How to get the difference between documents - batch-file

Everyday, a document is created automatically named articles.txt.
I have to make several changes to the document.
After the changes made the document is named articles_Final + date.txt
As example : articles_Final_2016_01_07.txt
The documents are then moved to a directory ". \ HISTO \ FINAL".
I have to compare the two last document created and to write the difference in a new document result.txt
I show you my code for findind the two last documents
#echo off & cls
SETLOCAL EnableDelayedExpansion
set "Dossier=.\HISTO\Final"
set /a "n=0, limit=2"
for /F "delims=" %%a in ('dir /B /A-D /O-D /T:W "%Dossier%\*.*"') do (
echo "%%a"
2>nul set /a "n+=1, 1/(limit-n)"||goto :break
)
:break
pause
exit
And le code who compare the two document
Here, I write the name of them but i would like to find the way to write automaticly the result of my first code
findstr /v /g:articles_Final_2016_01_04.txt articles_Final_2016_02_04.txt >result.txt

#echo off
cls
SETLOCAL EnableDelayedExpansion
set "Dossier=.\HISTO\Final"
set /a "n=0, limit=2"
for /F "delims=" %%a in ('dir /B /A-D /O-D /T:W "%Dossier%\*.*"') do (
echo "%%a"
set "file[!n!]=%%a"
2>nul set /a "n+=1, 1/(limit-n)"||goto :break
)
:break
set file
echo findstr /v /g:%Dossier%\%file[0]% %Dossier%\%file[1]%
pause
exit
(untried)
The findstr command will just be echoed - you'd need to check it and redirect the output.
the set file command is simply a way of displaying all variables that start with file.

Here, the final solution
#echo off
cls
SETLOCAL EnableDelayedExpansion
set "Dossier=.\HISTO\FINAL"
set /a "n=0, limit=2"
for /F "delims=" %%a in ('dir /B /A-D /O-D /T:W "%Dossier%\*.*"') do (
echo "%%a"
set "file[!n!]=%%a"
2>nul set /a "n+=1, 1/(limit-n)"||goto :break
)
:break
set file
findstr /v /g:%Dossier%\%file[0]% %Dossier%\%file[1]% >>difference.txt
::fc /L %Dossier%\%file[0]% %Dossier%\%file[1]% >>difference.txt
pause
exit

Related

Replacing text in a file name

What I am trying to do is replace part of a file name with my computer name.
#echo off
set host=%COMPUTERNAME%
set host=%host:~4, -2%
for /f "delims=" %%a in ('dir /a:-d /o:n /b') do call :next "%%a"
pause
GOTO:EOF
:next
set "newname=%~nx1"
set "newname=%newname:XXXX=zzzz%"
echo ren %1 "%newname%
When I run the above, it replaces the XXXX's with zzzz's
When I change set "newname=%newname:XXXX=zzzz%" to set "newname=%newname:XXXX=%host%"it just deletes the X's.
What happens if you use delayed expansion?
#Echo Off
SetLocal EnableDelayedExpansion
Set "Host=%COMPUTERNAME:~4,2%"
For /F "Delims=" %%A In ('Dir /B/A-D/ON') Do (Set "NewName=%%~nA"
Echo Ren "%%~A" "!NewName:XXXX=%Host%!%%~xA"
Pause
GoTo :EOF

