How would I modify this code so that I can enter in more than just one coefficient?
I am suppose to be able to enter in something like "3 2 1" and the spaces shouldn't affect my user input but I'm not sure how to do this.
This is the code I have so far:
#include <iostream>
using namespace std;
int *foil(int A[], int B[], int co, int coo)
{
int *product = new int[co+coo-1];
for (int i = 0; i<co+coo-1; i++)
product[i] = 0;
for (int i=0; i<coo; i++)
{
for (int j=0; j<co; j++)
product[i+j] += A[i]*B[j];
}
return product;
}
void printPoly(int poly[], int co)
{
for (int i=0; i<co; i++)
{
cout << poly[i];
if (i != 0)
cout << "x^" << i ;
if (i != co-1)
cout << " + ";
}
}
int main()
{
int co, coo;
int *A;
A=new int[co];
int *B;
B=new int[coo];
cout << "How many coefficients are in the first poly?: ";
cin >> co;
cout << "What are the coefficients? (Lowest power first): ";
cin >> *A;
cout << "How many coefficients are in the second poly?: ";
cin >>coo;
cout << "What are the coefficients? (Lowest power first): ";
cin >>*B;
printPoly(A, coo);
cout << "\n";
cout << "times" << endl;
printPoly(B, co);
cout << "\n";
cout << "-----" << endl;
int *product = foil(A, B, co, coo);
printPoly(product, co+coo-1);
return 0;
}
It outputs this:
How many coefficients are in the first poly?: 3
What are the coefficients? (Lowest power first): 3 2 1
How many coefficients are in the second poly?: What are the coefficients? (Lowest power first): 3 + 0x^1
times
1 + 0x1 + 0x^2
-----
3 + 0x^1 + 0x^2 + 0x^3
I want it to output it like this:
How many coefficients are in the first poly?: 3
What are the coefficients? (Lowest power first): 3 2 1
How many coefficients are in the second poly? 3
What are the coefficients? (Lowest power first): 1 2 1
3 + 2x^1 + 1x^2
times
1 + 2x^1 + 1x^2
-----
3 + 8x^1 + 8x^2 + 4x^3 + 1x^4
you need to take the inputs in a loop.
here is how you can do it.
cout << "How many coefficients are in the first poly?: ";
cin >> co;
cout << "What are the coefficients? (Lowest power first): ";
for(int i=0;i<co;i++)
cin >> *(A+i);
cout << "How many coefficients are in the second poly?: ";
cin >>coo;
cout << "What are the coefficients? (Lowest power first): ";
for(int i=0;i<coo;i++)
cin >>*(B+i);
printPoly(A, coo);
cout << "\n";
cout << "times" << endl;
printPoly(B, co);
cout << "\n";
cout << "-----" << endl;
int *product = foil(A, B, co, coo);
printPoly(product, co+coo-1);
getch();
return 0;
Here is the output image
Related
#include <iostream>
using namespace std;
int main () {
int pemboking, kode_lap[8], durasi[8];
string nama[8], tanggal[8], jam[8];
cout << "\nMasukan jumlah pembooking : ";
cin >> pemboking;
cout << endl;
for (int i = 0; i < pemboking; i++) {
cout << "Transaksi ke " << i + 1 << endl;
cout << "Masukan Nama : ";
getline(cin, nama[i]);
cout << "Masukan Kode Lapangan : ";
cin >> kode_lap[i];
cout << "Masukan Tanggal Sewa : ";
cin >> tanggal[i];
cout << "Masukan Jam main : ";
getline(cin, jam[i]);
cout << "Masukan Durasi Jam Main : ";
cin >> durasi[i];
cout << endl;
cout << endl;
}
}
when I use cin.ignore, the error will go directly to the input with index 1, index 0 is missed. if you don't use cin ignore it just skips the input using getline.
so how should i use the code, for a space input from the user.
although not in the same way, I hope the code meets my expectation that it can ask the user to input spaces for string type
So I'm doing a program for a class, and I set up an if loop inside a function definition to set parameters for entries. I'm supposed to be taking inputs between 0 and 10 only. But it's only catching the numbers that are less than 0. It won't catch the numbers larger than 10.
