Command to copy a file every 10 min only when Firefox is open - batch-file

Question

I would like to copy a file every 10 minutes when Firefox is open.
I am not sure what is the best way to do that but so far I have created a .bat that I wanted to link to a task in Task Scheduler that will run it every 10 minutes.
This is the command in the .bat :
copy "C:\Users\Me\Zotero\zotero.sqlite" "C:\Users\Me\Zotero\Zotero_Backup_sqlite\zotero_%date%.sqlite"
But Task Scheduler doesn't allow me to add a condition (= run only if firefox is open) nor to run a task every 10 minutes.
So here are my questions:
If a .bat is a good way to do this, how can I run a .bat with those two parameters?
If a .bat is not a good way to do this, what method would you recommend?

Answer 1

You could just have a batch file like this:
#echo off
:loop
tasklist /FI "IMAGENAME eq firefox.exe" 2>NUL | find /I /N "firefox.exe">NUL
if "%ERRORLEVEL%"=="0" copy "C:\Users\Me\Zotero\zotero.sqlite" "C:\Users\Me\Zotero\Zotero_Backup_sqlite\zotero_%date%.sqlite"
timeout /t 600 /nobreak
goto loop
This would be a standalone batch-script you would have to start yourself, or put in the startup folder.
You could also just take the
#echo off
tasklist /FI "IMAGENAME eq firefox.exe" 2>NUL | find /I /N "firefox.exe">NUL
if "%ERRORLEVEL%"=="0" copy "C:\Users\Me\Zotero\zotero.sqlite" "C:\Users\Me\Zotero\Zotero_Backup_sqlite\zotero_%date%.sqlite"
and run that every 10 minutes from task scheduler ofcourse.
You could also make this into your firefox shorcut and end it when the program isn't active anymore, like this:
#echo off
set programName=firefox.exe
start %programName%
:loop
tasklist /FI "IMAGENAME eq %programName%" 2>NUL | find /I /N "%programName%">NUL
if "%ERRORLEVEL%"=="0" copy "C:\Users\Me\Zotero\zotero.sqlite" "C:\Users\Me\Zotero\Zotero_Backup_sqlite\zotero_%date%.sqlite"
if "%ERRORLEVEL%"=="1" exit /b
timeout /t 600 /nobreak
goto loop