Giving users a certain amount of tries until program exits - arrays

Question

I'm creating a method where the user puts in a "PIN" number to access different methods.. Yes it's an ATM..
I'm trying to figure out how to make it so that the user gets a specific amount of tries until the program exit's..
After a bunch of research I haven't very well found anything useful.. The only thing I've found is to use .to_s.split(//) in order to add the number of the try into an empty array. Which doesn't make sense to me because why would you make an integer into a string..?
So my question is, how do you make it so that users only have a certain amount of tries, 3, until they get kicked out of the program?
Main source:
#!/usr/bin/env ruby
################
#ATM Rewrite
#
#Creator Lost Bam Not completed yet.
#
#11/19/15
##################
require_relative 'checking.rb'
require_relative 'savings.rb'
require_relative 'exit.rb'
require_relative 'loan.rb'
require_relative 'transfer.rb'
require_relative 'redirect.rb'
class ATM
attr_accessor :name, :checking_account, :savings_account, :pin_number, :transfer, :loan
def initialize( name, checking_account, savings_account )
#name = name
#checking_account = checking_account
#savings_account = savings_account
#pin_number = pin_number
end
end
##############
def pin
x = []
puts "Enter PIN Number:"
input = gets.chomp.to_i
if input == 1234
menu
else
x += 1.to_s.split(//) #<= This is what I found to convert integer to Array
puts "Invalid PIN, try again:"
input = gets.chomp
if x == 3
bad_pin
end
end
end
############
def menu #add #{name} on line 41
puts <<-END.gsub(/^\s*>/, ' ')
>
>Welcome thank you for choosing Bank of Bam.
>You may choose from the list below of what you would like to do
>For checking inquiries press '1'
>For savings account information press '2'
>To transfer funds press '3'
>To either apply for a loan, or get information on a loan press '4'
>To exit the system press '5'
>
END
input = gets.chomp
case input.to_i
when 1
checking_information
when 2
savings_information
when 3
transfer_funds
when 4
loan_info
when 5
exit_screen
else
puts "Invalid option please try again"
menu
end
end
def bad_pin
abort('Invalid PIN exiting sytem..')
exit
end
pin
Tried something new:
def pin
x = 3
puts "Enter PIN(#{x} attempts left):"
pin_num = gets.chomp
case pin_num.to_i
when 1234
menu
else
puts "Invalid PIN"
x -=1
return pin
if x == 0
bad_pin
end
end
end
It doesn't increment the number down it just keeps saying 3 tries left:
Enter PIN(3 attempts left):
4567
Invalid PIN
Enter PIN(3 attempts left):
45345
Invalid PIN
Enter PIN(3 attempts left):
6456
Invalid PIN
Enter PIN(3 attempts left):
4564
Invalid PIN

Answer 1

Your problem is that every time you recall the method the value of x resets again. You need to have a loop inside the pin method that'll keep track of attempts.
def pin
x = 3
while (x > 0) do
puts "Enter PIN(#{x} attempts left):"
pin_num = gets.chomp
case pin_num.to_i
when 1234
menu
else
puts "Invalid PIN"
x -=1
puts "no tries left" if x == 0
break if x == 0
end
end
end
Stay in the method. Recalling the method starts you back at three attempts.