Opening a random folder from a set directory

How can I create a batch script that opens a random folder within a specific directory? This code here prints out a randomly chosen file(I need it to open the folder, not the file) but I could not figure out how to open it.
#Echo Off
:Start
set directory="D:\Movies"
set count=0
for /f %%f in ('dir "%directory%" /b /s') do set /a count+=1
set /a randN=%random% %% %count% +1
set listN=0
for /f "tokens=1* delims=:" %%I in ('dir "%directory%" /a-d /b /s^| findstr /n /r . ^| findstr /b "%randN%"') do set filename=%%J
:Found
echo %filename%
pause
goto Start
I suddenly realised what I was doing wrong and solved the problem. Here is the final and working code:
#Echo Off
:Start
set directory="D:\Film"
set count=0
for /f %%f in ('dir "%directory%" /ad /b /s') do set /a count+=1
set /a randN=%random% %% %count% +1
set listN=0
for /f "tokens=1* delims=:" %%I in ('dir "%directory%" /ad /b /s^| findstr /n /r . ^| findstr /b "%randN%"') do set filename=%%J
:Found
%SystemRoot%\explorer.exe %filename%
exit /b
goto Start
You really shouldn't need to increment a count and use findstr for such a task; just assigning and sorting a random number should do:
#Echo Off
Set "source=D:\Film"
SetLocal EnableDelayedExpansion
For /D %%A In ("%source%\*") Do Set "$[!RANDOM!]=%%A"
For /F "Tokens=1* Delims==" %%A In ('"Set $[ 2>Nul|Sort"'
) Do Set "target=%%B" & GoTo Found
Exit /B
:Found
Explorer "%target%"
If you wanted a recursive directory search then change line 5 to:
For /D /R "%source%" %%A In (*) Do Set "$[!RANDOM!]=%%A"

Command line counter not incrementing

Hi I have a batch script to move x amount of files from one folder to another. The counter that count the files moved is not incrementing. The script is as follows
SETLOCAL ENABLEEXTENSIONS
SETLOCAL ENABLEDELAYEDEXPANSION
echo on
set DataMax=50
set Counter=1
set SrcMax=50
set DataLoc=Destination Folder
Set HoldLoc=Source Folder
set count=0
FOR /F %%a in ('DIR /B %DataLoc%\*.pst') do set /A count=count+1
if %count% GEQ %DataMax% (Goto Exit) else (GOTO FMove)
:FMove
Echo Gather Top 50 files
FOR /F "TOKENS=*" %%a IN ('dir /A-D /O-D /B %HoldLoc%\*.pst') DO (
if %Counter% LEQ %SrcMax% (
MOVE /y %HoldLoc%\%%a %DataLoc%\
SET /A Counter += 1
)
)
goto Exit
:Exit
exit
The Set /A Counter += 1 does not seem to work. Thanks in Advance for any assistance.
As you already have enabled delayed expansion try like:
FOR /F "TOKENS=*" %%a IN ('dir /A-D /O-D /B %HoldLoc%\*.pst') DO (
if !Counter! LEQ %SrcMax% (
MOVE /y %HoldLoc%\%%a %DataLoc%\
SET /A Counter=Counter+1
)
)
npockmaka has shown how to get your code to work under normal circumstances by using delayed expansion. However, it will fail if any files names contain the ! character (unlikely, but it could happen)
It is possible to make the code work without delayed expansion by intentionally dividing by zero when the maximum count is exceeded. The error message is hidden by redirecting to nul, and the || operator detects the error and conditionally executes the EXIT command.
I also streamlined the first loop to use FIND to quickly get the count, instead of iterating each file.
#echo off
setlocal
set /a count=0, SrcMax=DataMax=50
set "DataLoc=Destination Folder"
set "HoldLoc=Source Folder"
for /f %%N in (
'dir /b "%DataLoc%\*.pst"^|find /c /v ""'
) do if %%N geq %DataMax% exit /b
echo Gather Top 50 files
for /f "eol=: delims=" %%A in (
'dir /a-d /o-d /b "%HoldLoc%\*.pst"'
) do (
set /a "1/(SrcMax-count), count+=1" 2>nul || exit /b
move /y "%HoldLoc%\%%B" "%DataLoc%\"
)
Another option is to number each file via FINDSTR /N, and let FOR /F parse out the number and file name.
#echo off
setlocal
set /a SrcMax=DataMax=50
set "DataLoc=Destination Folder"
set "HoldLoc=Source Folder"
for /f %%N in (
'dir /b "%DataLoc%\*.pst"^|find /c /v ""'
) do if %%N geq %DataMax% exit /b
echo Gather Top 50 files
for /f "tokens=1* delims=:" %%A in (
'dir /a-d /o-d /b "%HoldLoc%\*.pst"^|findstr /n "^"'
) do (
if %%A gtr %SrcMax% exit /b
move /y "%HoldLoc%\%%B" "%DataLoc%"
)
There is one thing that concerns me in your logic.
If you already have 50 files in your destination, then you exit without doing anything. If you do not yet have 50 files, then you move up to 50 files from the source to the destination. If there are 49 files in the destination at the start, then there is the potential to end up with 99 files in the destination, assuming none of the moved file names match the existing files in the destination.

