C: Help understanding pointers - c

I have been building this hash table function that is given an array it gets a word from and a pointer to an array that it fills with my linked list struct. It compiles correctly but I get a segmentation fault at - *hashTable[hashVal] = *newNode; .
void hashTableCreate(char *array, list *hashTable[]) {
while(arrayPos < getArrayLength(array)) {
char *temp = getWord(array);
int hashVal = hashingFunc(temp);
if((*hashTable[hashVal]).word == temp ) {
(*hashTable[hashVal]).count = (*hashTable[hashVal]).count+1;
}
else {
list *newNode = malloc(sizeof(list));
strcpy(newNode->word,temp);
newNode->count = 1;
*hashTable[hashVal] = *newNode;
}
}
}
It's called like this:
void timeStructures(char *newArray) {
list *hashTable[3000];
hashTableCreate(newArray, hashTable);
}
I know this is to do with the way I am using my pointers but I can't figure it out. Any help would be appreciated.

There are several problems on this code:
You seem you are using extra asterisks when assigning newNode to hashTable.
You can use ++ operator to increment count, and use -> to access a member of a pointer to struct.
getWord is unknown to me, but seems impossible it can return a pointer to a string contained inside an element of hashTable, which means the next if will always be false (newNode's word is a copied string, not a pointer to array's word), as it compares memory addresses instead of strings.
You never free temp neither hashTable elements, which seems another misconception of what you are doing here.
As noted by #kaylum , you should initialize hashTable so you avoid comparing against unassigned array elements, neither modifying count on them.
hashTable has to be passed as a pointer to hashTableCreate, or this will work on a copied version of it:
Try this:
void hashTableCreate(char *array, list *(*hashTable[])) {
while(arrayPos < getArrayLength(array)) {
char *temp = getWord(array);
int hashVal = hashingFunc(temp);
if((*hashTable)[hashVal] != NULL &&
strcmp((*hashTable)[hashVal]->word, temp) == 0 ) {
(*hashTable)[hashVal]->count++;
}
else {
list *newNode = malloc(sizeof(list));
strcpy(newNode->word,temp);
newNode->count = 1;
(*hashTable)[hashVal] = newNode;
}
free(temp);
}
}
void timeStructures(char *newArray) {
list *hashTable[3000];
int i;
// Initialize hashTable pointers to NULL
for(i = 0; i < 3000; i++) {
hashTable[i] = NULL;
}
hashTableCreate(newArray, &hashTable);
// Free hashTable elements, malloc'ed at hashTableCreate
for(i = 0; i < 3000; i++) {
if(hashTable[i] != NULL) {
free(hashTable[i]);
}
}
}
Note 1: you never check if hashVal is higher than 3000, which might be fine if you know what you are doing, aka, you know hashingFunc will never return 3000 or higher. If you do not, you'll need to care about growing hashTable appropriately.
Note 2: executing getArrayLength on each loop might be a performance problem for large lists. You probably prefer to create a variable to contain its value and execute it only once.
Note 3: It might be some easier if you declare hashTable as a plain list of elements, not a list of pointers to elements, like list hashTable[3000];, but I don't know exactly what you're looking for. Also, it will always waste 3000 list elements of memory, so might be a performance problem.

