Creating File in arduino's Memory while arduino is operating - file

In my arduino project i have to store some integers(25 to be specific) in a file in arduino's memory (as i have arduino UNO and it doesn't have built-in port for SD Card) and read that file next-time i start the arduino .
Also my arduino is not connected to PC or laptop so i can't use file system of PC or laptop
so is there any way possible doing it ?

Arduino Uno has 1KB of non-volatile EEPROM memory, which you can use for this purpose. An integer is 2 bytes, so you should be able to store over 500 ints this way.
This example sketch should write a couple of integers from 10 to 5 into EEPROM memory:
#include <EEPROM.h>
void setup() {
int address = 0; //Location we want the data to be put.
for (int value = 10; value >= 5; --value)
{
// Write the int at address
EEPROM.put(eeAddress, value)
// Move the address, so the next value will be written after the first.
address += sizeof(int);
}
}
void loop() {
}
This example is a stripped down version of the one in the EEPROM.put documentation. Other examples can be found in the documentation of the various EEPROM functions.
Another nice tutorial on the subject can be found on tronixstuff.
By the way, if you need more memory, you could also use EEPROM memory banks. These are small ICs. They are available for very low prices in low amounts of memory, typically from 1KB to 256KB. Not much in terms of modern computing, but a huge expansion compared to the 1KB you have by default.

Related

Understanding the writing to flash process in the STM32 reference manual

I am programming the stm32l412kb where at one point I will be writing data to flash (from UART). From the stm32l41xx reference manual, I understand the steps in how to clear the memory before writing to it but on page 84 there is one step that I do not know how to do when writing the actual data. That step is the
Perform the data write operation at the desired memory address
What data write operation is it mentioning? I can't see any register the memory address goes to so I assume its going to use pointers? How would I go about doing this?
Your help is much appreciated,
Many thanks,
Harry
Apart from a couple of things (e.g. only write after erase, timings, alignment, lock/unlock) their ain't much difference between writing to RAM and writing to FLASH memory. So if you have followed the steps from the reference manual and the FLASH memory is ready (i.e. cleared and unlocked) then you can simply take an aligned memory address and write to it.
STMs very own HAL library contains a function which does all the cumbersome boilerplate for you and allows you to "just write":
HAL_StatusTypeDef HAL_FLASH_Program(uint32_t TypeProgram, uint32_t Address, uint64_t Data)
Internally this function uses a subroutine which performs the actual write and it looks like this:
static void FLASH_Program_DoubleWord(uint32_t Address, uint64_t Data)
{
/* Check the parameters */
assert_param(IS_FLASH_PROGRAM_ADDRESS(Address));
/* Set PG bit */
SET_BIT(FLASH->CR, FLASH_CR_PG);
/* Program first word */
*(__IO uint32_t*)Address = (uint32_t)Data;
/* Barrier to ensure programming is performed in 2 steps, in right order
(independently of compiler optimization behavior) */
__ISB();
/* Program second word */
*(__IO uint32_t*)(Address+4U) = (uint32_t)(Data >> 32);
}
As you can see there is no magic involved. It's just a dereferenced pointer and an assignment.
What data write operation is it mentioning?
The "data write" is just a normal write to a address in memory that is the flash memory. It is usually the STR assembly instruction. Screening at your datasheet, I guess the flash memory addresses are between 0x08080000 and 0x00080000.
Ex. the following C code would write the value 42 to the first flash memory address:
*(volatile uint32_t*)0x00080000 = 42.
For a reference implementation you can see stm32 hal drivers:
/* Set PG bit */
SET_BIT(FLASH->CR, FLASH_CR_PG);
/* Program the double word */
*(__IO uint32_t*)Address = (uint32_t)Data;
*(__IO uint32_t*)(Address+4) = (uint32_t)(Data >> 32);

Does Arduino Uno/OSEPP Uno have enough memory to create a servo array?

