Converting 2D array of numbers into chars - c

Question

I am making a maze using Depth-First search algorithm as a school project. The maze is working pretty much as I want but I have a little problem. I have to use # as a wall and . as a path when printing the maze but I used 0 as a wall and 1 as a path at first thinking that it is gonna be easy to change it later but I was wrong. How can I change 0 and 1 into # and .?
Code:
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
void nahodne_suradnice(int *r, int *s, int n)
{
srand(time(NULL));
*r = ((rand() % n) - 1) + 2;
if (*r == 1 || *r == n)
{
*s = (rand() % n) + 2;
}
else
{
if (rand() % 2 == 1)
*s = 1;
else
*s = n;
}
}
int main()
{
int i, j, n, r, s,smer,posledny_smer[1500];
int maze[500][500];
scanf_s("%d", &n);
if (n < 10 || n > 100)
{
return 0;
}
//vynulovanie pola/bludiska
for (i = 1; i < n + 1; i++)
{
for (j = 1; j < n + 1; j++)
{
maze[i][j] = 0;
}
}
//nahodny vyber zaciatku bludiska
nahodne_suradnice(&r, &s, n);
//generovanie bludiska
j = 0;
maze[r][s] = 2;
for (i = 0 ;; i++)
{
//backtracking
if ((maze[r - 1][s] == 1 || maze[r - 2][s] == 1 || r - 2 <=1 || s==n || s==1) && (maze[r][s + 1] == 1 || maze[r][s + 2] == 1 || s + 2 >= n || r == n || r==1) && (maze[r + 1][s] == 1 || maze[r + 2][s] == 1 || r + 2 >= n || s == n || s==1) && (maze[r][s - 1] == 1 || maze[r][s - 2] == 1 || s - 2 <=1 || r == n || r==1))
{
if (posledny_smer[j-1] == 1)
if (maze[r + 1][s] == 1 && maze[r + 2][s] == 1)
{
r += 2;
j--;
continue;
}
else
{
j--;
continue;
}
if (posledny_smer[j-1] == 2)
if (maze[r][s - 1] == 1 && maze[r][s - 2] == 1)
{
s -= 2;
j--;
continue;
}
else
{
j--;
continue;
}
if (posledny_smer[j-1] == 3)
if (maze[r - 1][s] == 1 && maze[r - 2][s] == 1)
{
r -= 2;
j--;
continue;
}
else
{
j--;
continue;
}
if (posledny_smer[j-1] == 4)
if (maze[r][s + 1] == 1 && maze[r][s + 2] == 1)
{
s += 2;
j--;
continue;
}
else
{
j--;
continue;
}
if (j == 0)
{
if (r == n)
{
nahodne_suradnice(&r, &s,n);
maze[1][s] = 3;
maze[2][s] = 3;
}
if (r == 1)
{
nahodne_suradnice(&r, &s, n);
maze[n][s] = 3;
maze[n - 1][s] = 3;
}
if (s == n-2)
{
nahodne_suradnice(&r, &s, n);
maze[r][1] = 3;
maze[r][2] = 3;
}
if (s == 3)
{
nahodne_suradnice(&r, &s, n);
maze[r][n] = 3;
maze[r][n-1] = 3;
}
break;
}
}
//buranie stien
smer = (rand() % 4) + 1;
if (smer == 1)
{
if (r - 2 >1 && s<n && s>1)
{
if (maze[r - 1][s] == 1 || maze[r - 2][s] == 1)
continue;
maze[r - 1][s] = 1;
maze[r - 2][s] = 1;
r -= 2;
posledny_smer[j] = smer;
j++;
continue;
}
}
if (smer == 2)
{
if (s + 2 < n && r < n && r>1)
{
if (maze[r][s+1] == 1 || maze[r][s+2] == 1)
continue;
maze[r][s + 1] = 1;
maze[r][s + 2] = 1;
s += 2;
posledny_smer[j] = smer;
j++;
continue;
}
}
if (smer == 3)
{
if (r + 2 < n && s < n && s>1)
{
if (maze[r + 1][s] == 1 || maze[r + 2][s] == 1)
continue;
maze[r + 1][s] = 1;
maze[r + 2][s] = 1;
r += 2;
posledny_smer[j] = smer;
j++;
continue;
}
}
if (smer == 4)
{
if (s - 2 >1 && r < n && r>1)
{
if (maze[r][s-1] == 1 || maze[r][s-2] == 1)
continue;
maze[r][s - 1] = 1;
maze[r][s - 2] = 1;
s -= 2;
posledny_smer[j] = smer;
j++;
continue;
}
}
}
//vypis bludiska
for (i = 1; i < n + 1; i++)
{
for (j = 1; j < n + 1; j++)
{
printf("%d", maze[i][j]);
}
printf("\n");
}
system("PAUSE");
return 0;
}
`
Thanks.

Answer 1

Change the definition of maze to:
char maze[500][500]
and change all references to use char instead of int. Then return '#' and '.' instead of 0 and 1.

Answer 2

You can change from 0 and 1 to # and . (or any other representation) when printing. For instance you can change:
printf("%d", maze[i][j]);
to
switch(maze[i][j]) {
case 0:
printf("#");
break;
case 1:
printf(".");
break;
default:
printf("X"); /* in case you have some value other than 0 or 1 in the maze */
}
If you do it like this, you can change which letters you want to display the maze as without changing other parts of your code.