I am running the following command in cmd for which I am able to get the log successfully.
cd C:\Users\sriram\AppData\Local\Temp\license1.1.4
C:\Users\sriram\AppData\Local\Temp\license1.1.4>lsmon.exe testprovilic.muc.company> C:\Users\sriram\AppData\Local\Temp\license1.1.4\usage.log
Above command will generate the logs in the usage log file. But I created a batch file as below for which it is giving me an error testprovilic.muc.company not found
#ECHO off
SET variable=C:\Users\s.d.vaidyanathan\AppData\Local\Temp\usage.log
START "C:\Users\s.d.vaidyanathan\AppData\Local\Temp\license1.1.4"lsmon.exe testprovilic.muc.company> "%variable%"
Could you please help me solve this issue.
Thanks and Regards,
Sriram
You need to add the "cd C:\Users\sriram\AppData\Local\Temp\license1.1.4" to the batch file. Or use the full path to the file like:
C:\Users\sriram\AppData\Local\Temp\license1.1.4\testprovilic.muc.company
So you would have ..
#ECHO off
cd C:\Users\sriram\AppData\Local\Temp\license1.1.4
SET variable=C:\Users\s.d.vaidyanathan\AppData\Local\Temp\usage.log
START "C:\Users\s.d.vaidyanathan\AppData\Local\Temp\license1.1.4"lsmon.exe testprovilic.muc.company> "%variable%"
or you could
#ECHO off
SET variable=C:\Users\s.d.vaidyanathan\AppData\Local\Temp\usage.log
START "C:\Users\s.d.vaidyanathan\AppData\Local\Temp\license1.1.4"lsmon.exe C:\Users\sriram\AppData\Local\Temp\license1.1.4\testprovilic.muc.company> "%variable%"
This doesn't work:
"C:\Users\s.d.vaidyanathan\AppData\Local\Temp\license1.1.4"lsmon.exe
The whole path needs to be in quotes and there needs to be a backslash after the last folder name.
Change it to this:
"C:\Users\s.d.vaidyanathan\AppData\Local\Temp\license1.1.4\lsmon.exe"
Open a command prompt window, type set and press key RETURN or ENTER to run this command. You get displayed all predefined environment variables with their current values. You can see TEMP, USERPROFILE and USERNAME.
Windows command line has a help. The command to get help is help, yes really. Try it out! You need help on command CD, enter in command prompt window help cd or alternatively cd /?. You need help on command SET and START, run help set or set /? and help start or start /?. All internal commands of cmd.exe and nearly all console applications support the parameter /? and output 1 or more help pages on running the command with this parameter.
You need a better overview of standard Windows commands? See Microsoft's command-line reference and SS64's command line reference.
I assume that sriram is your user account and s.d.vaidyanathan is the user account of someone else. By default a standard user has no permissions to access folders and files in a different user's profile than the own profile since Windows Vista. That means, you logged in as sriram can't access the files and folders of C:\Users\s.d.vaidyanathan because of missing permissions to do so. It would be necessary to use command Runas to run the batch file with account s.d.vaidyanathan.
#echo off
rem Execute lsmon.exe from license1.1.4 in my folder for temporary
rem files and folders and write the log file also into this folder.
"%TEMP%\license1.1.4\lsmon.exe" testprovilic.muc.company >"%TEMP%\license1.1.4\usage.log"
Note: Double quotes must be used around path AND file name. Just double quoting parts of a file name with path may or may not work depending on error correction and how the application is written. For details see answer on set environment variables with spaces.
See also the Microsoft article Using command redirection operators.
And regarding right usage of command START not really needed here see for example answer on How to call a batch file in the parent folder of current batch file?
Related
I am programming a DOS-like shell, but it starts in %UserProfile% instead of %UserProfile%\Desktop\Coding projects\CM-DOS.
The actual shell, kernel.bat's code is:
#echo off
type INFO.txt
pause
INFO.txt is in the same directory as kernel.bat (CM-DOS).
It says:
CM-DOS is a FREE, open-source Disk Operating System by Tristan
Carpenter. If anyone trys to sell you a paid copy of CM-DOS, send me
an e-mail at tristan4#mail.com. Please use this DOS shell kindly. This
shell is licensed under the MIT License. Do whatever you want with the
shell, create closed-source versions, fork it, I don't really care.
The script tries to type "%UserProfile%\INFO.txt", which doesn't exist.
How can I start the file in it's actual directory, instead of %UserProfile%.
If you run the script (clicking or navigating (cd <folder>) and .\kernel.bat) and the current folder isn't, well, the current folder, then something is off with either your console setup or there is an additional code executed in the background. Try to echo %CD% to see what the folder is and check the prompt string usually in the shape of:
C:\Users\Username>
which is the default path if you run cmd.exe as a user or:
C:\Windows\System32>
if you run as an Administrator / user with elevated privileges.
This can be changed though with regedit.exe.
However what you might be seeing is that you run your code (kernel.bat or however you name it) which might display the first path before execution or after the last command you might be dropped into a shell. Neither should be the case according to the code, yet it can happen if you started cmd.exe, then wrote cmd.exe (i.e. spawned another shell) and then ran your script.
What I suspect is that you're running the code like this:
C:\Users\You> .\Desktop\Coding projects\CM-DOS\kernel.bat
in which case the %CD% would be C:\Users\You and type command would be looking for C:\Users\You\INFO.txt. A better solution is simply creating a variable for the folder where your script is located - which is provided automatically, it's %~dp0 (echo %~dp0) and with that you can do:
echo off
type "%~dp0INFO.txt"
pause
to make it location independent, or better said, to access relatively according to the kernel.bat (the current script)'s location.
