Trouble with array in function - c

Question

I'm having trouble with a program that takes a 2d array, calculates the average of each row, then stores these averages in a new array. Where I seem to be having the problem is with actually assigning the averages to the new 1d array. If I put a print statement in the loop directly after the value has been assigned it seems to be there and work fine. But once I try to display whats in the array with my created display function it is all zeroes except for one entry that's a random large number.
Sample Output:
36.25 58.00 52.00 42.00 51.75 47.00 <--- From print within average function (Correct)
0.000 0.000 0.000 0.000 406778500087808.000 0.000 <--- From created display function
void row_average(int vals2d[][4], int rows, int cols)
{
int k, l, sum;
float avg, rowavg[6];
for (k=0; k<rows; k++){
sum = 0;
avg = 0;
for (l=0; l<cols; l++){
sum = sum + vals2d[k][l];
avg = (float)sum/4;
}
rowavg[k] = avg;
printf("%.2f ", rowavg[k]);
}
}
void array_1display(float rowavg[], int size)
{
int m;
for (m=0; m<size; m++){
printf("%.3f ", rowavg[m]);
}
}
int main()
{
float rowavg[6];
int vals2d[6][4] ={
{12,54,34,45},
{68,76,65,23},
{75,23,76,34},
{6,45,58,59},
{35,67,93,12},
{66,90,25,7}
};
row_average(vals2d, 6, 4);
printf("\n");
array_1display(rowavg, 6);
}

Answer 1

You need to pass your array rowavg[] or make it global.
Here is some correction:
#include <stdio.h>
void row_average(int vals2d[][4], int rows, int cols, float rowavg[])
{
int k, l, sum;
float avg;
for (k=0; k<rows; k++){
sum = 0;
avg = 0;
for (l=0; l<cols; l++){
sum = sum + vals2d[k][l];
avg = (float)sum/4;
}
rowavg[k] = avg;
printf("%.2f ", rowavg[k]);
}
}
void array_1display(float rowavg[], int size)
{
int m;
for (m=0; m<size; m++){
printf("%.3f ", rowavg[m]);
}
}
int main()
{
float rowavg[6];
int vals2d[6][4] ={
{12,54,34,45},
{68,76,65,23},
{75,23,76,34},
{6,45,58,59},
{35,67,93,12},
{66,90,25,7}
};
row_average(vals2d, 6, 4, rowavg);
printf("\n");
array_1display(rowavg, 6);
}