I'm pretty bad at coding (I know the basics), and I'm trying to create an array of servos in Arduino to control via Serial with Processing. I vaguely remember something about Arduino microcontrollers having really limited memory, so I'm not sure if creating an array of Servo objects would work. Here's the code I have so far:
#include <Servo.h>
Servo[] servos = new Servo[6]; //holds the servo objects
int[] servoPos = {90,112,149,45,75,8}; //holds the current position of each servo
char serialVal; //store the serialValue received from serial
void setup()
{
for(int i = 0; i < servos.length; i++) //attach servos to pins
{
servos[i].attach(i+8);
}
Serial.begin(115200); //initialize serial
}
Would an Arduino Uno board be able to support this array and utilize it like in Java? Before now, I've been creating each object separately, which was very inefficient and time-consuming to type and read.
Also, if there's anything that would stop this code from executing, please tell me. I appreciate your help.
My advice is to fire up your Arduino IDE and give it a try. First off you're going to find that you have some problems in your code:
Your array syntax is incorrect. For example:
int[] servoPos = {90,112,149,45,75,8}; //holds the current position of each servo
should be written:
int servoPos[] = {90,112,149,45,75,8}; //holds the current position of each servo
I guess this servos.length is a Java thing? Instead you should determine that value by:
sizeof(servos) / sizeof(servos[0])
After you get it to compile you'll see a message in the black console window at the bottom of the Arduino IDE window:
Sketch uses 2408 bytes (7%) of program storage space. Maximum is 32256 bytes.
Global variables use 242 bytes (11%) of dynamic memory, leaving 1806 bytes for local variables. Maximum is 2048 bytes.
So that will give you some idea of the memory usage. To check free memory at run time I use this library:
https://github.com/McNeight/MemoryFree

C - Store global variables in flash?

As the title may suggest, I'm currently short on SRAM in my program and I can't find a way to reduce my global variables. Is it possible to bring global variables over to flash memory? Since these variables are frequently read and written, would it be bad for the nand flash because they have limited number of read/write cycle?
If the flash cannot handle this, would EEPROM be a good alternative?
EDIT:
Sorry for the ambiguity guys. I'm working with Atmel AVR ATmega32HVB which has:
2K bytes of SRAM,
1K bytes of EEPROM
32K bytes of FLASH
Compiler: AVR C/C++
Platform: IAR Embedded AVR
The global variables that I want to get rid of are:
uint32_t capacityInCCAccumulated[TOTAL_CELL];
and
int32_t AccumulatedCCADCvalue[TOTAL_CELL];
Code snippets:
int32_t AccumulatedCCADCvalue[TOTAL_CELL];
void CCGASG_AccumulateCCADCMeasurements(int32_t ccadcMeasurement, uint16_t slowRCperiod)
{
uint8_t cellIndex;
// Sampling period dependant on configuration of CCADC sampling..
int32_t temp = ccadcMeasurement * (int32_t)slowRCperiod;
bool polChange = false;
if(temp < 0) {
temp = -temp;
polChange = true;
}
// Add 0.5*divisor to get proper rounding
temp += (1<<(CCGASG_ACC_SCALING-1));
temp >>= CCGASG_ACC_SCALING;
if(polChange) {
temp = -temp;
}
for (cellIndex = 0; cellIndex < TOTAL_CELL; cellIndex++)
{
AccumulatedCCADCvalue[cellIndex] += temp;
}
// If it was a charge, update the charge cycle counter
if(ccadcMeasurement <= 0) {
// If it was a discharge, AccumulatedCADCvalue can be negative, and that
// is "impossible", so set it to zero
for (cellIndex = 0; cellIndex < TOTAL_CELL; cellIndex++)
{
if(AccumulatedCCADCvalue[cellIndex] < 0)
{
AccumulatedCCADCvalue[cellIndex] = 0;
}
}
}
}
And this
uint32_t capacityInCCAccumulated[TOTAL_CELL];
void BATTPARAM_InitSramParameters() {
uint8_t cellIndex;
// Active current threshold in ticks
battParams_sram.activeCurrentThresholdInTicks = (uint16_t) BATTCUR_mA2Ticks(battParams.activeCurrentThreshold);
for (cellIndex = 0; cellIndex < TOTAL_CELL; cellIndex++)
{
// Full charge capacity in CC accumulated
battParams_sram.capacityInCCAccumulated[cellIndex] = (uint32_t) CCGASG_mAh2Acc(battParams.fullChargeCapacity);
}
// Terminate discharge limit in CC accumulated
battParams_sram.terminateDischargeLimit = CCGASG_mAh2Acc(battParams.terminateDischargeLimit);
// Values for remaining capacity calibration
GASG_CalculateRemainingCapacityValues();
}
would it be bad for the nand flash because they have limited number of
read/write cycle?
Yes it's not a good idea to use flash for frequent modification of data.
Read only from flash does not reduce the life time of flash. Erasing and writing will reduce the flash lifetime.
Reading and writing from flash is substantially slower compared to conventional memory.
To write a byte whole block has to be erased and re written in flash.
Any kind of Flash is a bad idea to be used for frequently changing values:
limited number of erase/write cycles, see datasheet.
very slow erase/write (erase can be ~1s), see datasheet.
You need a special sequence to erase then write (no language support).
While erasing or writing accesses to Flash are blocked at best, some require not to access the Flash at all (undefined behaviour).
Flash cells cannot freely be written per-byte/word. Most have to be written per page (e.g. 64 bytes) and erased most times in much larger units (segments/blocks/sectors).
For NAND Flash, endurance is even more reduced compared to NOR Flash and the cells are less reliable (bits might flip occasionally or are defective), so you have to add error detection and correction. This is very likely a direction you should not go.
True EEPROM shares most issues, but they might be written byte/word-wise (internal erase).
Note that modern MCU-integrated "EEPROM" is most times also Flash. Some implementations just use slightly more reliable cells (about one decade more erase/write cycles than the program flash) and additional hardware allowing arbitrary byte/word write (automatic erase). But that is still not sufficient for frequent changes.
However, you first should verify if your application can tolerate the lengthly write/erase times. Can you accept a process blocking that long, or rewrite your program acordingly? If the answer is "no", you should even stop further investigation into that direction. Otherwise you should calculate the number of updates over the expected lifetime and compare to the information in the datasheet. There are also methods to reduce the number of erase cycles, but the leads too far.
If an external device (I2C/SPI) is an option, you could use a serial SRAM. Although the better (and likely cheaper) approach would be a larger MCU or think about a more efficient (i.e. less RAM, more code) way to store the data in SRAM.