command prompt help, show specific files

Need your help
I need create a batch file (command prompt) to
⁃ Show a list of folders and sub folders
⁃ within them are exe files
⁃ Only show the 2 most up to date exe files
⁃ display specific folders not all
And export information in a txt file
I'm using XP if that helps
update
I have the below commands
first one works and orders by most recent file, but doesn't give me time and date
second shows time and date but doesn't order by most recent
#ECHO OFF
setlocal EnableDelayedExpansion
set j=0
Echo Test
echo\
FOR /f "delims=" %%i IN ('dir C:\test\ /o-n-d /b') DO (
echo %%i
set /A j=j+1
if !j! geq 2 (
goto :end1
)
)
:end1
#ECHO OFF
setlocal EnableDelayedExpansion
set j=0
echo\
Echo Test
echo\
FOR /f "delims=" %%i IN ('forfiles /p C:\testmove /s /m *.* /C "cmd /c echo #file #fdate #ftime" ') DO (
echo %%i
set /A j=j+1
if !j! geq 2 (
goto :end2
)
)
:end2
pause
#ECHO OFF
SETLOCAL enabledelayedexpansion
SET "sourcedir=U:\sourcedir"
SET "lastdir="
(
FOR /f "delims=" %%a IN (
'dir /s /b /a-d "%sourcedir%\*.exe" '
) DO (
IF "%%~dpa" neq "!lastdir!" (
SET "lastdir=%%~dpa"
SET /a count=0
FOR /f "delims=" %%i IN ('dir /s /b /a-d /o:d "%%~dpa\*.exe"') DO IF !count! lss 2 (
SET /a count+=1
ECHO %%~ti %%~fi
)
)
)
)>newfile.txt
GOTO :EOF
Produces newfile.txt. You would need to set your required directory name in sourcedir. I showed the data as date/time fullfilename because fullfilename is of variable-length whereas date and time are fixed. Might have been easier if you'd shown us the format you expect - saves guesswork and revisions.
To show the two most recently modified files, change .../b /a-d /o:d "%%~... to .../b /a-d /o:-d "%%~... (note - between the o: and d)
Uses Robocopy to show the two latest modified .exe files in the current folder tree
It also displays the UTC date and time of the two files.
#echo off
setlocal enabledelayedexpansion
set "folder=%cd%"
set c=0
for /f "tokens=1,2,*" %%a in (
'robocopy "%folder%" "%folder%" "*.exe" /s /is /nocopy /nc /ns /ts /fp /np /ndl /njh /njs /xjd /r:0 /w:0 /l ^| sort /r '
) do echo "%%a %%b" - "%%c" & set /a c+=1 & if !c! EQU 2 goto :done
:done
pause

