I'm inserting an image in my template file as
<?php echo $this->Html->image('profile_picture.png', array('alt'=>'frame partner avatar'), array('id'=>'framePartnerAvatar')); ?>
Now I'm trying to give style to this image by using the id mentioned, but on checking through Firebug only source and alternate name is visible. Image id is not coming there.
You have to use the correct syntax:
<?php echo $this->Html->image(
'profile_picture.png',
array(
'alt'=>'frame partner avatar',
'id'=>'framePartnerAvatar'
)); ?>
See HtmlHelper::image()
According to the documentation the method used to create images requires two parameters. The first one being the source link and the second one being the options parameter
$this->Html->image('cake_logo.png', ['alt' => 'CakePHP']);
Your code should be something along the lines of this
$this->Html->image('profile_picture.png', array(
'alt'=>'frame partner avatar',
'id'=>'framePartnerAvatar')
);
$thumb_img = $this->Html->image('yourimage.png',array('alt'=>'yoursite.com','id'=>'yourId'));
Please ensure that all HTML attributes such as alt, id, class etc needs to be written within a single array, and not multiple arrays.
<?php echo $this->Html->image('profile_picture.png', array(
'alt'=>'frame partner avatar',
'id'=>'framePartnerAvatar'
)
); ?>
This will certainly generate the following HTML:
<img src="/img/profile_picture.png" alt='frame partner avatar' id='framePartnerAvatar' />
Peace! xD
Related
I'm trying to over-ride the default layout template of Categories list within the Module
mod_articles_categories
The reason for that is to be able to display the images associated with each category which is set in the params of each category.
The code that I found to show those images is
json_decode($item->params)->image
But it's not working, any ideas?
The "official" way would be to use something like this within the foreach ($list as $item) :
<?php
$params = new JRegistry();
$params->loadString($item->params);
$image = $params->get('image');
if ($image) : ?>
<img src="<?php echo $image; ?>" />
<?php endif; ?>
But you code should work as well. At least it does when I tested it locally. The code I posted would allow you to set a default value for the param. Like $params->get('image', 'foo/bar.png');. Other than that it does about the same.
My Goal:
Reuse of a contact form to be related to several different entities I call "Parents" ie Group has contact information, Member has contact info etc....
The way I tried doing it was:
1. Creating a view file for contact, named "form.ctp" which doesn`t create a new form, nor submits, just echo's the contact's fields.
2. Calling this file using requestAction
My Problem:
The form's _Token get crumbled.
Parent add.ctp example
<?php echo $this->Form->create('Group');?>
<fieldset>
echo $this->Form->input($field_prefix.'contact_id',array('type'=>'hidden'));
<?php echo $this->requestAction(array('controller' => 'contacts', 'action' => 'form'), array('named' => array('index'=>'0','parent'=>'Group',
'fields'=>array(
'email'=>array('value'=>'xx#yy.com','hidden'=>1)
))));
inside the form.ctp I have:
//Associated Model
echo $this->Form->input('Contact.0.city',array('type'=>'hidden'));
echo $this->Form->input('Contact.0.postcode');
echo $this->Form->input('Contact.0.phone');
echo $this->Form->input('Contact.0.cellphone');
echo $this->Form->input('Contact.0.email',array('value'=>""));
echo $this->Form->input('Contact.0.id',array('type'=>'hidden'));
?>
Looking at the HTML source code that is generated, I see that whether I use the request action or just copy the contect of the form.ctp into the "Parent's" add file, I get the same HTML result.
HOWEVER!!! when I use the form.ctp Action Request, I get the blackhole, the tokens are being messed up!!!
Any Ideas?
Thanks in advance
Orly
If your problem is solely reusing a form, you can use the form as a Element, and then you could call it multiple times, substituting in the exact values you need.
As for SecurityComponent, I would recommend (at least as a temporary fix) disabling SecurityComponent for that specific action by using $this->Security->unlockedActions(); in your controller's beforeFilter()
created a view function and any time i click the link to view a template, the url at the top of the page is correct but it spits out the same list of fields in the database.
the fields are
accounts - id, company name, abn
template - id, name, description, account_id
field - id, name, field type, template_id
function view(){
$accounts=$this->User->AccountsUser->find('list',
array('fields'=>array('id', 'account_id'),
'conditions' =>array('user_id' =>
$this->Auth->user('id'))));
$templates=$this->Template->find('first',
array('conditions' => array(
'Template.account_id' => $accounts)));
$fields=$this->Field->find('all',
array('conditions' => array(
'Field.template_id' => Set::extract('/Template/id', $templates))));
$this->set('template', $templates);
$this->set('account', $accounts);
$this->set('field', $fields);
}
here is the view
<div class = "conlinks">
</br></br></br></br></br><h2>Here is your template fields</h2></br>
<?php foreach($field as $fields): ?>
<tr>
<td align='center'><?php echo $fields['Field']['name']; ?>
</tr></br>
<?php endforeach; ?>
</div>
so the problem is its grabbing the exact same list of fields, not the correct template_id when it prints out the fields
You should be able to debug this for yourself. Just narrow the bug down step by step.