CPU write value passed from application to qemu is strange

I was trying to run RTEMS(a real-time OS) application on a sparc virtual machine using QEMU.
I'm almost there and I've seen it working hours ago. But after removing some prints it is not working and later I found it's not because of the removed prints. The data is not being passed correctly between the RTEMS image and the QEMU emulation model.(I'm working with QEMU version 1.5.50 and lan9118.c model borrowed from QEMU version 2.0.0. I modifed lan9118 a little.)
In the QEMU model, the memory region ops are defined as
struct MemoryRegionOps {
/* Read from the memory region. #addr is relative to #mr; #size is
* in bytes. */
uint64_t (*read)(void *opaque,
hwaddr addr,
unsigned size);
/* Write to the memory region. #addr is relative to #mr; #size is
* in bytes. */
void (*write)(void *opaque,
hwaddr addr,
uint64_t data,
unsigned size);
...
}
and in the RTEMS application, I write to the device like
*TX_FIFO_PORT = cmdA;
*TX_FIFO_PORT = cmdB;
where TX_FIFO_PORT is defined as below.
#define TX_FIFO_PORT (volatile ulong *)(SMSC9118_BASE + 0x20)
But when I write, for example,
cmdA : 0x2a300200 and cmdB : 0x2a002a00,
The values I expected are
cmdA : 0x0002302a and cmdB : 0x002a002a. (Just endian converted values)
But the values I see at the write function (entrance of QEMU) are
cmdA : 0x02000200 and cmdB : 0x2a002a00 respectively.
The observed values have not been endian converted and even the first value is different(lower 16 bit repeated).
What could be problem?
Any hint will be deeply appreciated.
Strangely I fixed this by commenting out the endian conversion for cmdA and cmdB in the RTEMS before writing to the device.(It was ok with the endian conversion..I don't know) So it's working 'almost'.
Anyway, here is a tip about exchaning CPU write/read data in QEMU processor and deivce.
In QEMU, Each device model provides write and read function, also it specifies how the word should be transferd to/from the device regarding endianness. It is specified like below.
static const MemoryRegionOps lan9118_mem_ops = {
.read = lan9118_readl,
.write = lan9118_writel,
.endianness = DEVICE_NATIVE_ENDIAN,
};
Here is the copy from email I received from Peter Maydell from qemu-discuss#nongnu.org mailing list.
------------------------
This depends on what the MemoryRegionOps struct for the memory region sets its .endianness field to.
DEVICE_NATIVE_ENDIAN means the device sees values the same way round as the guest CPU's native endianness[*], so if the guest does a 32 bit write of 0x12345678 then it appears in the write function's argument as 0x12345678. DEVICE_BIG_ENDIAN means that if the CPU is little endian then the word will be byteswapped.
DEVICE_LITTLE_ENDIAN means that if the CPU is big endian then the word will be byteswapped. The latter are useful for devices or buses which have a specific endianness which is not the same as that of the CPU (eg PCI is always little endian).