Related

Increment integer pointer in a loop in C

My original code to display nodes in a queue in order from lowest to greatest:
void display (queue *q) {
node *ptr = q->front;
int i = 0;
int size = q->size;
while (i <= size) {
while (ptr->id != i) {
ptr = ptr->next;
}
if (i == 0) {
printf("%d ", ptr->id);
printf("%d\n", ptr->running);
}
else {
printf("%d ", ptr->id);
}
i++;
ptr = q->front;
}
}
Had kept producing Segmentation Fault (Core Dumped) errors. I have malloc the two variables being compared and this error has been fixed.
void display (queue *q) {
node *ptr = malloc(10);
ptr = q->front;
int *i = NULL;
i = malloc(sizeof(int));
*i = 0;
int size = q->size;
while(*i <= size){
while (ptr->id != *i) {
ptr = ptr->next;
}
if (*i == 0) {
printf("%d %d\n", ptr->id, ptr->running);
}
else {
printf("%d %d %d %d\n", ptr->id, ptr->running, ptr->ready, ptr->blocked);
}
i = i + 1 * (sizeof(char));
ptr = q->front;
}
}
However now this doesn't produce the output that I want. I want to increment the i pointer so that it can be the same as my original code.
This has been immensely frustrating, any help would be greatly appreciated!
If I read your first code listing correctly, there's at least one important thing here you need to think about. You seem to have a linked list here, and you're iterating over that list using ptr = ptr->next. This means you need to know when to stop. One common way of setting up a linked list is that the last item in the list has a next value of NULL. Then process the nodes one at a time, and once you are done with one node, you you check whether the next value is NULL: if it isn't you can move on that that next node, if it is NULL you stop.
Here you're not doing checks like this, so you need another way to ensure that you know when to stop. What you seem to be doing is taking the value of q->size and using that to inform you how many items there are in the linked list. So the first thing to think about is how confident you are that that value is correct. For example, if the code building the list puts only two items into the list, bet sets size to three, you'll end up falling off the end of the list, and a segmentation fault is not unlikely.
But there's something even more important than that. Even if you're getting the correct number of items in the list from q->size, you're comparing your loop variable i to size like this:
int i = 0;
while (i <= size) {
⋮
}
This is going to loop with i having the values [ 0, 1, … size ], which is actually size + 1 times. If you want to loop exactly size times, you want a test like i < size rather than i <= size. This is a common mistake, often called an off-by-one error.
Unfortunately, your second listing complicates things, rather than making them better. Go back to your first one and see if you can fix the things I've mentioned here.

Segmentation fault copying tree nodes into array

I use this structure for my tree:
typedef struct product{
char name[50];
char id[5];
double price;
int amount;
struct product *left_p, *right_p;
}product_t;
So, I must convert the tree into an array.
I wrote this for the tree dimension:
int tree_dim(product_t *node_p){
int i = 1 ;
if (node_p == NULL)
i = 0;
else{
i += tree_dim(node_p->left_p);
i += tree_dim(node_p->right_p);
}
return i;
}
My tree is populated by reading the records from a txt file. The records are 21 and the value returned by tree_dim is correct. The value is stored inarr_dim.
Then I create aproduct_t *products_a; wich will be the "array" and allocate it in memory by using products_a = malloc (arr_dim*sizeof (product_t));
Now, this is the function to fill the array with the tree nodes:
void fill_array(int *index, product_t *node_p, product_t *products_a){
if (node_p != NULL){
fill_array(index, node_p->left_p, products_a);
products_a[*index++] = *node_p;
fill_array(index, node_p->right_p, products_a);
}
}
But it gives me segmentation fault error so I also tried this 2nd solution:
int fill_array(product_t *node_p, product_t *products_a){
int i = 1 ;
if (node_p == NULL){
i=0;
}
else
{
i += fill_array(node_p->left_p, products_a);
products_a[i-1] = *node_p;
i += fill_array(node_p->right_p, products_a);
}
return i;
}
Which doesn't give segmentation fault but when I print the array there are empty positions.
I need some tips on where I'm wrong. Maybe a problem with the index and the recursive calls but I can't figure it out.
Look at the precedence of these two operators
*index++
++ Incrementation has higher precedence than * dereference right?
So if you first move in memory by sizeof(int) then you arent no more in your allocated memory and dereferencing would cause UB.
Its always better to use brackets () if you arent sure about precedence.
(*index)++ // This is right
Filip has already pointed out the problem with your first function.
The problem with your second function is that it works only when filling from the left branch. After you have done that and copied the current product, there are some elements in the array, but copying from the right branch will start at index 0 again, so it will overwrite existing data and leave data at the end uninitialised.
You could fix this by passing the current index i to your function, but I find the i = func(..., i); syntax a bit redundant.
In C, you can pass in a subarray of array starting at element i with &array[i] or just array + i. (Remember that an array in a function call "decays" into a pointer to the first element, &array[0].)
So this will work:
int fill_array(product_t *node_p, product_t *products_a)
{
int i = 0;
if (node_p == NULL) return 0;
i += fill_array(node_p->left_p, products_a);
products_a[i++] = *node_p;
i += fill_array(node_p->right_p, &products_a[i]);
return i;
}

How to keep linked list head from changing?

