As the title of my question says the sleep() function works properly (and every other function call in the C function, the problem is that after it's finished running I get an error that says:
"Run-Time Check Failure #0 - The value of ESP was not properly saved across a function call. This is usually a result of calling a function declared with one calling convention with a function pointer declared with a different calling convention."
I believe the way I'm handling the registers when I call the sleep function is done properly because it actually works, I posted the whole function just in case it's needed to detect where I might be misplacing the stack contents in another function call.
The function basically prints an elevator going up from the last floor on the bottom to the top-most one.
int deSubidaASM() {
int sleepTime = 900;
char *clear = "cls";
char *piso = "[x]";
char *pisoVacio = "[ ]";
char *texto = "%s\n";
char *fuerza = "Fuerza G: 1";
_asm {
mov ebx, 0 //int a=0
mov ecx, 9 //int b=9
_while1: //while (a <= 9)
cmp ebx, 9 //
jg _fin //if ebx>9, end
_Fuerza: //writes on screen
mov eax, fuerza
push eax
mov eax, texto
push eax
mov esi, ecx //
call printf
mov ecx, esi //
pop edx
pop edx
_sleep:
mov eax, sleepTime
push eax //pushes the sleep time input
mov esi, ebx //auxiliary variable to keep the cycle counters
mov edi, ecx //same as the above line comment
call Sleep //sleep() call
mov ecx, edi //returns the values from the aux variables
mov ebx, esi //same as the above line comment
pop eax //cleans the stack
_clearscreen:
mov eax, clear //Bloque para clearscreen
push eax
mov esi, ebx
mov edi, ecx
call system
mov ecx, edi
mov ebx, esi
pop edx
_while2 : //while (b >= 0)
cmp ecx, 0 //
jle _resetearWhile2 //if ecx<0 restart while2
cmp ebx, ecx // if the levels match
je _printPiso //print elevator
jne _printVacio //print floor
_printPiso :
mov eax, piso
push eax
mov eax, texto
push eax
mov esi, ecx //
call printf
mov ecx, esi //
pop edx
pop edx
dec ecx
jmp _while2
_printVacio :
mov eax, pisoVacio
push eax
mov eax, texto
push eax
mov esi, ecx //
call printf
mov ecx, esi //
pop edx
pop edx
dec ecx
jmp _while2
_resetearWhile2:
mov ecx, 9 //b=9
inc ebx
jmp _while1
_fin :
}
}
The WinApi Sleep() function follows the STDCALL calling convention. It had already cleaned up the stack when it returns. When you do the same, the stack is "overcleaned" ;-). Remove the line:
pop eax //cleans the stack
I don't know what compiler you use. My compiler (Visual Studio 2010) needs another call to Sleep():
call dword ptr [Sleep]
Too much for a comment. I mean push and pop the registers you are interested in preserving, including those you are juggling around from esi <-> ebx and edi <-> ecx.
_sleep:
push ecx // save the regs
push edx
push ebp
mov eax, sleepTime // func argument
push eax // pushes the sleep time input
call Sleep // sleep() call
pop eax // clean off stack
pop ebp // restore regs
pop edx
pop ecx
Related
I have elements loaded in stack and I need to move them to array. My code looks like this:
%include "asm_io.inc"
segment .data
array db 100 dup(0)
length db 0
segment .text
global _asm_main
extern getchar
_asm_main:
enter 0, 0
pusha
call getchar
char_loop:
mov ebx,10
sub eax, '0'
mul ebx
mov ebx, eax
call getchar
sub eax, '0'
add eax, ebx
push eax
inc BYTE[length]
call getchar
cmp eax, 10
je fill_array
cmp eax, 13
je fill_array
cmp eax, 32
je skip_spaces
jmp char_loop
skip_spaces:
call getchar
cmp eax, 32
je skip_spaces
jmp char_loop
fill_array:
mov ecx, [length]
mov ebx, array
l1:
pop eax
mov [ebx], eax ; should be al instead of eax
inc ebx
call print_int
call print_nl
loop l1
print_array:
mov ecx, [length]
mov ebx, array
l2:
mov eax, [ebx] ; should be al instead of eax
call print_int
call print_nl
inc ebx
loop l2
_asm_end:
call print_nl
popa
mov eax, 0
leave
ret
print_int in asm_io.asm is
print_int:
enter 0,0
pusha
pushf
push eax
push dword int_format
call _printf
pop ecx
pop ecx
popf
popa
leave
ret
Where int_format is int_format db "%i",0
Length and values in stack are correct, I had them printed but when I try to print array only last value is correct. Other values are random numbers. I tried combinations of registers of different sizes but it did not work. I think that error has to do something with size of registers or size of array.
Answer here:
As #xiver77 said in comments I was writing into array 4 bytes instead 1 byte. One element in array has 1 byte and I tried to write 4 bytes. That creates overflow of bites and change other elements in array. Instead mov [ebx], eax should be mov [ebx], al and mov eax, [ebx] for printing should be mov al [ebx].
