Sum one column and subtract over second column - sql-server

Question

I want to display the subtraction of two columns. From the first column I need to get sum all value and substract with each value from the second column.
This is the table structure:
id | name | col1 | col2 | date
------------------------------------
432| xxx | 0 | 15 |2015-11-17
432| yyy | 10 | 30 |2015-11-19
432| zzz | 60 | 40 |2015-11-20
433| aaa | 0 | 60 |2015-11-17
433| bbb | 80 | 20 |2015-11-19
433| ccc | 60 | 10 |2015-11-20
Formula should go:
sum(col1) = 70 =>>> WHERE ID = 432
70 - col2 col3
-------------------------
=> 70 - 15 = 55
=> 70 - (30 + 15) = 25
=> 70 - (40 + 45) = -15
---------------------------
sum(col1) = 140 ===>> WHERE ID = 433
140 - col2 col3
-------------------------
=> 140 - 60 = 80
=> 140 - (60 + 20) = 60
=> 140 - (10 + 80) = 50
result is col3 and Output should be like as
id | name | col1 | col2 | col3 | date
-------------------------------------------
432| xxx | 0 | 15 | 55 | 2015-11-17
432| yyy | 10 | 30 | 25 | 2015-11-19
432| zzz | 60 | 40 | -15 | 2015-11-20
433| aaa | 0 | 60 | 80 | 2015-11-17
433| bbb | 80 | 20 | 60 | 2015-11-19
433| ccc | 60 | 10 | 50 | 2015-11-20
EDIT: What if I need the values ​​vary depending on the group as a 432 and 433 id column.

Answer 1

Schema Info
DECLARE #TEST TABLE
(
id INT,
name VARCHAR(10),
col1 INT,
col2 int
)
INSERT INTO #TEST VALUES
(432,'xxx',0, 15 ),
(432,'yyy',10, 30 ),
(432,'zzz',60, 40 ),
(433,'aaa',0, 60 ),
(433,'bbb',80, 20 ),
(433,'ccc',60, 10 )
Query
SELECT T.id ,
T.name ,
T.col1 ,
T.col2 ,
SUM(T.col1) OVER( PARTITION BY T.id ORDER BY T.id ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING)
- SUM(T.col2) OVER ( PARTITION BY T.id ORDER BY T.id ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW ) AS col3
FROM #TEST T;
Results
id | name | col1 | col2 | col3 |
---------------------------------
432 | xxx | 0 | 15 | 55 |
432 | yyy | 10 | 30 | 25 |
432 | zzz | 60 | 40 | -15 |
433 | aaa | 0 | 60 | 80 |
433 | bbb | 80 | 20 | 60 |
433 | ccc | 60 | 10 | 50 |
SQL Fiddle

Answer 2

This should work:
declare #total int = (select sum(col1) from Table)
select id, name, col1, col2, #total - (select sum(col2) from Table where date <= T.date) as col3, date from Table T
I was assuming you want to substract every time the previous total (based on the date). I hope this is OK.

Answer 3

You can use simple select query with cross apply
SELECT ID
,NAME
,COL1
,COL2
,A.C1 - (
SUM(COL2) OVER (
ORDER BY ID
)
) AS COL3
FROM TABLE1 T1
CROSS APPLY (
SELECT SUM(COL1) AS C1
FROM TABLE1 T2
) A

Answer 4

You can use two subqueries in SELECT fields list.
With the first you'll get a sum of all rows of your table named yourtable, in the second you'll get a sum of all rows before the current. So you can subtract two values.
Try this:
SELECT T.id, T.name, T.col1, T.col2,
ISNULL(
(SELECT SUM(T2.col1) FROM yourtable T2)
,0) -
ISNULL(
(SELECT SUM(T3.col2) FROM yourtable T3
WHERE T3.id <= T.id)
,0) as col3,
t.date
FROM yourtable T
Go on Sql fiddle example
EDIT
SELECT T.id, T.name, T.col1, T.col2,
ISNULL(
(SELECT SUM(T2.col1) FROM yourtable T2 where T2.id = T.id)
,0) -
ISNULL(
(SELECT SUM(T3.col2) FROM yourtable T3
WHERE T3.id = T.id AND T3.date <= T.date)
,0) as col3,
t.date
FROM yourtable T
Go on Sql Fiddle edited example
Pay attention: A deep edit can be a different question. Two queries are differents
Pay attention: it's no good a field named ID with repeated values