How do I count the number of words in a string with Snowflake? I cant seem to find anything on Google directly.
Try doing this. It assumes that a space separates every word:
SELECT ARRAY_SIZE(SPLIT(string,' '));
This UDF will handle punctuation, multiple spaces between words, line breaks, etc. It's not completely bulletproof, but should work for most use cases.
create or replace function WORD_COUNT(SENTENCE string)
returns number
language sql
as
$$
array_size(split(trim(regexp_replace(regexp_replace(SENTENCE, '[^A-Za-z0-9]', ' '), '[ ]{2,}', ' ')), ' '))
$$;
select word_count('The quick brown--fox jumps over.the;lazy?dog.');
Here is a sample of the issue:
SELECT 'True'
WHERE 'Hello ' IN ('Hello', 'Goodbye', 'Hello ')
Currently this returns 'True' because SQL ignores trailing spaces when comparing VARCHAR. In this related question, this can be solved by using LIKE, however this won't work with an IN condition.
How can I ensure that the comparison takes into account the trailing spaces, specifically when using the IN condition?
Edit:
My list of acceptable values can include items with trailing spaces. Looking to compare exact values essentially (i.e 'Hello ' won't match with 'Hello ')
Assuming that your list of acceptable values do not have trailing spaces, perhaps you could use:
SELECT 'True'
WHERE 'Hello ' IN ('Hello', 'Goodbye') AND 'Hello ' NOT LIKE '% '
You could add a non-space char to the end of your search temrs:
DECLARE #Terminator char(1) = '|';
SELECT 'True'
WHERE 'Hello ' + #Terminator IN ('Hello' + #Terminator , 'Goodbye' + #Terminator)
This will force the comparison to take into account the trailing spaces while keeping everything seargable. (I assume you want to use columns either on the left or on the right side of the IN operator)
I can think of this solution on top of my head:
SELECT 'True'
WHERE reverse('Hello ') IN (reverse('Hello'), reverse('Goodbye'))
Basically this forces to compare string using reverse function.
But Zohar's solution below is most performance driven solution.
SELECT 'True'
WHERE 'Hello '+'|' IN ('Hello'+'|', 'Goodbye'+'|')
I've been using this for some time:
SUBSTRING(str_col, PATINDEX('%[^0]%', str_col), LEN(str_col))
However recently, I've found a problem with columns with all "0" characters like '00000000' because it never finds a non-"0" character to match.
An alternative technique I've seen is to use TRIM:
REPLACE(LTRIM(REPLACE(str_col, '0', ' ')), ' ', '0')
This has a problem if there are embedded spaces, because they will be turned into "0"s when the spaces are turned back into "0"s.
I'm trying to avoid a scalar UDF. I've found a lot of performance problems with UDFs in SQL Server 2005.
SUBSTRING(str_col, PATINDEX('%[^0]%', str_col+'.'), LEN(str_col))
Why don't you just cast the value to INTEGER and then back to VARCHAR?
SELECT CAST(CAST('000000000' AS INTEGER) AS VARCHAR)
--------
0
Other answers here to not take into consideration if you have all-zero's (or even a single zero).
Some always default an empty string to zero, which is wrong when it is supposed to remain blank.
Re-read the original question. This answers what the Questioner wants.
Solution #1:
--This example uses both Leading and Trailing zero's.
--Avoid losing those Trailing zero's and converting embedded spaces into more zeros.
--I added a non-whitespace character ("_") to retain trailing zero's after calling Replace().
--Simply remove the RTrim() function call if you want to preserve trailing spaces.
--If you treat zero's and empty-strings as the same thing for your application,
-- then you may skip the Case-Statement entirely and just use CN.CleanNumber .
DECLARE #WackadooNumber VarChar(50) = ' 0 0123ABC D0 '--'000'--
SELECT WN.WackadooNumber, CN.CleanNumber,
(CASE WHEN WN.WackadooNumber LIKE '%0%' AND CN.CleanNumber = '' THEN '0' ELSE CN.CleanNumber END)[AllowZero]
FROM (SELECT #WackadooNumber[WackadooNumber]) AS WN
OUTER APPLY (SELECT RTRIM(RIGHT(WN.WackadooNumber, LEN(LTRIM(REPLACE(WN.WackadooNumber + '_', '0', ' '))) - 1))[CleanNumber]) AS CN
--Result: "123ABC D0"
Solution #2 (with sample data):
SELECT O.Type, O.Value, Parsed.Value[WrongValue],
(CASE WHEN CHARINDEX('0', T.Value) > 0--If there's at least one zero.
AND LEN(Parsed.Value) = 0--And the trimmed length is zero.
THEN '0' ELSE Parsed.Value END)[FinalValue],
(CASE WHEN CHARINDEX('0', T.Value) > 0--If there's at least one zero.
AND LEN(Parsed.TrimmedValue) = 0--And the trimmed length is zero.