How can I deal with given situtaion related to Hardware change

I am maintaining a Production code related to FPGA device .Earlier resisters on FPGA are of 32 bits and read/write to these registers are working fine.But Hardware is changed and so did the FPGA device and with latest version of FPGA device we have trouble in read and write to FPGA register .After some R&D we came to know FPGA registers are no longer 32 bit ,it is now 31 bit registers and same has been claimed by FPGA device vendor.
So there is need to change small code as well.Earlier we were checking that address of registers are 4 byte aligned or not(because registers are of 32 bits)now with current scenario we have to check address are 31 bit aligned.So for the same we are going to check
if the most significant bit of the address is set (which means it is not a valid 31 bit).
I guess we are ok here.
Now second scenario is bit tricky for me.
if read/write for multiple registers that is going to go over the 0x7fff-fffc (which is the maximum address in 31 bit scheme) boundary, then have to handle request carefully.
Reading and Writing for multiple register takes length as an argument which is nothing but number of register to be read or write.
For example, if the read starts with 0x7fff-fff8, and length for the read is 5. Then actually, we can only read 2 registers (which is 0x7fff-fff8, and 0x7fff-fffc).
Now could somebody suggest me some kind of pseudo code to handle this scenario
Some think like below
while(lenght>1)
{
if(!(address<<(lenght*31) <= 0x7fff-fffc))
{
length--;
}
}
I know it is not good enough but something in same line which I can use.
EDIT
I have come up with a piece of code which may fulfill my requirement
int count;
Index_addr=addr;
while(Index_add <= 7ffffffc)
{
/*Wanted to move register address to next register address,each register is 31 bit wide and are at consecutive location. like 0x0,0x4 and 0x8 etc.*/
Index_add=addr<<1; // Guess I am doing wrong here ,would anyone correct it.
count++;
}
length=count;
The root problem seems to be that the program is not properly treating the FPGA registers.
Data encapsulation would help, and, instead of treating the 31-bit FPGA registers as memory locations, they should be abstracted.
The FPGA should be treated as a vector (a one-dimensional array) of registers.
The vector of N FPGA registers should be addressable by an register index in the range of 0x0000 through N-1.
The FPGA registers are memory mapped at base addr.
So the memory address = 4 * FPGA register index + base addr.
Access to the FPGA registers should be encapsulated by read and write procedures:
int read_fpga_reg(int reg_index, uint32_t *reg_valp)
{
if (reg_index < 0 || reg_index >= MAX_REG_INDEX)
return -1; /* error return */
*reg_valp = *(uint32_t *)(reg_index << 2 + fpga_base_addr);
return 0;
}
As long as MAX_REG_INDEX and fpga_base_addr are properly defined, then this code will never generate an invalid memory access.
I'm not absolutely sure I'm interpreting the given scenario correctly. But here's a shot at it:
// Assuming "address" starts 4-byte aligned and is just defined as an integer
unsigned uint32_t address; // (Assuming 32-bit unsigned longs)
while ( length > 0 ) // length is in bytes
{
// READ 4-byte value at "address"
// Mask the read value with 0x7FFFFFFF since there are 31 valid bits
// 32 bits (4 bytes) have been read
if ( (--length > 0) && (address < 0x7ffffffc) )
address += 4;
}

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