I'm trying to create a linked list structure to store data. The head of the linked list seems to be updating somehow. I have the following code. I can't seem to figure out how put char array data into a node and keep it from updating when the address to said char array's data updates.
The following code prints out whatever string is passed into the processStr function. How do I keep head from updating ?
//Linked List Structure
mainNode *head = NULL;
//take and store word in data structure
void processStr(char *str){
//char array
char strArray[sizeof(str)+1];
//stores lower case string
char strLower[strlen(str)];
int i;
for(i = 0; str[i]; i++)
strLower[i] = tolower(str[i]);
strLower[i] = '\0';
//printf("%s : ", strLower);
//Starts Linked List
if(head == NULL){
mainNode *mainPtr = (mainNode *)malloc(sizeof(mainNode));
nameNode *namePtr = (nameNode *)malloc(sizeof(nameNode));
mainPtr->name = strLower;
mainPtr->numOccurances = 1;
mainPtr->next = NULL;
mainPtr->nextName = namePtr;
namePtr->name = strArray;
namePtr->next = NULL;
head = mainPtr;
}
printf("%s : " , head->name);
}
You assign the pointers mainPtr->name and namePtr->name to variables strLower and strArray that are declared locally in processStr(). That means after that function returns, any access to these pointers results in undefined behaviour. You could do sth. like
mainPtr->name = strdup( strLower );
instead to allocate memory for the strings.
Btw.: strLower must also be declared as char strLower[strlen(str)+1];
The above code will only run once only which will add information to head only once. If you want to add more information in case of second run then add code for else condition. Example:-
if ( head == NULL ) {
// code to insert data in case of first run
}else{
// code to insert data for second run and so.....
}

Pointer becomes null

I'm passing a file pointer to a function(A) which then opens the file, reads a line in a while loop (for each line in the file) and calls another function(B) using theses values. The issue is after running through function B once, the file pointer becomes NULL and I'm not sure why.
void readMatrixData(matrix *matrix, FILE *fileInput)
{
char buffer[30];
while(fgets(buffer, 30, fileInput) != NULL) {
char *splitString = strtok(buffer, ",");
int row = atoi(splitString);
splitString = strtok(NULL, ",");
int column = atoi(splitString);
splitString = strtok(NULL, ",");
int value = atoi(splitString);
insertNewNode(&matrix->rowArray[row], &matrix->columnArray[column], value, row, column);
}
}
I check if fopen returns NULL before calling function A, and it's not. I've also set a breakpoint on the while loop and the first time it hits, fileInput has some memory allocated. However, on the second loop fileInput becomes NULL and I'm not sure why.
EDIT:
Here's the insertNewNode function:
void insertNewNode(node **rowHead, node **columnHead, int value, int row, int column) {
//Get to the correct position in the column linked list
if (*columnHead == NULL) {
*columnHead = malloc(sizeof(node));
} else {
while((*columnHead)->nextColumn != NULL && (*columnHead)->nextColumn->row < row)
*columnHead = (*columnHead)->nextColumn;
}
//Get to the correct position in the row linked list.
if (*rowHead == NULL) {
*rowHead = malloc(sizeof(node));
} else {
while((*rowHead)->nextRow != NULL && ((*rowHead)->nextRow->column < column))
*rowHead = (*rowHead)->nextRow;
}
node *newNode = malloc(sizeof(node));
newNode->column = column;
newNode->row = row;
newNode->value = value;
(*columnHead)->nextColumn = newNode;
(*rowHead)->nextRow = newNode;
}
The structs involved are:
typedef struct matrix {
node **rowArray;
node **columnArray;
Size matrixDimensions;
} matrix;
typedef struct node {
int value;
int row;
int column;
struct node *nextColumn;
struct node *nextRow;
} node;
and I initialise the matrix arrays with:
node *columns[m->matrixDimensions.columns];
node *rows[m->matrixDimensions.rows];
for (int i=0; i< m->matrixDimensions.columns; i++)
{
columns[i] = NULL;
}
for (int i=0; i < m->matrixDimensions.rows; i++)
{
rows[i] = NULL;
}
m->columnArray = columns;
m->rowArray = rows;
Probably the function insertNewNode overwrites memory
Prefer strtol over atoi.
As #DavideBerra suggested, comment out the call to insertNewNode and step through the code to confirm you can make multiple iterations of your while loop.
I don't understand how you are initialising your matrix arrays using m->matrixDimensions.columns and m->matrixDimensions.rows. Are you using C99 VLAs?
Crank up the warning levels of your compiler and ensure zero-warning compilation.
You do not initialize the nextRow and nextColumn fields of your newly allocated node. Doing so should prevent you from at least some trouble. It is strange that you do not get a Segfault.
You are also mixing array and linked list, what could happen if you get "overflowing" values from your file ? I feel like the segfault is not far away from here. Be very careful, your code shows weird concept mixing !
As others had suggested you, comment your insertNewNode call and see if your loop is well performed. If it is, run your program step by step using a debugger. Hope this helps, good luck !
check the value of row and column before accessing matrix->rowArray and matrix->columnArray whether these values are less than the array size.
My guess is that the values row,column may be outside your matrix and thus overwriting memory. Add a check of the values you receive and make sure your matrix is large enough. Remember arrays are zero indexed in C.