You can add cd %CD% and %CD% stands for the current direction. the final code would be
#echo off
cd %CD%
type INFO.txt
pause
I'm setting up an external hard drive with portable apps, and there are some CLI tools that I'd like to easily access.
I've done it before but I forgot how; basically, I have a file which sets the PATH variable for all the required CLI programs, and then allows me to use the command prompt normally.
How do I do this without having to run the file from another command prompt, but by double clicking the Batch file?
If your command line tools are in a folder named CLiTools next to the batch-file, then you could have 2 lines as the batch-file content.
#set "path=%path%;%~dp0CLiTools"
#cmd
You can double click the batch-file, it will open cmd with the modified setting of %path% and you can enter commands as you would normally do. If you have i.e. xyz.exe in the CLiTools folder, then you can type xyz at the current command prompt and will be recognized as a command.
The changed environment applies to the current child cmd session that inherited the environment.
%~dp0 is the drive and path of argument 0 which is the drive and path to the batch-file in this case.
I'm writing a script to automate software installation and optimization using batch files. It needs administrator privileges.
When admin rights are given to cmd, I had to switch from "%cd%\program.exe" to "%0\..\program.exe". However, after doing that, I can't get a file to open if it is in a directory with spaces.
Subsequently, I removed the quotation marks at the beginning like this:
%0\..\program.exe"
This caused the directory problem to go away but now Programs with spaces won't open and using xcopy will give me a parse error.
I need it to open both files with spaces and files inside of directories with spaces.
Please help me solve this problem. Thanks in advance.
%0 should already be doublequoted, but is the drive path name and extension of the running batch-file. You really want to use this:
"%~dp0…\program.exe"
… represents an actual directory sequence, not a relative path
To get a better idea of what is going on open a Command Prompt window, enter Call /? and read its output.
Note: the p in %~dp0 already has a trailing backslash, so you don't need to append one yourself.
I want to create a batch file to launch my executable file after it has made some changes to itself.
My batch file is:
START /D "C:\Users\me\AppData\Roaming\Test\Test.exe"
When I run it though I just get a brief console flash and Test.exe doesn't start up.
I've verified the EXE is there in the directory.
I've launched the exe manually to verify it is working as well.
My batch file resides in
C:\Users\admin\AppData\Roaming\run.bat"
There are two issues:
The /D option solely defines the starting or working directory, but not the program to execute.
The start command considers the first quoted argument as the title of the new window. To avoid confusion with other arguments, always provide a window title (that may also be empty).
There are two solutions, which are actually not exactly equivalent:
Remove the /D option, so the current working directory is used:
start "" "C:\Users\me\AppData\Roaming\Test\Test.exe"
Keep the /D option and explicitly provide the new working directory to be used:
start "" /D "C:\Users\me\AppData\Roaming\Test" "Test.exe"
try changing to this
start /d "C:\Users\me\AppData\Roaming\Test" Test.exe
You will see the console flash and your program should startup.
Update
Thanks for #SomethingDark 's suggestion to use the following code.
start "" C:\Users\me\AppData\Roaming\Test\Test.exe
However, the above code will not work if your filename contains space.
Try with the following command.Add it to your batch script.Notice that you have to add double quotes after start keyword if there is/are whitespaces in the path string.
start "" "C:\Users\me\AppData\Roaming\Test\Test.exe"
Enclose any directory names which are longer than one-word into quotation marks. So the following path:
start C:\Program Files\MySQL\MySQL Workbench 8.0 CE\MySQL.exe
Should become something like this:
start C:\"Program Files"\MySQL\"MySQL Workbench 8.0 CE"\MySQL.exe
I'm writing a .bat file to handle some script generation automatically so I don't have to type in half a dozen command arguments each time I want to run it.
I have to run a vb script from the batch file
#call ..\Database\scripts\runscriptupdates.vbs
However the script will only run if using the the command prompt from
C:\Windows\SysWOW64\cmd.exe
By default the bat file uses the cmd.exe in system32
C:\Windows\System32\cmd.exe
Is there a way to force the batch file to use this cmd.exe to run the vbs file? I've been trawling the web for about an hour now and haven't found anything which helps (so far).
I've tried running the syswow64 with "start ..." however it doesn't seem to take the arguments after it.
Many thanks, Neil
You can try:
%windir%\SysWoW64\cmd.exe /c mybatch.bat
This will run the batch itself from a 32-bit command prompt. Thus, the call to your vbs will also be coming from a 32-bit command prompt.
I also had this problem, and I found the way to solve it.
You just need to change System Variables.
Go to Control Panel » System » Advanced System Settings » Environment Variables.
Find the variable ComSpec, then just click Edit... and change the path to "C:\Windows\SysWow64\cmd.exe"
Try typing this one line in your batch file.
%windir%\SysWoW64\cmd.exe /c ["]cscript [script name] [host options] [script arguments]["]
Where:
script name is the name of the script file, including the file name extension and any necessary path information.
host options are the command-line switches that enable or disable various Windows Script Host features. Host options are always preceded by two slashes (//).
script arguments are the command-line switches that are passed to the script. Script arguments are always preceded by one slash (/).
Example:
%windir%\SysWoW64\cmd.exe /c "cscript VoltageDrop.vbs /"Campbell.sin" "L08""
Note: In this line I do not pass any host options. This command will execute the string,
cscript VoltageDrop.vbs /"Campbell.sin" "L08"
as a command in the 32-bit command prompt.