Group by a set of Values (Check-In or Check-Out) - sql-server

Question

I have a simple table which records people clocking-in and clocking out like so.
Id | EmployeeNumber | InOutId | InOutDateTime
-----------------------------------------------------
1 | 505 | IN | 2015-03-24 08:32:42:000
1 | 506 | IN | 2015-03-24 08:35:47:000
1 | 507 | IN | 2015-03-24 08:46:12:000
1 | 505 | OUT | 2015-03-24 16:59:00:000
1 | 506 | OUT | 2015-03-24 17:05:00:000
I want to show the total people currently IN and those currently OUT. In other words:
- Total IN means those that do not have a corresponding OUT for that given day. - Total OUT means those that do have an IN and an OUT for that given day.
So, based on my table above, I want to get the following results:
TotalCurrentlyIn | TotalCurrentlyOut
-----------------------------------------
1 | 2
This is what I have so far:
DECLARE #d date;
set #d = cast('2015-03-24 15:02:42.000' as date)
select EmployeeNumber, InOutId, InOutDateTime from MyAttendance
where
InOutDateTime >= DATEADD(day, DATEDIFF(day, 0, #d), 0)
and InOutDateTime < DATEADD(day, DATEDIFF(day, 0, #d) +1, 0)
order by
EmployeeNumber, InOutId
I need to be able to sum and group by - any ideas?

Answer 1

try,
DECLARE #d date;
set #d = cast('2015-03-24 15:02:42.000' as date)
;with cte as(
select t.EmployeeNumber,t.InOutId as in1,
t1.InOutId out1,t.InOutDateTime from #t t
left join (select EmployeeNumber,InOutId,InOutDateTime from #t
where InOutId='OUT' and cast(InOutDateTime as date)=cast(#d as date) ) t1
on t.EmployeeNumber=t1.EmployeeNumber and
cast(t.InOutDateTime as date)=cast(t1.InOutDateTime as date)
where t.InOutId='IN' and cast(t.InOutDateTime as date)=cast(#d as date))
select count(in1) Totalin,count(out1) Totalout, sum(case when out1 is null then 1 else 0 end) TotalCurrentlyIn
,count(out1) TotalCurrentlyOut from cte
data
declare #t table (Id int,EmployeeNumber int, InOutId varchar(3), InOutDateTime datetime)
insert into #t(Id, EmployeeNumber,InOutId, InOutDateTime) values
(1 , 505 , 'IN' , '2015-03-24 08:32:42:000'),
(1 , 506 , 'IN' , '2015-03-24 08:35:47:000'),
(1 , 507 , 'IN' , '2015-03-24 08:46:12:000'),
(1 , 505 , 'OUT' , '2015-03-24 16:59:00:000'),
(1 , 506 , 'OUT' , '2015-03-24 17:05:00:000')

Answer 2

CheckIn = 1 and CheckOut = 2 so you need to check last entry of all the uses.
Select EmployeeId, ActionType, Max(ActionDateTime)
From AttendanceLog
Where
ActionDateTime >= DATEADD(day, DATEDIFF(day, 0, #d), 0)
and ActionDateTime < DATEADD(day, DATEDIFF(day, 0, #d) +1, 0)
Group by
EmployeeId, ActionType
Order by
EmployeeId,ActionType

Answer 3

If I understand the question. you need to know how much person is in the office right now:
the first query return the max date for any employee, than you join it with the actionType
select
EmployeeId , max(ActionDateTime) as MaxActionDateTime into #temptable
from table
group by EmployeeId
select count (EmployeeId), ActionType
from table inner join #temptable
on table.EmployerId == #temptable.EmployerId
and table.ActionDateTime == #temptable.MaxActionDateTime
group by ActionType

Answer 4

Using a windowing function you can get the last action for every employee and count those
With data As (
Select id, EmployeeNumber, InOutId
, lastAction = ROW_NUMBER() OVER (PARTITION BY EmployeeNumber
ORDER BY InOutDateTime DESC)
From table1
)
Select Count(CASE InOutId WHEN 'IN' THEN 1 END) TotalCurrentlyIn
, Count(CASE InOutId WHEN 'OUT' THEN 1 END) TotalCurrentlyOut
From data
Where lastAction = 1