I have a dropdown that only shows the id of a table row.
I like to show multiple values from that table to the user in the dropdown.
Do I need to add an array with columnames in the variabele from the controller or something like that?
Edit:
In function add I've this variable
$addresses = $this->Users->Addresses->find('list', ['limit' => 200]);
In the view
echo $this->Form->input('address_id', ['options' => $addresses]);
I only want to show the values address_id, city, street, zipcode in the dropdown.
Use a virtual field:
in your Addresses entity file you can do
function _getFullName()
{
$ret = $this->city.' '.$this->street.' '.$this->zipcode;
return $ret;
}
and then in your controller you can do
$addresses = $this->Users->Addresses->find(
'list',
['limit' => 200, 'valueField' => 'full_name']
);
The Form::Select() only needs one array for it's values to display. It uses the index to define the value and the the value of the array to display.
What you could do is fetch the needed columns from the table and use concat() to create one string from those two columns which you then put into an array.
Alternatively you could take a look at the displayField() in the Table class which accepts an array. The downside of doing this is when you use $table->find('list'); you'll get something along the lines of Sevvlor;1 which is probably not what you want.
Related
In cakephp, I executed this query to find the id field value of the corresponding username
$count = $this->User->find('all',array('conditions'=>array('User.username' => $n)))
How I will get take the value of a field from this array result to a variable?
I am new to cakephp and any help will be very useful.
Well, after calling find, you will notice that $count will be populated if something was brought from the database. I would change something, though, I would use "first" instead of "all" because you are finding only one record.
You can either use this
//in your controller
$count = $this->User->find('first',
array('conditions'=>array('User.username' => $n)));
//and set the variable to be used in the view in this way
$this->set('yourId', $count['User']['id']);
Then in your view
echo $yourId;
Or, you can also do this
$yourId = $this->User->field('id', array('User.username' => $n));
$this->set(compact('yourId'));
and then in your view
echo $yourId
I have two tables: Ingredients and Customers. The relationship between them is that Customers hasMany Ingredients. By default when doing the cakebake using the console, the only way to change them is by assigning an ingredient to the customer in the Ingredients page. However, I want to have in Customers page a checkbox list of Ingredients that can be assigned. Is it possible to do this? If yes, how?
edit:
What I have done until now is that I add this code to my add.ctp:
echo $this->Form->input('Ingredient',
array('label'=>'',
'type'=>'select',
'multiple'=>'checkbox',
'options'=>$ingredients));
However, it gives me "Undefined variable: ingredients" error when I tried to open the add view.
You want and need a HABTM relationship. Different customers can access and use the same ingredients. Look at the docs here yours would be very similar to different Posts using same Tags.
If you are getting this error:
"Undefined variable: ingredients"
It sounds like you haven't declared this variable in your controller, and set it so that the view can use it. Without knowing your code, you would probably need do do something like this (please note I am guessing what your application structure looks like and have not tested this code).
CustomersController.php
// The controller action for your view
public function view() {
// Get the ID and name of all your ingredients
$ingredients = $this->Ingredient->find('all', array(
'fields' => array('id', 'name'),
'order' => 'name',
'recursive' => -1
));
// We will use this array to store all the HTML select options
$ingredientOptions = array();
// Loop through all the ingredients and add them to the select
// options in a format that is suitable for CakePHP to use in
// the view to build your HTML select menu.
foreach ($ingredients as $i) {
$ingredient = $i['Ingredient'];
$ingredientOptions[$ingredient['id']] = $ingredient['name'];
}
// Make the variable available to the view
$this->set('ingredients', $ingredientOptions);
}
I would like to make a configuration page like this for my CMS
http://img4.hostingpics.net/pics/72087272ok.png
I want this page (admin/settings/index) gets me the various settings (ID 1 to 21) came to my table and in case of change, I can, in this form, do an update
After 3 days of not especially fruitful research I found something. I put in my SettingsController:
admin_index public function () {
if (!empty($this->data)) {
$this->Setting->saveAll($this->request->data['Setting']);
} else {
$this->request->data['Setting'] = Set::combine($this->Setting->find('all'),
'{n}. Setting.id', '{n}. Setting');
}
}
and my view:
<?php
echo $this->Form->create('Setting', array ('class' => 'form-horizontal'));
foreach($this->request->data['Setting'] as $key => $value) {
echo $this->Form->input('Setting.' . $key . '.pair');
echo $this->Form->input('Setting.' . $key . '.id');
}
echo $this->Form->end(array('class' => 'btn btn-primary', 'label' => 'Save',
'value' => 'Update!', 'div' => array ('class' => 'form-actions')));
?>
he is recovering well all my information, I can even update. The trouble is that I do not really know how I can do to get the same result as my first screenshot. He puts everything in the textarea while in some cases I want the checkbox and / or drop-down.
please help me or explain to me how to make a page that retrieves configuration information from my table and allows me to edit without use an address like admin/settings/edit/ID
My table settings is something like this here
http://img4.hostingpics.net/pics/724403settings.png
If you are asking about how to format the output to produce a "settings" page, you will need to do it manually or add some kind of metadata to your table schema, such as "field_type".