%include "asm_io.inc"
;
; initialized data is put in the .data segment
;
segment .data
array: dd 180,32,455,499,388,480,239,346,257,84
fmt: dd ",%d",0
; uninitialized data is put in the .bss segment
;
segment .bss
resd 10
;
; code is put in the .text segment
;
segment .text
extern printf
global asm_main
asm_main:
enter 0,0 ; setup routine
pusha
; The following is just example of how to print an array
push dword 10
push dword array
call print_array
add esp,8 ; clean up stack
; don't delete anything following this comment
popa
mov eax, 0 ; return back to C
leave
ret
segment .data
ListFormat db ",%u", 0
segment .text
global print_array
print_array:
enter 0,0
push esi
push ebx
xor esi, esi ; esi = 0
mov ecx, [ebp+12] ; ecx = n
mov ebx, [ebp+8]
xor edx, edx
mov dl, [ebx + esi] ; ebx = address of array
mov eax,edx
call print_int
dec ecx
inc esi
print_loop:
xor edx,edx
mov dl,[ebx + esi]
push ecx ; printf might change ecx!
push edx ; push array value
push dword ListFormat
call printf
add esp, 8 ; remove parameters (leave ecx!)
inc esi
pop ecx
loop print_loop
call print_nl
pop ebx
pop esi
leave
ret
So this code prints out 180,0,0,0,32,0,0,0,199,1 when I want to print out 180,32,455,499,388,480,239,346,257,84. I think that it's because this is designed to print byte words. I'm trying to print in double words and I'm guessing something in the print_array needs to be changed. I tried mov dl, [ebx+esi*4] but it still doesn't print the array that I want to print. Or does something else needs to be changed to print array of double words?
You could leave it at changing the mov dl, [ebx+esi] instruction into mov edx, [ebx+esi*4], but that would be just half the fun!
1 Why not try to make a loop that can deal with the special case of the first value in the list that doesn't need the comma prefix? No more using print_int.
2 Also don't use the LOOP instruction. It's slow! The pair cmp jb (that can macro-fuse) is much better.
3 And replacing the prolog enter 0,0 and epilog leave codes by simply addressing the parameters via ESP relative addressing is simple enough.
4 Always consider the special cases! What if the array happens to be empty?
print_array:
push ebx
push esi
mov ebx, [esp+12] ; Begin array
mov esi, [esp+16] ; n
test esi, esi
jz done
lea esi, [ebx+esi*4] ; End array
mov edx, ListFormat+1 ; "%u"
more: mov eax, [ebx] ; Array dword value
push eax
push edx ; "%u" first time, ",%u" others
call printf
add esp, 8
add ebx, 4 ; To next dword in the array
mov edx, ListFormat ; ",%u"
cmp ebx, esi ; Current address < Last address ?
jb more ; Yes
call print_nl
done: pop esi
pop ebx
ret
Under the right conditions, keeping ESP fixed inside this loop can be worth doing. See Peter Cordes' comments below this answer.
Next is a version of this code that keeps ESP fixed inside the loop:
print_array:
push ebx
push esi
mov ebx, [esp+12] ; Begin array
mov esi, [esp+16] ; n
test esi, esi
jz done
sub esp, 8 ; Space for the printf args
lea esi, [ebx+esi*4] ; End array
mov edx, ListFormat+1 ; "%u"
more: mov eax, [ebx] ; Array dword value
mov [esp+4], eax
mov [esp], edx ; "%u" first time, ",%u" others
call printf
add ebx, 4 ; To next dword in the array
mov edx, ListFormat ; ",%u"
cmp ebx, esi ; Current address < Last address ?
jb more ; Yes
call print_nl
add esp, 8
done: pop esi
pop ebx
ret
This builds successfully and there is nothing wrong with typing integers. However, I can't see the outcome of gcd and the debugger runs without anything. Is it because of the infinite loop? I am totally lost in here. Could anyone figure out what I am missing here? Please help me what is wrong with this?
INCLUDE Irvine32.inc
.data
strA BYTE "Enter an integer A: ",0
strB BYTE "Enter an integer B: ",0
temp DWORD ?
