scanf() multiple words in C - c

Question

I need a simple function that can read multiple words into a string in C, kind of like Scanner.nextLine() in Java or Console.ReadLine() in C#, but I can't seem to find a simple method anywhere, I tried all sorts of things, but none of them seem to work 100% of the time.

Answer 1

You can use fgets
char *fgets(char *str, int n, FILE *stream)
Be aware that fgets reads until reach the size n, or a newline or an EOF.
This is made to avoid buffer overflow, so you need to make sure that your buffer is big enough to store the string.

Answer 2

scanf is what you want:
#include <stdio.h>
int main(void)
{
char string[50];
scanf(" %49[^\n]s",string);
printf("you entered: %s\n",string);
}

Answer 3

you can follow this:
char str[100];// as length of the total words neded
fgets(str,100,stdin)
printf("output: %s",str);
return 0;

Answer 4

Use fgets to parse an input string into a char buffer.
char * fgets ( char * str, int num, FILE * stream );
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Then use sscanf to dissect this string to however you need it.
int sscanf ( const char * s, const char * format, ...);
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Answer 5

This removes the '\n' character that is included in the string returned by fgets, thus making the function practically equivalent to the functions present in popular managed languages:
//gets a line from the specified stream
int getline(char* charArray, int maxLength, FILE* stream) {
int i;
if (fgets(charArray, maxLength, stream) == NULL)
return 1; //some error occurred
for (i = 0; i < maxLength; i++) {
if (charArray[i] == '\n') {
if (i != 0 && charArray[i - 1] == '\r') //cater for windows line endings
i--;
charArray[i] = '\0';
return 0; //all's well that ends well
} else if (charArray[i] == '\0')
return 0; //smooth sailing fam
}
return 2; //there was no string terminator
}

Answer 6

Here you go:
#include "stdio.h"
//gets a line from the specified stream
int getline(char* charArray, int maxLength, FILE* stream) {
int i;
if (fgets(charArray, maxLength, stream) == NULL)
return 1; //some error occurred
for (i = 0; i < maxLength; i++) {
if (charArray[i] == '\n') {
if (i != 0 && charArray[i - 1] == '\r') //cater for windows line endings
i--;
charArray[i] = '\0';
return 0; //all's well that ends well
} else if (charArray[i] == '\0')
return 0; //smooth sailing fam
}
return 2; //there was no string terminator
}
int main() {
char money[4];
printf("How much money do you have on you? ");
getline(money, 4, stdin);
printf("Oh really? $%d? Good. :)\n", atoi(money));
char string[4];
printf("Where is our next lesson?\n");
getline(string, 4, stdin);
printf("%s", string);
return 0;
}