Now Cake will automatically generate a checkbox for a boolean or tiny int, for example, but as you have varchars, ints, texts and so on, this won't work for you (pair is presumably varchar or text to allow for the different possible values.
You cannot really automagically generate the outputs you want without telling Cake.
One option would be to add a field_type to the table, so:
key value field
site_name My Site input
site_online 1 checkbox
meta_desc [some text] textarea
and something like
foreach($settings as $setting) {
echo $this->Form->{$setting['field']}($setting['key'],
array('value' => $setting['value']));
}
might do what you are after.
Or if($key=='site_name') // output a textbox
but this is not exactly ideal.
i have existing website.
and i write the new back-end (in cakephp) without changing front-end programm
the discomfort that
db table has field names as
id
news_date
news_title
news_content
is it possiable to do something in cakephp model file (reindentify the field names)
so i can use model in controller as
News.date
News.title
News.content
What you need to do is setup some very basic virtual fields in your news model. Something like this should suit your needs.
public $virtualFields = array(
'title' => 'news_title',
'date' => 'news_date',
'content' => 'news_content'
);
Also do yourself a favour by checking out the other model attributes that could help you out, you'll want to set displayType as new_title I'd imagine.
Is said by Dunhamzz, virtualFields are a good solution until you want to work with these new field-names.
Since I assume your frontend needs to use the old names from the database I would go with the afterFind-callback in your model.
Let's say you've got the model news.php:
# /app/model/news.php
function afterFind($results) {
foreach ($results as $key => $val) {
if (isset($val['News']['title'])) {
$results[$key]['News']['news_title'] = $val['News']['title']);
# unset($results[$key]['News']['title']); //use this if you don't want the "new" fields in your array
}
if (isset($val['News']['date'])) {
$results[$key]['News']['news_date'] = $val['News']['date']);
# unset($results[$key]['News']['date']); //use this if you don't want the "new" fields in your array
}
if (isset($val['News']['content'])) {
$results[$key]['News']['news_content'] = $val['News']['content']);
# unset($results[$key]['News']['content']); //use this if you don't want the "new" fields in your array
}
}
return $results;
}
You need to rename the database-fields to your new wanted value. You then can use these within conditions like every other field.
Only difference is, that you get back an array where all your fields have been renamed to your frontend-fields.
For more information about the available callback-methods have a look here: Callback Methods
I want a function to alter one field, "is_featured" to 1(true) of Event model of given ID, to mark an event as "Featured".
class EventsController extends AppController{
function feature($id){}
}
you can use saveField to do this
for example
$this->Event->id = $id;
$this->Event->saveField('is_featured', true);
You can perform update in one field by two ways:
$this->Model->id=$id;
$this->Model->saveField("fieldName","value");
OR
$this->Model->updateAll(array("fieldName"=>"value"),array("fieldName"=>"condition"));
in second example, first array will update the value in defined field and second array defines the "WHERE" condition
You can also use set() method
$this->Model->read(null, $id);
$this->Model->set(array(
'fieldname' => 'value',
));
$this->Model->save();
In cakephp 3 to update your data:
Include in your Controller:
use Cake\ORM\TableRegistry;
In your action:
$articlesTable = TableRegistry::get('Articles');
$article = $articlesTable->get(12); // Return article with id 12
$article->title = 'CakePHP is THE best PHP framework!';
$articlesTable->save($article);
Source: http://book.cakephp.org/3.0/en/orm/saving-data.html
You can use this technique to update the field(s)
$this->Event->save($this->request->data, true, array('id', 'is_featured'))
If you don’t want the modified field to be automatically updated when saving some data add 'modified' => false to your $data array
If you don’t pass the id, the model cannot set its primary key and will “add” instead of “edit” the field(s)
You can do this easy way
$this->Event->saveField('username', $user); //Where username is Model field name and $user is value
strangely; sometimes I like to resort for plain old sql: one-liner + no overhead there, makes me sure no callbacks/events get involved (beware this may be not what you want!)
$id = (int) $id;
$this->Event->query("UPDATE events SET is_featured=1 WHERE id=$id");