What's wrong with my word count program? - c

Question

Trying to make a function that outputs the count of words a user enters into the program. I keep getting a value of 2 with this code and I am not sure why or where I am going wrong. If someone can point me in the right direction that would be great. Thanks!
Here is the code:
#include <stdio.h>
#include <string.h>
int wordcount(char string[101]){
int i, words = 0;
for(i=0;string[i] != '\0';i++)
{
if(string[i] != '\t' && string[i] != '\0'){
words++;
while(string[i] != ' ' && string[i] != '\t' && string[i] !=
'\0')
i++;
}
}
return words;
}
int main (void) {
char input[101];
printf("Word Counter\n");
printf("============\n");
printf("string to be analyzed: \n");
scanf("%100[^\n]", input);
wordcount(input);
printf(" %s - words = %i\n", input, wordcount(input));
}

Answer 1

The main problem now is there are two.
if(string[i] != '\t' && string[i] != '\0'){ deterioration, changing for the worse
i is +1 to twice in the for and while.
For example, it will change as follows.
int wordcount(char string[101]){
int i, words = 0;
for(i=0;string[i] != '\0'; i++){
if(string[i] != ' ' && string[i] != '\t'){// assuming not included the newline.
words++;
i += strcspn(&string[i], " \t") -1;// i point to last character of word
}
}
return words;
}
or i changes it will be in one place.
int wordcount(char string[]){
int i, words = 0;
char prev =' ';
for(i=0;string[i] != '\0'; i++){
if(isspace(prev) && !isspace(string[i])){//isspace in <ctype.h>
words++;//count front edge
}
prev = string[i];
}
return words;
}