Batch File - Recursively check folders and move files

I am trying to create a windows batch file that will scan a folder with many sub folders. Each sub folder can contain many files. I need the script to check if a sub folder contains over a certain number of files, and if it does move half of the files to a new folder with the same name but with a number at the end.
Example:
Main folder
-Subfolderone
-Subfoldertwo
-Subfolderthree
If Subfoldertwo contains over a certain number of files, lets say 1000, then half of the files within Subfoldertwo will be moved to Subfoldertwo(2), and so on for each sub folder.
Main folder
-Subfolderone
-Subfoldertwo
-Subfoldertwo(2)
-Subfolderthree
Any help would be much appreciated. Thank you.
#ECHO OFF
SETLOCAL
SET "sourcedir=c:\sourcedir"
SET limit=5
FOR /f "delims=" %%a IN ('dir /b /s /ad "%sourcedir%\*"') DO (
SET /a newnum=2
FOR /f %%c IN ('dir /b/a-d "%%~a" 2^>nul ^|find /c /v ""') DO IF %%c gtr %limit% CALL :process "%%a"
)
)
GOTO :EOF
:process
IF EXIST "%~1(%newnum%)\" SET /a newnum+=1&GOTO process
ECHO MD "%~1(%newnum%)"
FOR /f "skip=%limit%delims=" %%m IN ('dir /b /a-d "%~1"') DO ECHO MOVE "%~1\%%m" "%~1(%newnum%)\"
GOTO :eof
Simple enough. I've set the sourcedir to a constant for my testing and the limit to 5 for the same reason.
First build a list of the original diretory tree, then count the files in each directory. If that count is greater than the limit, process the directory.
In process, first find whether the proposed new directory already exists. If it does, keep incrementing the number 'til it doesn't.
Then list the filenames (only) from the original full-directoryname, skipping the first %limit% and for the remainder, move them to the new directoryname.
The required commands are merely ECHOed for testing purposes. After you've verified that the commands are correct, change ECHO MD to MD to actually create the directories. Append 2>nul to suppress error messages (eg. when the directory already exists)
AND change ECHO MOVE to MOVE to actually move the files. Append >nul to suppress report messages (eg. 1 file moved)
Edit : revised for 'move half the files'
#ECHO OFF
SETLOCAL
SET "sourcedir=c:\sourcedir"
SET limit=5
FOR /f "delims=" %%a IN ('dir /b /s /ad "%sourcedir%\*"') DO (
SET /a newnum=2
FOR /f %%c IN ('dir /b/a-d "%%~a" 2^>nul ^|find /c /v ""') DO IF %%c gtr %limit% SET /a nmove=%%c / 2&CALL :process "%%a"
)
)
GOTO :EOF
:process
IF EXIST "%~1(%newnum%)\" SET /a newnum+=1&GOTO process
ECHO MD "%~1(%newnum%)"
FOR /f "skip=%nmove%delims=" %%m IN ('dir /b /a-d "%~1"') DO ECHO MOVE "%~1\%%m" "%~1(%newnum%)\"
GOTO :eof
(simply calculate half of the count into nmove then skip that number instead)
you might test this:
#ECHO OFF &SETLOCAL
set "StartFolder=X:\Main folder"
set /a MaxFiles=1000
cd /d "%StartFolder%"
:NewFolderCreated
set "NewFolderFlag="
for /f "delims=" %%a in ('dir /b /ad /on') do call:process "%StartFolder%\%%~a"
if defined NewFolderFlag (goto:NewFolderCreated) else goto:eof
:process
SETLOCAL
cd "%~1"
for /f %%b in ('dir /b /a-d 2^>nul^|find /c /v ""') do set /a FileCount=%%b
if %FileCount% leq %MaxFiles% exit /b
set /a MoveCount=FileCount-MaxFiles
set "CurrentFolder=%~n1"
set "NextPath=%StartFolder%\%CurrentFolder%(2)%~X1"
echo("%CurrentFolder%"|findstr /re ".*([0-9][0-9]*)\"^">nul||goto:moving
set "BasePath=%CurrentFolder:~0,-1%"
:loop
if not "%BasePath:~-1%"=="(" set "FolderNo=%BasePath:~-1%%FolderNo%"&set "BasePath=%BasePath:~0,-1%"&goto:loop
set /a FolderNo+=1
set "NextPath=%StartFolder%\%BasePath%%FolderNo%)%~X1"
:moving
echo(Moving %MoveCount% files from "%~1" to "%NextPath%".
md "%NextPath%" 2>nul &&set "NewFolderFlag=true"
for /f "skip=%MaxFiles%delims=" %%b in ('dir /b /a-d /o-n') do move "%~1\%%~b" "%NextPath%" >nul
endlocal &set "NewFolderFlag=%NewFolderFlag%"
exit /b

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