int main()
{
float score1, score2, score3, score4, score5;
cout << endl;
cout << "Judge #1: " << endl;
getJudgeData(score1);
cout << "Judge #2: " << endl;
getJudgeData(score2);
cout << "Judge #3: " << endl;
getJudgeData(score3);
cout << "Score #4: " << endl;
getJudgeData(score4);
cout << "Score #5: " << endl;
getJudgeData(score5);
calcScore(score1, score2, score3, score4, score5);
return 0;
}
void getJudgeData (float &score)
{
cin >> score;
if(score < 0 || score > 10)
{
cout << "Error: Please enter a score between 0 and 10." << endl;
cin >> score;
}
}
Please change the if condition in your getJudgeData function into a while loop:
void getJudgeData (float &score)
{
cin >> score;
while (score < 0 || score > 10)
{
cout << "Error: Please enter a score between 0 and 10." << endl;
cin >> score;
}
}
Otherwise the condition will be only checked once, means for the first input of every judge. This isn't intended, if I understood your issue correctly.
Please find more information regarding the while loop here:
while
So I was doing a program where i need to find the total area of all floors, where the floors are determined by the user. I think I'm correct on the part to use the pointers, so to check if the code was correct I tried it doing it with basic addition. but even with basic addition it seems to have already some problems. I tried looking for similar questions in here and I can't find anything that might help me, so I hope you guys can help me. Thank you in advance.
float *Length=NULL, *Width=NULL, *Area=NULL, TotalArea, templ, tempw;
int floors, count;
cout << "Input the number of floors to proceed\n";
cout << ":";
cin >> floors;
Length = new float[floors];
Width = new float[floors];
Area = new float[floors];
for (int loop = 0; loop < floors; loop++)
{
cout << "\n\nFloor " << loop + 1 << endl;
cout << "Input the Length: \n";
cin >> templ;
cout << "Input the Width: \n";
cin >> tempw;
*(Length + loop) = templ;
*(Width + loop) = tempw;
*(Area + loop) = (*Length + loop) + (*Width + loop);
count = loop;
for (int count = 0; count < floors; count++)
{
TotalArea = TotalArea + *Area+count;
}
}
cout << TotalArea << endl;
I tried inputting the following:
floor:2
floor 1
length: 1
width: 1
floor 2
length: 1
width: 1
The answer should be 4, but the output ends up with 10.
You don't need arrays and pointers. Since you are looping through the floors and summing the areas of each floor, you can "forget" about previously encountered lengths, widths and areas, and only remember the total area encountered so far.
float length;
float width;
float area;
float totalArea;
int floors;
std::cout << "Input the number of floors to proceed\n";
std::cout << ":";
std::cin >> floors;
totalArea = 0;
for (int loop = 0; loop < floors; loop++)
{
std::cout << "\n\nFloor " << loop + 1 << std::endl;
std::cout << "Input the Length: " << std::endl;
std::cin >> length;
std::cout << "Input the Width: " << std::endl;
std::cin >> width;
area = length * width;
totalArea += area;
}
std::cout << totalArea << std::endl;
Notice how I added these annoying std:: everywhere? If you wonder why, see this other question: Why is “using namespace std;” considered bad practice?
I tried making some changes based on you guys comments and here is what I did.
There are some warnings I don't really know why but It seems to be working
float* Length = NULL, * Width = NULL, TotalArea, tempw, templ, * Area = NULL;
int floors, loop = 0;
cout << "Input the number of floors to proceed\n";
cout << ":";
cin >> floors;
for (int loop = 0; loop < floors; loop++)
{
Length = new float[floors];
Width = new float[floors];
Area = new float[floors];
cout << "\n\nFloor " << loop + 1 << endl;
cout << "Input the Length: \n";
cin >> templ;
cout << "Input the Width: \n";
cin >> tempw;
*(Length +loop) = l;
*(Width+loop) = w;
Area[floors] = (*(Length+loop)) * (*(Width+loop));
TotalArea += a[floors];
}
cout << TotalArea << endl;
This is what I came u with, it seems to be working, the output is also correct now.
The code below is in C++. How do I translate it to C?
void drawBoard()
{
system( "cls" );
cout << "SCORE: " << score << endl << endl;
for( int y = 0; y < 4; y++ )
{
cout << "+------+------+------+------+" << endl << "| ";
for( int x = 0; x < 4; x++ )
{
if( !board[x][y].val ) cout << setw( 4 ) << " ";
else cout << setw( 4 ) << board[x][y].val;
cout << " | ";
}
cout << endl;
}
cout << "+------+------+------+------+" << endl << endl;
}
The code is pretty much C compatible already. However, the couts are a C++ construct.