Circular shift a dynamic c array by n elements

I have a queue of set length implemented as a dynamic c array implemented like this:
typedef struct {
float* queue;
int size;
int pointer;
} QueueStruct;
void createQueue(QueueStruct* queueInstance, int size){
queueInstance->queue = malloc(sizeof(float)*size);
queueInstance->size = size;
queueInstance->pointer = 0;
}
void addElementToQueue(QueueStruct* queueInstance,float element){
queueInstance->queue[pointer] = element;
if (queueInstance->pointer == queueInstance.size - 1){
queueInstance->pointer = 0;
} else {
++queueInstance->pointer;
}
}
void freeQueue(QueueStruct* queueInstance){
free(queueInstance->queue);
}
And I want to implement this function:
float* returnQueue(QueueStruct queueInstance){
//I want this function to malloc a new float* and then put the queue in it in the
// correct order, from start to finish, as pointed too by the pointer.
//Im not sure how to do this.
}
Any help would be appreciated.
Edit: Corrected a silly programming mistake - this is a simplified version of what is actually in my program.
Let's see if I got that right.
float* returnQueue(QueueStruct *queueInstance){
int j = 0;
float *ret = malloc(sizeof(float)*queueInstance->size); //Allocates the memory you want.
//Copies the elements from pointer to End into the new buffer (assumes, that the array has been filled at least once, add a marker to make sure)
if(queueInstance->FilledOnce) { //Marker variable, explanation as above.
for(int i = queueInstance->pointer; i < queueInstance->size; ++i, ++j)
ret[j] = queueInstance->queue[i];
}
//Copies the newest elements (from beginning to pointer) into the buffer.
for(int i = 0; i < queueInstance->pointer; ++i, ++j)
ret[j] = queueInstance->queue[i];
return ret; //Returns the code in question.
}
To make this code work, you'd have to add 'FilledOnce' to your struct, and amend your 'Add' Code as follows:
void addElementToQueue(QueueStruct* queueInstance, float element){
queueInstance->queue[queueInstance->pointer] = element;
if (queueInstance->pointer == queueInstance.size - 1){
queueInstance->pointer = 0;
queueInstance->FilledOnce = 1;
} else {
++queueInstance->pointer;
}
}
I also advise you, to reset your variables, once you're done with it.
void freeQueue(QueueStruct* queueInstance){
free(queueInstance->queue); //Frees the queue
queueInstance->queue = NULL; //Nulls the reference
queueInstance->FilledOnce = 0;
queueInstance->pointer = 0;
queueInstance->size = 0;
}
This way, if you reuse the struct, you won't run into the problem of trying to access non-allocated memory. Just be sure to check for those variables.
I hope this helps.
I think you should allocate memory for your struct also.
You have made pointer of struct but forgot to allocate memory for that struct
use QueueStruct queuestruct= malloc(sizeof(Queuestruct))
then when you pass this to any of the function above then you can easily allocate
memory for queue poiter in which you can store element for your queue array
This implementation is insufficient. A pointer variable give us location of a tail of queue, but what points to it's head?

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