THEN '0' ELSE LTRIM(RTRIM(Parsed.TrimmedValue)) END)[FinalTrimmedValue]
FROM
(
VALUES ('Null', NULL), ('EmptyString', ''),
('Zero', '0'), ('Zero', '0000'), ('Zero', '000.000'),
('Spaces', ' 0 A B C '), ('Number', '000123'),
('AlphaNum', '000ABC123'), ('NoZero', 'NoZerosHere')
) AS O(Type, Value)--O is for Original.
CROSS APPLY
( --This Step is Optional. Use if you also want to remove leading spaces.
SELECT LTRIM(RTRIM(O.Value))[Value]
) AS T--T is for Trimmed.
CROSS APPLY
( --From #CadeRoux's Post.
SELECT SUBSTRING(O.Value, PATINDEX('%[^0]%', O.Value + '.'), LEN(O.Value))[Value],
SUBSTRING(T.Value, PATINDEX('%[^0]%', T.Value + '.'), LEN(T.Value))[TrimmedValue]
) AS Parsed
Results:
Summary:
You could use what I have above for a one-off removal of leading-zero's.
If you plan on reusing it a lot, then place it in an Inline-Table-Valued-Function (ITVF).
Your concerns about performance problems with UDF's is understandable.
However, this problem only applies to All-Scalar-Functions and Multi-Statement-Table-Functions.
Using ITVF's is perfectly fine.
I have the same problem with our 3rd-Party database.
With Alpha-Numeric fields many are entered in without the leading spaces, dang humans!
This makes joins impossible without cleaning up the missing leading-zeros.
Conclusion:
Instead of removing the leading-zeros, you may want to consider just padding your trimmed-values with leading-zeros when you do your joins.
Better yet, clean up your data in the table by adding leading zeros, then rebuilding your indexes.
I think this would be WAY faster and less complex.
SELECT RIGHT('0000000000' + LTRIM(RTRIM(NULLIF(' 0A10 ', ''))), 10)--0000000A10
SELECT RIGHT('0000000000' + LTRIM(RTRIM(NULLIF('', ''))), 10)--NULL --When Blank.
Instead of a space replace the 0's with a 'rare' whitespace character that shouldn't normally be in the column's text. A line feed is probably good enough for a column like this. Then you can LTrim normally and replace the special character with 0's again.
My version of this is an adaptation of Arvo's work, with a little more added on to ensure two other cases.
1) If we have all 0s, we should return the digit 0.
2) If we have a blank, we should still return a blank character.
CASE
WHEN PATINDEX('%[^0]%', str_col + '.') > LEN(str_col) THEN RIGHT(str_col, 1)
ELSE SUBSTRING(str_col, PATINDEX('%[^0]%', str_col + '.'), LEN(str_col))
END
The following will return '0' if the string consists entirely of zeros:
CASE WHEN SUBSTRING(str_col, PATINDEX('%[^0]%', str_col+'.'), LEN(str_col)) = '' THEN '0' ELSE SUBSTRING(str_col, PATINDEX('%[^0]%', str_col+'.'), LEN(str_col)) END AS str_col
This makes a nice Function....
DROP FUNCTION [dbo].[FN_StripLeading]
GO
CREATE FUNCTION [dbo].[FN_StripLeading] (#string VarChar(128), #stripChar VarChar(1))
RETURNS VarChar(128)
AS
BEGIN
-- http://stackoverflow.com/questions/662383/better-techniques-for-trimming-leading-zeros-in-sql-server
DECLARE #retVal VarChar(128),
#pattern varChar(10)
SELECT #pattern = '%[^'+#stripChar+']%'
SELECT #retVal = CASE WHEN SUBSTRING(#string, PATINDEX(#pattern, #string+'.'), LEN(#string)) = '' THEN #stripChar ELSE SUBSTRING(#string, PATINDEX(#pattern, #string+'.'), LEN(#string)) END
RETURN (#retVal)
END
GO
GRANT EXECUTE ON [dbo].[FN_StripLeading] TO PUBLIC
cast(value as int) will always work if string is a number
SELECT CAST(CAST('000000000' AS INTEGER) AS VARCHAR)
This has a limit on the length of the string that can be converted to an INT
If you are using Snowflake SQL, might use this:
ltrim(str_col,'0')
The ltrim function removes all instances of the designated set of characters from the left side.
So ltrim(str_col,'0') on '00000008A' would return '8A'
And rtrim(str_col,'0.') on '$125.00' would return '$125'
This might help
SELECT ABS(column_name) FROM [db].[schema].[table]
replace(ltrim(replace(Fieldname.TableName, '0', '')), '', '0')
The suggestion from Thomas G worked for our needs.
The field in our case was already string and only the leading zeros needed to be trimmed. Mostly it's all numeric but sometimes there are letters so the previous INT conversion would crash.