For starters, in your view function, do a print_r on the following variables, and make sure each one contains a logical result:
$accounts
$templates
$fields
If you find unexpected results there, I'd be looking at the parameters you pass into each of your finds, and making sure they're OK. You're passing in $accounts as an array to your find condition - make sure it matches the format that cake expects. Do the same for Set::extract('/Template/id', $templates).
Also look at the SQL that Cake is producing.
If you're not already using it, I'd highly recommend installing Cake's Debug Kit Toolbar - https://github.com/cakephp/debug_kit/ because it makes debugging variables and SQL much easier.
If you do the above steps and can't solve your problem, you should at least be able to narrow it down to a line or two of code. Update your answer to show what line or two is causing the problem, and include print_r's of some of the variables you're working with. That should help others on StackOverflow to give you a specific answer.
Hope that helps!
the issue was I wasn't getting the parameters when click the link
function view($name){
$fields = $this->Template->Field->find('list',array(
'fields'=> array('name'),
'conditions' => array(
'template_id'=> $name)));
$this->set('field', $fields);
}
and the view
<div class = "conlinks">
</br><h2>Here is your template fields</h2>
<?php foreach($field as $name): ?>
<tr>
<td align='center'>
<?php echo $name; ?>
</tr></br>
<?php endforeach; ?>
</br>
<?php
echo $this->Html->link('Back', '/templates/view', array('class' => 'button'));?>
</div>
I've started a project in CakePHP. I have no experience of it, most of my experience is with Symfony2.
Right now, I have built a view file, a controller, and a model for use with this project and it's database. In one controller I want to pass one record from the database to the view for use on the homepage. However, I'm unable to pass the record as I get this error:
Notice (8): Undefined variable: content [APP\View\Contents\home.ctp,
line 42]
Here is my controller code:
function home() {
$content = $this->Content->query("SELECT title, content FROM content WHERE id = 1;");
$this->set('pagecontent',$content);
}
And here is the code I'm using to display the data in the view file:
<?php $content['content']; ?>
What have I missed?
EDIT:
I have changed the <?php $content['content']; ?> to <?php echo $pagecontent['Content']['content']; ?> inline with the changes outlined in the answer from Ross. However, there is now this error:
Notice (8): Undefined index: Content [APP\View\Contents\home.ctp, line
43]
I have used the <?php echo debug($this->viewVars); ?> and this is the output from that:
app\View\Contents\home.ctp (line 42) Array (
[pagecontent] => Array
(
[0] => Array
(
[content] => Array
(
[title] => <h1>This is a title</h1>
[content] => <p>this is some test text</p>
)
)
)
)
$this->set('pagecontent',$content); - this is where you are setting view variables.
You are trying to access a variable called $content, when in fact it is stored as $pagecontent.
Also based on Cake conventions, the key content should actually be Content, so your output should probably be:
<h1><?php echo $pagecontent['Content']['title']; ?></h1>
<div class="page-content">
<?php echo $pagecontent['Content']['content']; ?>
</div>
You can always do debug($this->viewVars); to see exactly what you have access to.
Seeing the output helps; the error is due to how cake is returning the data.
This is likely due to you using query() rather than find() or read(). (also explains why your content key is lowercase - query() uses the table name, rather than the model name.
Try:
$content = $this->Content->find('first',
array('fields' => array('title', 'content'),
'conditions' => array('Content.id' => 1)
)
);
$this->set('pagecontent', $content);
// view
echo $pagecontent['Content']['title'];
echo $pagecontent['Content']['content'];
should now work.
The alternative is to just access the data through the array index:
echo $pagecontent[0]['content']['title']
which isn't as "cake" like.
to expand = query() returns data in a different structure than using find or read. There's other ways you can do this too.
$this->Content->id = 1;
$this->set('pagecontent', $this->Content->read(array('title', 'content')));
should also be valid.
I am very new in cake php, i want to know how to create form in cake php,please describe,when we go to create a form then what i have to do,like create model and controller everything
In the view file, something like this would work:
<?php
echo $this->Form->create();
echo $this->Form->input('firstname', array('label' => 'Enter your first name:'));
echo $this->Form->input('email', array('label' => 'Enter your email address:'));
echo $this->Form->input('password', array('label' => 'Enter your password:'));
echo $this->Form->end('Save');
?>
In your controller:
if($this->request->is('post')){
$this->User->save( $this->request->data );
}
You can apply some sort of validation in your model, look in the documentation for that.
Best option to learn about cakephp is it's own doc book
But I'm providing you some basic code to create form :
$this->Form->create('ModelName');
$this->Form->input('ModelName.fieldname', array('type'=>'text', 'label'=>'Modified-Name'));
$this->Form->end(__('Submit'));
Here array('type'=>'text'...): type shows which type of input field you want.
(...'label'=>'Modified-Name'): By default it shows field text as fieldname but by using 'label' you can modify your field text.
$this->form->create('controlpage',
array(
'action'=>'controll',
'class'=>'class',
'enctype' => 'multipart/form-data',
'onsubmit'=>'return valid()'
));
Block quote
Create form in html save it as ctp
Block quote
And call it in view. enter code hereUse cake php book to read further.