I am new to Sikuli. I am Automating a web application that have option to upload a file.
When I click on upload button it opens a popup window.In that window I have to select a file. How I can do it using sikuli.
I am using linux operating system so I can't use AutoIT.
Below is my code which I am trying
public static void imageClick()
{
Screen s= new Screen();
try {
s.capture();
s.find("Desktop.png");
s.click("Desktop.png",0);
System.out.println("Desktop is selected");
} catch (FindFailed e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
Desktop.png is a image file which I kept in my project. first I am searching it then clicking on it.
Anyone can help me how I can achieve this. Any help will be highly appreciated.
Finally I done in in below way
First import sikuli jar file to your project
Capture the Image where you want to click and save it to some location
for Ex. /home/dev/Desktop/abc.png
Screen s = new Screen(); //Created the Object of screen class
s.click("/home/dev/Desktop/abc.png");
public static void imageClick()
{
Screen s= new Screen();
Pattern DesktpIcon = new Pattern("Desktop.png");
s.click(DesktpIcon);
System.out.println("Desktop is Clicked.");
}
Related
I need to upload a document via Selenium WebDriver using Chromedriver. I have tried all the Action class and JavaScript stuff, but those do not work. I am assuming they do not work because those are relying on the button to be an input field, however, the upload button I'm dealing with is not. It's HTML looks like this:
Steps to reproduce:
Go to: https://www.fedex.com/apps/printonline/#!
Click on View Products under Marketing Material
Click on Get Started under Brochure
Click on Use your File to upload the file
Use Your File
I am able to click the use your file button, but I am not sure how I can upload the file.
driver.get("https://www.fedex.com/apps/printonline/#!");
driver.manage().window().maximize();
driver.manage().deleteAllCookies();
driver.manage().timeouts().pageLoadTimeout(40, TimeUnit.SECONDS);
driver.manage().timeouts().implicitlyWait(30,TimeUnit.SECONDS);
//Thread.sleep(6000);
if (driver.findElement(By.xpath("//area[#alt='close']")) != null) {
driver.findElement(By.xpath("//area[#alt='close']")).click();
}
driver.findElement(By.xpath("//a[#title='Marketing Materials']/child::button")).click();
Thread.sleep(1000);
driver.findElement(By.xpath("//a[#title='Get Started - Brochures']")).click();
Thread.sleep(1000);
WebElement element = driver.findElement(By.xpath("//*[#class='btn fxg-btn-orange mycomputer-upload-link']"));
((JavascriptExecutor)driver).executeScript("arguments[0].click()", element);
Ok so first of all get rid of those Thread.sleep(), use fluent wait with polling time, preferably as a function to locate the elements:
private WebElement waitFor(By locator) {
int timeout = 10;
FluentWait<WebDriver> wait = new FluentWait<>(driver)
.pollingEvery(Duration.ofMillis(200))
.withTimeout(Duration.ofSeconds(timeout))
.ignoring(NoSuchElementException.class);
return wait.until((driver) -> driver.findElement(locator));
}
Then you can click the buttons and upload the file like this:
waitFor(By.cssSelector("button.view-products")).click();
waitFor(By.cssSelector("a.get-started")).click();
waitFor(By.cssSelector("a.get-started")).click();
waitFor(By.cssSelector("input.file-upload")).sendKeys("path_to_my_file");
Notice I am using the input element to upload the file - I am not clicking the a link, as you do not need to do that. Just send the path directly to the input element.
I'm trying to generate qrcode code in my application with qrgen and then saved in specific file but there is a problem in the libary 'java.io.FileOutputStream' where it can not be found. i want to know how to replace the libary and if there is another way to generate qrcode please share it with me
ByteArrayOutputStream out =QRCode.from(s).to(ImageType.PNG).stream();
try {
FileOutputStream fout = new FileOutputStream(new File(
"C:\\Users\\Public\\Pictures\\Sample Pictures\\QR_Code.JPG"));
fout.write(out.toByteArray());
fout.flush();
fout.close();
} catch (Exception e) {
// Do Logging
}
That isn't supported. Mobile devices don't have a file system in the way desktops have so this logic just won't work. There is a file system but it's to a large part private to the application, see: https://www.codenameone.com/manual/files-storage-networking.html
I am trying to take screenshot of sub menu which happens on hovering in selenium using TakesScreenshot. But this is not working. Screenshot is taken but sub menu is not present in the image.
I have also tried using implicit wait after hover, but nothing worked.
Please suggest a method to capture screenshot of the sub menu.
contactUs.hoverHM();
screenshot = ((TakesScreenshot) PageFactoryBase.getSharedWebDriver()).getScreenshotAs(OutputType.BYTES);
scenario.embed(screenshot, "image/png");
This did the trick for me. I am pretty sure it will work for you.