For converting number as varchar to int, you could also use simple
(column + 0)
Very easy way, when you just work with numeric values:
SELECT
TRY_CONVERT(INT, '000053830')
Try this:
replace(ltrim(replace(#str, '0', ' ')), ' ', '0')
If you do not want to convert into int, I prefer this below logic because it can handle nulls
IFNULL(field,LTRIM(field,'0'))
SUBSTRING(str_col, IIF(LEN(str_col) > 0, PATINDEX('%[^0]%', LEFT(str_col, LEN(str_col) - 1) + '.'), 0), LEN(str_col))
Works fine even with '0', '00' and so on.
Starting with SQL Server 2022 (16.x) you can do this
TRIM ( [ LEADING | TRAILING | BOTH ] [characters FROM ] string )
In MySQL you can do this...
Trim(Leading '0' from your_column)
I want to make a substring of a column value using a specific delimiter.I tried SUBSTRING_INDEX,but it doesn't work for SQL.Is there any way to achieve this??
Column values are:
ARTCSOFT-1111
ARTCSOFT-1112
ARTCSOFT-1113
and I want to achieve the same thing in SQL:
SUBSTRING_INDEX(Code,'SOFT-',1))
i.e I want the number after SOFT- in my substring.I can't use only - because before SOFT- there is chance that - may occur(rare case,but I don't want to take a chance)
Try using just SUBSTRING . For example
SELECT
SUBSTRING(code, CHARINDEX('SOFT-', code) + 5, LEN(code)) AS [name] from dbo.yourtable
hope this helps.
Tested Result:
SELECT RIGHT(Code , CHARINDEX ('-' ,REVERSE(Code))-1)
Read this as: Get the rightmost string after the first '-' in a reversed string - which is the same as the string after the last '-' character.
Try This Query:
select substring(col,charindex('-',col)+1,len(col)-charindex('-',col)) from #Your_table
Explanation of Query:
Here Charindex find the '-' delimeter [length] IN Given String and now that Result[length+1] is our starting point and ending length is [len(col)-starting length] gives ending point and then use substring Function to split a string according to our requirement.
Result of Query:
Required_col
1111
1112
1113
I have a string with a specific pattern:
23;chair,red [$3]
i.e., a number followed by a semicolon, then a name followed by a left square bracket.
Assuming the semicolon ; always exists and the left square bracket [ always exists in the string, how do I extract the text between (and not including) the ; and the [ in a SQL Server query? Thanks.
Combine the SUBSTRING(), LEFT(), and CHARINDEX() functions.
SELECT LEFT(SUBSTRING(YOUR_FIELD,
CHARINDEX(';', YOUR_FIELD) + 1, 100),
CHARINDEX('[', YOUR_FIELD) - 1)
FROM YOUR_TABLE;
This assumes your field length will never exceed 100, but you can make it smarter to account for that if necessary by employing the LEN() function. I didn't bother since there's enough going on in there already, and I don't have an instance to test against, so I'm just eyeballing my parentheses, etc.
Assuming they always exist and are not part of your data, this will work:
declare #string varchar(8000) = '23;chair,red [$3]'
select substring(#string, charindex(';', #string) + 1, charindex(' [', #string) - charindex(';', #string) - 1)
An alternative to the answer provided by #Marc
SELECT SUBSTRING(LEFT(YOUR_FIELD, CHARINDEX('[', YOUR_FIELD) - 1), CHARINDEX(';', YOUR_FIELD) + 1, 100)
FROM YOUR_TABLE
WHERE CHARINDEX('[', YOUR_FIELD) > 0 AND
CHARINDEX(';', YOUR_FIELD) > 0;
This makes sure the delimiters exist, and solves an issue with the currently accepted answer where doing the LEFT last is working with the position of the last delimiter in the original string, rather than the revised substring.
select substring(your_field, CHARINDEX(';',your_field)+1
,CHARINDEX('[',your_field)-CHARINDEX(';',your_field)-1)
from your_table
Can't get the others to work. I believe you just want what is in between ';' and '[' in all cases regardless of how long the string in between is. After specifying the field in the substring function, the second argument is the starting location of what you will extract. That is, where the ';' is + 1 (fourth position - the c), because you don't want to include ';'. The next argument takes the location of the '[' (position 14) and subtracts the location of the spot after the ';' (fourth position - this is why I now subtract 1 in the query). This basically says substring(field,location I want substring to begin, how long I want substring to be). I've used this same function in other cases. If some of the fields don't have ';' and '[', you'll want to filter those out in the "where" clause, but that's a little different than the question. If your ';' was say... ';;;', you would use 3 instead of 1 in the example. Hope this helps!
If you need to split something into 3 pieces, such as an email address and you don't know the length of the middle part, try this (I just ran this on sqlserver 2012 so I know it works):
SELECT top 2000
emailaddr_ as email,
SUBSTRING(emailaddr_, 1,CHARINDEX('#',emailaddr_) -1) as username,
SUBSTRING(emailaddr_, CHARINDEX('#',emailaddr_)+1, (LEN(emailaddr_) - charindex('#',emailaddr_) - charindex('.',reverse(emailaddr_)) )) domain
FROM
emailTable
WHERE
charindex('#',emailaddr_)>0
AND
charindex('.',emailaddr_)>0;
GO
Hope this helps.