Best approach to merge three distinct TSQL select statments - sql-server

Question

I'm looking to return one tsql statement, that contains four fields, from three separate, unrelated tables.
One table contains a list of objects, say fruits, and for each fruit, I want a sell buy date and best before date.
First statement would therefore look something like:
select fruit from fruit table -- this returns multiple rows
Second statement would look something like:
select sellbuyDate from sellTable -- this returns a single row
and the third would look something like:
select bestbefore from bestTable -- this returns a single row
Don't get to hung up on the table names. I'm working on a legacy system, that we cant change, so need to combine the three table into one.
The underlining table needs to have all the fields returned in a single row, with the second and third results applied to the first statement.
Apples | 12-12-2008 | 12-12-2009
Pears | 12-12-2008 | 12-12-2009
I've implemented the following temp table:
CREATE TABLE #Fruits
(
Fruit VARCHAR(100),
SellBuyDate DATETIME,
BestBefore DATETIME
)
INSERT INTO #Fruits
SELECT Fruit from fruit
INSERT INTO #Fruits
SELECT sellbuyDate from sellTable
INSERT INTO #Fruits
SELECT bestbefore from bestable
SELECT * from #Fruits
This throws an error, because each insert doesn't contain the three fields specified.
any other suggestions would be well received.

Answer 1

You can select them all together by doing a CROSS JOIN by not specifying any join criteria between the three tables as follows:
CREATE TABLE fruit ( fruit_name VARCHAR(30) );
CREATE TABLE sellTable ( sellByDate DATETIME );
CREATE TABLE bestTable ( bestBefore DATETIME );
CREATE TABLE allFruits
(
fruit_name VARCHAR(30),
sellByDate DATETIME,
bestBefore DATETIME
);
INSERT INTO fruit (fruit_name)
VALUES ('apple'), ('pear');
INSERT INTO sellTable(sellByDate)
VALUES ('12/05/2012');
INSERT INTO bestTable(bestBefore)
VALUES ('12/12/2012');
INSERT INTO allFruits (fruit_name, bestBefore, sellByDate)
SELECT f.fruit_name, b.bestBefore, s.sellByDate
FROM fruit f, bestTable b, sellTable s;
SELECT *
FROM allFruits;

Answer 2

maybe you are looking for this answer, although your question could be a little clearer on what that would accomplish
INSERT INTO #Fruits(fruit)
SELECT Fruit from fruit
INSERT INTO #Fruits(sellbuyDate)
SELECT sellbuyDate from sellTable
INSERT INTO #Fruits(bestbefore)
SELECT bestbefore from bestable
SELECT * from #Fruits
the other possible solution is
insert into #Fruits
select Fruit, sellbuyDate, bestbefore from fruit
cross join sellTable
cross join bestable

Answer 3

May be you need this.
SELECT FRUIT,
(SELECT SELLBUYDATE FROM SELLTABLE) AS SELLBUYDATE,
(SELECT BESTBEFORE FROM BESTTABLE) AS BESTBEFORE
FROM FRUIT
or
SELECT FRUIT.FRUIT
, SELLTABLE.SELLBUYDATE
, BESTTABLE.BESTBEFORE
FROM FRUIT
INNER JOIN SELLTABLE ON 1=1
INNER JOIN BESTTABLE ON 1=1

Answer 4

Without the schema of the 3 tables. I would guess its one of the following.
CREATE TABLE #Fruits
(
Fruit VARCHAR(100),
SellBuyDate DATETIME,
BestBefore DATETIME
)
INSERT INTO #Fruits(Fruit,SellBuyDate,BestBefore)
Select Fruit, Sellbuydate,bestbefore
from fruit,selltable,bestable
Or if your tables are set up properly
INSERT INTO #Fruits(Fruit,SellBuyDate,BestBefore)
Select Fruit, Sellbuydate,bestbefore
from fruit f
inner join selltable s
on f.pkey = s.fkey
inner join bestable b
on f.pkey = b.fkey