C - Printing a dynamic array - c

Question

I am creating a program that modifies a dynamic array. It must initialize the array and be able to insert into it. I have been unable print the array after in order to test it, how would I go about this?
Piece of relevant code:
typedef struct {
char first;
char second;
} name;
typedef struct {
int number;
name name;
} data;
/*points to array, number allocated, number used*/
typedef struct {
data *info;
size_t numof;
size_t numused;
} list;
void init(list *l) {
l->data = malloc(sizeof(l) * l->numof);
l->numused = 0;
l->numof = 2;
}
int insert(list *l, const data *dat) {
if (l->numused == l->numof) {
l->numof *= 2;
l->data = (int *)realloc(l->data, l->numof * sizeof(int));
}
l->data[l->numused++] = *dat;
return 0;
}
int main(void) {
int i;
list l;
data list1;
/*example info for testing*/
list.number = 1234;
strcpy(list1.name.first, "abc");
strcpy(list1.name.second, "xyz");
init(&l);
insert(&l, list1);
/*runs through array elements to print*/
for (i=0; i < ((int)sizeof(&l)) /(int)sizeof(&l); i++) {
printf("%s\n", list1);
}
return 0;
}
Edit: I just need to know how to print the array to see if I'm doing it correctly, the code above will have errors as I had been messing around trying to figure it out.

Answer 1

strcpy(list1.name.first, "abc");
strcpy(list1.name.second, "xyz");
These both will invoke undefined behaviour as first and second are declared as char variables , and you copy string literals to them .
You need to declare both of them as character arrays .
And this -
for (i=0; i < ((int)sizeof(&l)) /(int)sizeof(&l); i++) {
printf("%s\n", list1);
}
You try to print struct variable list1 with %s specifier, maybe you tend to print the strings that you wanted to copy. So directly print list1.name.first and list1.name.second in printf with %s specifier.
And the condition -
i < ((int)sizeof(&l)) /(int)sizeof(&l)
The cast is not necessary , and it will yield 1 so, loop will run for 1 time . Change the condition .

Answer 2

In your code, the member of structure name is defined as char. But you are trying to copy a string into it. May be this was a typo. If not you should define them as character array or character pointer. Also in your print statement you are trying to print structure data as string. It should be like -
printf("%s %s\n", list1.name.first, list1.name.second);
Also you assigned value 1234 to list.number. You may have meant list1.number. The parameters in function call of insert is wrong as well. And lastly, you have put l->data in functions init and insert which should be l->info.