Dynamic allocation of char** [closed] - c

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This is the text of my example:
Loading number N then N words from standard input. The word is not longer than 100 characters. Dynamically allocate array of loaded words as a series of pointers to character strings (dynamic array needs to have a type char **). Provide a set of words printed in a single line with spaces between the words.
Can someone tell me how to set the character limits?
Should I do this:
scanf("%100s", str[i])
or something else?
BTW, how can I allocate the memory for a type like this (char **,int **,etc)?
This is my code that I've done, so what have I done wrong?
int main()
{
int i,n;
printf("How much words? "), scanf("%d", &n);
char *str= (char *)malloc(n*sizeof(char *));
for(i = 0; i < n; i++)
{
str[i] = malloc(100 * sizeof(char *));
printf("%d. word: ", i + 1),scanf("%s", str[i]);
}
for (i = 0; i < n; i++)
{
printf("%s ", str[i]);
}
getch();

Answer 1

Wrong type for array of pointers
// char *str
char **str
Code clean-up with comments.
// add void
int main(void) {
int i,n;
// Easier to understand if on 2 lines-of code
printf("How much words? ");
// test scanf() results
if (scanf("%d", &n) != 1) return -1;
// Consider different style to allocate memory, as well as type change
// char *str= (char *)malloc(n*sizeof(char *));
char **str= malloc(sizeof *str * n);
// check allocation
assert(str == NULL);
for(i = 0; i < n; i++) {
str[i] = malloc(sizeof *str[i] * 100);
// check allocation
assert(str[i] == NULL);
printf("%d. word: ", i + 1);
fflush(stdout);
// limit input width to 99
// test scanf() results
if (scanf("%99s", str[i]) != 1) return -1;
}
for (i = 0; i < n; i++) {
// Add () to clearly show beginning/end of string
printf("(%s) ", str[i]);
}
getch();
}