To make it fully C compatible, you could replace cout with printf. For instance, in your code,
cout << "SCORE: " << score << endl << endl; --> printf("SCORE: %d \n\n", score);
You'll have to play around with the different parameters to get the formatting and output right, but that's the general idea. A good reference is this site: Printf
Assuming val and score are int, the following lines:
cout << "SCORE: " << score << endl << endl;
cout << "+------+------+------+------+" << endl << "| ";
cout << setw( 4 ) << " ";
cout << setw( 4 ) << board[x][y].val;
would translate to:
printf("SCORE: %d\n\n", score);
printf("+------+------+------+------+\n| ";
printf(" ");
printf("%4d", board[x][y].val);
You can figure out the rest .
Trying to display # of each combo ordered and total price. Not sure why it won't store values in A, B, and C. Novice programmer here, so be easy. Been having the problem with if statements for a while, so obviously I'm doing the whole if statement thing incorrectly.
#include <iostream>
using namespace std;
int main( )
{
int group = 0;
char combo = ' ';
int A = 0;
int B = 0;
int C = 0;
double total = 0.0;
cout << "How many customers are in the group? ";
cin >> group;
for (int counter = 0; counter < group; counter = counter + 1)
{
cout << "Enter combo ordered: ";
cin >> combo;
if (combo = A)
{
A = A + 1;
cout << "Enter combo ordered: ";
cin >> combo;
}
else if (combo = B)
{
B = B + 1;
cout << "Enter combo ordered: ";
cin >> combo;
}
else if (combo = C)
{
C = C + 1;
cout << "Enter combo ordered: ";
cin >> combo;
}
total = A*6 + B*6.25 + C*5.75;
}
cout << "# of Combo A ordered: " << A << endl;
cout << "# of Combo B ordered: " << B << endl;
cout << "# of Combo C ordered: " << C << endl;
cout << "Total price: $" << total << endl;
system("pause");
return 0;
}
For-loop should be for (int counter = 0; counter < group; counter++)
If statement should use == for equality. = is for assignment only.
Your if statement needs to quote the character you are comparing: if (combo == 'A') {. It is also possible that you'll need to access combo as an array of characters, like so: if (combo[0] == 'A') {
I think you may need to tweak just a few things; a few compilers don't like it when you compute a double using int and there is no reason to not use double here since the program is small. Also a few syntax errors (i.e. with = instead of ==). Have you tried displaying your output in an isolated way? Something like:
main(){
double A = 1;
double B = 2;
double C = 3;
double total = A*6 + B*6.25 + C*5.75;
cout << "# of Combo A ordered: " << A << endl;
cout << "# of Combo B ordered: " << B << endl;
cout << "# of Combo C ordered: " << C << endl;
cout << "Total price: $" << total << endl;
system("pause");
return 0;
}
Your corrected code:
#include <iostream>
using namespace std;
int main( )
{
int group = 0;
char combo = ' ';
double A = 0;
double B = 0;
double C = 0;
double total = 0.0;
cout << "How many customers are in the group? ";
cin >> group;
for (int counter = 0; counter < group; counter++)
{
cout << "Enter combo ordered: ";
cin >> combo;
if (combo == 'A')
{
A++;
}
else if (combo == 'B')
{
B++;
}
else if (combo == 'C')
{
C++;
}
cout << "Enter combo ordered: ";
cin >> combo;
}
total = A*6 + B*6.25 + C*5.75;
cout << "# of Combo A ordered: " << A << endl;
cout << "# of Combo B ordered: " << B << endl;
cout << "# of Combo C ordered: " << C << endl;
cout << "Total price: $" << total << endl;
system("pause");
return 0;
}
I would also display your value for group to make sure that the if loop is even running at least once. There are a few fault points here that I would test individually.
EDIT:
Maybe test this:
#include <iostream>
using namespace std;
int main( )
{
int group = 0;
cout << "How many customers are in the group? ";
cin >> group;
for (int counter = 0; counter < group; counter++)
{
cout << "Test success";
}
to see if you are even entering into your for loop.