_driver = new FirefoxDriver();
_driver.Navigate().GoToUrl("http://www.w3schools.com/jquery/tryit.asp?filename=tryjquery_event_mouseover_mouseout");
_driver.SwitchTo().Frame(_driver.FindElement(By.Id("iframeResult")));
Actions builder = new Actions(_driver);
builder.MoveToElement(_driver.FindElement(By.TagName("p"))).Build().Perform();
var screenshot = ((ITakesScreenshot)_driver).GetScreenshot();
var filename = new StringBuilder("D:\\");
filename.Append(DateTime.Now.ToString("HH_mm_ss dd-MM-yyyy" + " "));
filename.Append("test");
filename.Append(".png");
screenshot.SaveAsFile(filename.ToString(), System.Drawing.Imaging.ImageFormat.Png);
After hovering mouse on the text, it turns yellow and below is the screen shot that I took.
Below is another approach where you can use 'Print screen' Key in your Test code and get the image from the clipboard in the system.
What is have done is used KeyEvent 'PRTSC' to get the Image into the system clipboard and then get the system clipboard to write it to a file. I hope it will also copy the mouseover.
Robot rob = new Robot();
rob.keyPress(KeyEvent.VK_PRINTSCREEN);
Clipboard clip = Toolkit.getDefaultToolkit().getSystemClipboard();
Transferable content = clip.getContents(null);
BufferedImage img = (BufferedImage)content.getTransferData(DataFlavor.imageFlavor);
ImageIO.write(img, "png", new File("D:\\test.png"));
I have tried the same scenario but for clickAndHold for hover skin. It worked for me with the help of Actions as below:
WebElement elm = driver.findElement(By.id("btn1"));
Actions builder = new Actions(driver);
Action act = builder.clickAndHold(elm).build();
act.perform();
try {
File scrFile = ((TakesScreenshot)driver).getScreenshotAs(OutputType.FILE);
FileUtils.copyFile(scrFile, new File("c:\\Img\\screenshot.png"));
} catch (IOException e) {
e.printStackTrace();
}
act = builder.release(elm).build();
act.perform();
You can instead replace clickAndHold with moveToElement Mouse hover the element. take the screenshot then release the element or move away from it.
Thanks everyone for answering on this thread.
I am able to take screenshot using robot as suggested by Vivek.
builder.moveToElement(getSharedWebDriver().findElement(By.xpath("//div[#class='brand section']/ul/li[#class='active hasflyout']"))).perform();
Robot robot = new Robot();
Point point;
point = getSharedWebDriver().findElement(By.xpath("//div[#class='brand section']/ul/li[#class='active hasflyout']")).getLocation();
int x = point.getX();
int y = point.getY();
robot.mouseMove(x,y);
In ideal case, either perform() or mouseMove() should be used. But somehow in my case, i had to use both the functions.
I need to export a .property file when user clicks on a hyperlink. I am using liferay portal 6.1.1. When user clicks on hyperlink, I am making a jquery.get() to the serveResource method which is inside the MyMVCPortlet class. Here the code that always writes the content to response(verified on fiddler) but is not creating a downloadable file.
resourceResponse.reset();
resourceResponse.setContentType("text/plain");
resourceResponse.setProperty("content-disposition", "attachment; filename=test.txt");
OutputStream out = resourceResponse.getPortletOutputStream();
try {
out.write("key=value".getBytes());
}
catch(IOException e){
e.printStackTrace();
}
finally {
out.close();//Also tried out.flush(); - dint help
}
Do I need to set something on resourceResponse after the write is complete?
I tried different options and got exhausted. The same code on plain java servlet works but not on liferay. Is there anything I am missing? Thanks in advance!
Try to use one of PortletResponseUtil.sendFile() instead of manual operations on portletOutputStream. Eg.
PortletResponseUtil.sendFile(resourceRequest, resourceResponse, "test.txt", "key=value".getBytes())
I have a set of Image elements that I use to download pictures. All the pictures have to be downloaded, but I wish to download the picture the user is looking at in the first place. If the user changes the viewed picture, I wish to cancel the downloads in progress to get the viewed picture as fast as possible.
To start a download I write: myImage.Source = new BitmapImage(theUri);.
How should I cancel it?
myImage.Source = null; ?
act on the BitmapImage ?
a better solution ?
I don't wish to download the picture by code to keep the benefit of the browser cache.
This is definitely doable -- I just tested it to make sure. Here is a quick class you can try:
public partial class Page : UserControl
{
private WebClient m_oWC;
public Page()
{
InitializeComponent();
m_oWC = new WebClient();
m_oWC.OpenReadCompleted += new OpenReadCompletedEventHandler(m_oWC_OpenReadCompleted);
}
void StartDownload(string sImageURL)
{
if (m_oWC.IsBusy)
{
m_oWC.CancelAsync();
}
m_oWC.OpenReadAsync(new Uri(sImageURL));
}
void m_oWC_OpenReadCompleted(object sender, OpenReadCompletedEventArgs e)
{
BitmapImage oBMI = new BitmapImage();
oBMI.SetSource(e.Result);
imgMain.Source = oBMI;
}
}
This works just like you wanted (I tested it). Everytime you call StartDownload with the URL of an image (presumably whenever a user clicks to the next image) if there is a current download in progress it is canceled. The broswer cache is also definitely being used (I verified with fiddler), so cached images are loaded ~ instantly.