.columns.object_id
WHERE sys.index_columns.index_id = sys.indexes.index_id
AND sys.index_columns.object_id = sys.indexes.object_id
AND sys.index_columns.is_included_column = 1
ORDER BY sys.columns.name
FOR XML Path('')), 2, 10000), '') AS [Included Column Names],
sys.indexes.index_id, sys.indexes.object_id
FROM sys.indexes
INNER JOIN SYS.index_columns
ON sys.indexes.index_id = SYS.index_columns.index_id
AND sys.indexes.object_id = sys.index_columns.object_id
INNER JOIN sys.objects
ON sys.OBJECTS.object_id = SYS.indexES.object_id
WHERE sys.objects.type = 'U'
)
SELECT IndexSummary.[Table Name],
IndexSummary.[Index Name],
IndexSummary.[Indexed Column Names],
IndexSummary.[Included Column Names],
PhysicalStats.page_count as [Page Count],
CONVERT(decimal(18,2), PhysicalStats.page_count * 8 / 1024.0) AS [Size (MB)],
CONVERT(decimal(18,2), PhysicalStats.avg_fragmentation_in_percent) AS [Fragment %]
FROM IndexSummary
INNER JOIN sys.dm_db_index_physical_stats (DB_ID(), NULL, NULL, NULL, NULL)
AS PhysicalStats
ON PhysicalStats.index_id = IndexSummary.index_id
AND PhysicalStats.object_id = IndexSummary.object_id
WHERE (SELECT COUNT(*) as Computed
FROM IndexSummary Summary2
WHERE Summary2.[Table Name] = IndexSummary.[Table Name]
AND Summary2.[Indexed Column Names] = IndexSummary.[Indexed Column Names]) > 1
ORDER BY [Table Name], [Index Name], [Indexed Column Names], [Included Column Names]
Results of the query look like this:
Table Name Index Indexed Cols Included Cols Pages Size (MB) Frag %
My_Table Indx_1 Col1 Col2, Col3 123 0.96 8.94
My_Table Indx_2 Col1 Col2, Col3 123 0.96 8.94
Complete Description
For the complete explanation see Identifying Duplicate or Redundant Indexes in SQL Server.
Try the script below to show Unused Indexes, hope it helps
/****************************************************************
Description: Script to show Unused Indexes using DMVs
****************************************************************/
SELECT TOP 100
o.name AS ObjectName
, i.name AS IndexName
, i.index_id AS IndexID
, dm_ius.user_seeks AS UserSeek
, dm_ius.user_scans AS UserScans
, dm_ius.user_lookups AS UserLookups
, dm_ius.user_updates AS UserUpdates
, p.TableRows
, 'DROP INDEX ' + QUOTENAME(i.name)
+ ' ON ' + QUOTENAME(s.name) + '.' + QUOTENAME(OBJECT_NAME(dm_ius.object_id)) as 'drop statement'
FROM sys.dm_db_index_usage_stats dm_ius
INNER JOIN sys.indexes i ON i.index_id = dm_ius.index_id AND dm_ius.object_id = i.object_id
INNER JOIN sys.objects o on dm_ius.object_id = o.object_id
INNER JOIN sys.schemas s on o.schema_id = s.schema_id
INNER JOIN (SELECT SUM(p.rows) TableRows, p.index_id, p.object_id
FROM sys.partitions p GROUP BY p.index_id, p.object_id) p
ON p.index_id = dm_ius.index_id AND dm_ius.object_id = p.object_id
WHERE OBJECTPROPERTY(dm_ius.object_id,'IsUserTable') = 1
AND dm_ius.database_id = DB_ID()
AND i.type_desc = 'nonclustered'
AND i.is_primary_key = 0
AND i.is_unique_constraint = 0
ORDER BY (dm_ius.user_seeks + dm_ius.user_scans + dm_ius.user_lookups) ASC
GO
I was just reading some MSDN blogs, noticed a script to do this and remembered this question.
I haven't bothered testing it side by side with Andomar's to see if one has any particular benefit over the other.
One amendment I would likely make to both though would be to take into account the size of both indexes when assessing redundancy.
Edit:
Also see Kimberley Tripp's post on Removing duplicate indexes

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