finalStr BYTE "GCD of the two integers is: ",0
.code
main PROC
call Clrscr
mainLoop:
mov edx,OFFSET strA
call WriteString
call ReadInt
mov temp, eax
call Crlf
mov edx, OFFSET strB
call WriteString
call ReadInt
mov ebx, eax
mov eax, temp
call Crlf
call GCD
mov edx, OFFSET finalStr
call WriteString
call WriteInt
call WaitMsg
jmp mainLoop
main ENDP
abs PROC
cmp eax, 0 ; see if we have a negative number
jge done
neg eax
done:
ret
abs ENDP
gcd PROC
call abs ;takes absolute value of both registers
mov temp, eax
mov eax, ebx
call abs
mov ebx, eax
mov eax, temp
cmp eax, ebx ; making sure we divide the bigger number by the smaller
jz DONE ; if numbers are equal, GCD is eax either way
jc SWITCH ;swaps if ebx is larger then eax
mov edx, 0
SWITCH: ;swaps values so eax is larger then ebx
mov temp, eax
mov eax, ebx
mov ebx, temp
mov edx, 0
jmp L1
L1: ;divides until remainder is 0, then eax is GCD
div ebx
cmp edx, 0
jz DONE
mov eax, edx
jmp L1
DONE:
gcd ENDP
END main
Your GCD function is missing a return instruction:
DONE: <-- There should be a RET after the DONE label
gcd ENDP
I'll tell you one thing wrong with that code straight up (there may be other issues, that's just the one that immediately popped out):
jc SWITCH ;swaps if ebx is larger then eax
mov edx, 0
SWITCH: ;swaps values so eax is larger then ebx
mov temp, eax
mov eax, ebx
mov ebx, temp
mov edx, 0
jmp L1
L1: ;divides until remainder is 0, then eax is GCD
This will switch the registers no matter what since regardless of the state of the carry flag, you run the code at SWITCH. Either you explicitly jump to there, or you fall through to there.
I suspect the jmp L1 (which is superfluous at its current position, for reasons identical to the jump if carry) should be immediately after the jc SWITCH so that the whole thing either swaps or doesn't swap.
In other words, something like:
jnc L1 ; skip swap unless ebx > eax.
SWITCH: push eax ; don't need temp at all, use stack.
push ebx
pop eax
pop ebx
L1:
mov edx, 0 ; carry on.
My task here is to add a code that sorts the array with insertion sort.
'printf' function prints a string
printArray prints the array
For some reason the array doesn't get sorted, and i cant find the reason why.
Help will be appreciated.
main:
push MSG ; print welcome message
call printf
add esp,4 ; clean the stack
call printArray ;print the unsorted array
;;;;;;;;;;add code here;;;;;;;;;;
mov eax,1
loop1:
mov ebx, array
add ebx, eax
loop2:
mov esi, ebx
dec esi
mov esi, [esi] ;esi holds the value before what ebx points to
cmp [ebx], esi
ja endLoop2
mov edx, esi
mov esi, ebx
dec esi
mov ecx, [ebx]
mov [esi], ecx
mov [ebx], edx
dec ebx
cmp ebx, array
ja loop2
endLoop2:
inc eax
cmp eax, 11
jbe loop1
;;;;;;;end of your code;;;;;;;;;;;;;;
call printArray
mov eax, 1 ;exit system call
int 0x80
If your array is full of 1 byte values, use movb instead of mov when loading and storing to memory.
I have the following assembly code:
; File: strrev.asm
; A subroutine called from C programs.
; Parameters: string A
; Result: String is reversed and returned.
SECTION .text
global strrev
_strrev: nop
strrev:
push ebp
mov ebp, esp
; registers ebx,esi, and edi must be saved if used
push ebx
push edi
xor esi, esi
xor eax, eax
mov ecx, [ebp+8] ; load the start of the array into ecx
jecxz end ; jump if [ecx] is zero
mov edi, ecx
reverseLoop:
cmp byte[edi], 0
je reverseLoop_1
inc edi
inc eax
jmp reverseLoop
reverseLoop_1:
mov esi, edi ;move end of array into esi
mov edi, ecx ;reset start of array to edi
reverseLoop_2:
mov al, [esi]
mov bl, [edi]
mov [esi], bl
mov [edi], al
inc edi
dec esi
dec eax
jnz reverseLoop_2
end:
pop edi ; restore registers
pop ebx
mov esp, ebp ; take down stack frame
pop ebp
ret
Which works fine until you start looping through reverseLoop_2. Using gdb, eax is listed as being 11, which it should be (this is the length of the string I passed in through a separate c program). This is show in the debugger as:
Breakpoint 2, reverseLoop_2 () at strrev.asm:40
40 mov al, [esi]
(gdb) display $eax
1: $eax = 11
However, if I step through the program to the next line, it resets to 0.
(gdb) next
41 mov bl, [edi]
1: $eax = 0
I need eax to be preserved since its the one keeping track of how many times reverseLoop_2 needs to loop. Why is it resetting to 0 after the call to mov?
If you're using eax as a loop counter, you shouldn't write to it inside the loop :
reverseLoop_2:
mov al, [esi]
Remember that al is the least significant byte of eax :
I think this should work.
mov eax, address of your string
push esi
push edi
mov edi, eax
mov esi, eax
; find end of string
sub ecx, ecx
not ecx
sub al, al
cld
repne scasb
; points to the byte after '0x00'
dec edi
dec edi
; main loop will swap the first with the last byte
; and increase/decrease the pointer until the cross each other
_loop:
cmp esi, edi ; if both pointers meet, we are done
jg _done
mov al, [edi]
mov bl, [esi]
mov [esi], al
mov [edi], bl
inc esi
dec edi
jmp _loop
_done:
pop edi
pop esi