Split string from file txt - c

Question

The C program must split the string when it finds ! or ? or .
The string must contain the \n newline and ! or ? or . where it is present. An example of the file test.txt
Lorem ipsum dolor sit amet, consectetur adipisicing elit, sed do eiusmod tempor
incididunt ut labore et dolore magna aliqua. Ut enim ad minim veniam quis nostrud
exercitation ullamco laboris nisi ut aliquip ex ea commodo consequat.
Ut enim ad minima veniam, quis nostrum exercitationem ullam corporis suscipit
laboriosam, nisi ut aliquid ex ea commodi consequatur Quis autem vel eum
iure reprehenderit qui in ea voluptate velit esse quam nihil molestiae
consequatur, vel illum qui dolorem eum fugiat quo voluptas nulla pariatur?
my code reads up to the first token, where am I wrong?
int main(){
FILE *file;
char stringa[MAXCHAR];
file = fopen ("prova.txt", "r");
if (file == NULL){
perror("errore nell'apertura del file");
return (1);
}
while (fscanf(file, "%[^!?.]", stringa) != EOF) {
printf("Data from file:\n%s", stringa);
//break;
}
fclose(file);
return 0;
}
my output:
Lorem ipsum dolor sit amet, consectetur adipisicing elit, sed do eiusmod tempor
incididunt ut labore et dolore magna aliqua
Thanks for your help...

Answer 1

It exits because you used break as soon as you spot the ., ? or ! in input.
I believe what you want is to replace any of these three characters in input stream by \n.
If that's the case then replace break by printf("\n")

Answer 2

Your code reads up to the first token found but it puts back the tokens so even without the "break" your program will not read any further , it will go into an infinite loop because your while condition isn't so well defined , it should be :
while (fscanf(file, "%[^!?.]", stringa) == 1) //checks if text was read successfully
Also you need to get rid of any tokens when encountered , this should do it:
while (fscanf(file, "%[^!?.]", stringa) == 1) {
printf("Data from file: %s\n", stringa);
fscanf(file,"%*[!?.]");
}