This is the output of my program. Even though the conditions have been met, it still does not go out of the loopenter image description here
This is my program. The first while loop asks if the user owns a car.
#include <stdio.h>
#include <conio.h>
#define TRANSPORT 1
int main()
{
char PrivateVehicle;
printf("DRIVING ANF FLYING CARBON FOORPRINT \n");
printf("I. LAND \n");
printf("A. PRIVATE OWNED \n");
while (TRANSPORT==1)
{
do
{
printf("Question 1: \n");
printf("Do you have your own private vehicle? [Y/y]-Yes, [N/n]-No \n");
printf("Note: Only the letters Y, y for yes and N, n for no would be accepted \n");
scanf (" %c", &PrivateVehicle);
if (PrivateVehicle!='Y' && PrivateVehicle!='y' && PrivateVehicle!='N' && PrivateVehicle!='n')
printf("Inavlid \n");
} while (PrivateVehicle!='Y' && PrivateVehicle!='y' && PrivateVehicle!='N' && PrivateVehicle!='n');
if (PrivateVehicle=='Y'|| PrivateVehicle=='y') // should go out of the loop after condition is met
printf("Y/y\n"); //For checking
else if (PrivateVehicle=='N'|| PrivateVehicle=='n') // should go out of the loop after condition is met
printf("N/n\n"); //For checking
TRANSPORT==0;
}
printf("Out"); //For checking
printf("B. PUBLIC TRANSPORT \n");
}
You can't assign to a macro identifier with
TRANSPORT == 0;
(even when "fixing" the == with =). You need to use a variable if you need to change a value of something, e.g. int TRANSPORT = 0; instead of the #define directive.
The reason for the non-terminating loop is that after macro expansion, you have
while (1==1)
which is always true.
The symbol TRANSPORT is a preprocessor macro, it can't be changed at run-time. In fact, in the generated code there is no reference to the TRANSPORT symbol at all, it doesn't exist once the preprocessor replaces it in the code.
TRANSPORT is define as preprocessor macro - you yould change it to be a variable.
Then you'd still need to changehe evaulationTRANSPORT==0; to be an assignment TRANSPORT=0;
You mustn't use #define TRANSPORT 1, but instead int TRANSPORT = 1 or something like that.
The #define creates a macro, which is the association of an identifier
or parameterized identifier with a token string. After the macro is
defined, the compiler can substitute the token string for each
occurrence of the identifier in the source file.
Related
For Caesar cipher encryption, I have this code. This program uses text written by the user. But I want this to be read from a text file and run.
#include<stdio.h>
#include <conio.h>
#include<string.h>
void main()
{
int key,i;
char [30];
clrscr();
printf("\n enter plain text : ");
gets(data);
printf("\ enter key value : ");
scanf("%d",&key);
{
for (i=o;i<strlen(data);i++) {
if (data[i]==' ') {}
else
{
if (data[i]>='x')
{
data[i]=data[i]-26;
}
data[i]=data[i]+key;
}
}
}
printf("your cipher text is : %s",data);
getch();
}
Did you just copy and paste this code from somewhere?
As everyone else has already pointed out, there are some pretty big problems with your code, so I'll try and touch on the ones they haven't mentioned throughout. To start though, you should declare main as an int. The return value tells you if the program exited correctly, it's not just convention.
Here is your original code, formatted. I removed conio.h because it's been deprecated for years and moreover you don't need it here. All it was doing was clearing the screen for you, which you can do with System("CLS");, although here is a great article that's been shared many times here on SO that explains why you should refrain from using it.
#include<stdio.h>
#include<string.h>
int main()
{
int key,i;
// original: char [30];
// I'm guess you copied and pasted wrong?
char plainText[30];
printf("\n enter plain text : ");
gets(data);
printf("\nenter key value : ");
scanf("%d",&key);
// You had brackets here, essentially creating an unnecessary
// block of code.
for(i=o;i<strlen(data);i++)
{
// Where did the "data" variable come from? You haven't declared it
// and you're trying to get its length in this for loop
if (data[i]==' ')
{
// ?
}
else
{
if (data[i]>='x')
{
// Instead of this approach I would go with a modulus operation
// If you're not familiar with modular arithmetic I really recommend you look
// it up. It's absolutely essential in cryptography. It's central to both
// symmetric and asymmetric key cryptography.
data[i]=data[i]-26;
}
// This is the heart of the Caesar cipher right here. This is where you're actually
// shifting the characters, so it's a literal Caesar cipher
data[i]=data[i]+key;
}
}
// Again, you haven't declared "data" so you can't call it. I'm guessing you didn't
// try to compile this program because it is teeming with errors GCC, Clang, and VC++
// would have caught immediately
printf("your cipher text is : %s",data);
getch();
// Remember to make your "main" function return an <code>int</code>. This value is
// very important, especially when your program gets called by another program because
// it's how your program communicates that it ran successfully, or something went
// wrong. In that case you could set a specific error code to know exactly
// what went wrong and were
// Example:
int x = 1;
if (x == 1)
exit(4);
// This program would now exit with a status of 4, which you would then know was due
// to this function. This was a contrived example, but hopefully you get the gist
return 0;
}
I have an assignment due and I am drawing a blank on what exactly to do... I'm sure it is simple but I havent quite gotten the hang of things yet. The assignment is -
Write a program that gives the user 2 menu options: either call a function that will print a greeting and your name 4 times or call a function that will count down from 10 to 0 and then print "Blastoff!". Both functions should use for loops to print the appropriate output.
I have the prompt and the functions done so far... but I am unsure of how to display one or the other depending on the choice the user makes. Thank you for your help.
#include <stdio.h>
int main (void){
// declare counter variable
int i;
// prompt the user to make a choice
printf("What would you like to do?\n 1. Print my name\n 2. Count down from 10\n");
printf("\n");
// display greeting and name 4 times
for(i=1;i<=4;i++)
{
printf("Hi, my name is Bridget\n");
}
// display countdown
for(i=10;i>=0;--i)
{
printf("%d\n", i);
}
printf("Blastoff!");
}
You should read the input from user's keyboard:
int c;
c = getchar();
if (c == '1')
{
// display greeting and name 4 times
for(i=1;i<=4;i++)
{
printf("Hi, my name is Bridget\n");
}
}
if (c == '2')
{
// display countdown
for(i=10;i>=0;--i)
{
printf("%d\n", i);
}
}
printf("Blastoff!");
you should use Switch case.
switch(choice) {
case 1: //first for loop
break;
case 2: //second for loop
break;
}
Looks like you are missing a couple of points here. Firstly, you have not yet written any functions. Try looking here to gain some insight on that front.
Secondly, to make a choice based on user input you need to actually get that input somehow. You'll probably want to use scanf.
Lastly, once you have the user's input (say, in a variable declared as int input;) you can use if to control the flow of your program based on that variable like this:
if(input == 1){
greet();
}
else {
countDown();
}
Cheers! If you have any further questions feel free to comment below.
First of all you haven't actually declared you functions. Functions in C should be declared like the main function is. For more info in this see here.
// display greeting and name 4 times
void greeting(){
for(i=1;i<=4;i++)
{
printf("Hi, my name is Bridget\n");
}
}
void countdown() {
// display countdown
for(i=10;i>=0;--i)
{
printf("%d\n", i);
}
printf("Blastoff!");
}
To get the user's input the most common way is by keyboard. scanf accomplishes that in C. Details on scanf here
int main(void){
int i, choice;
//prompt the user to make a choice
// You don't need 2 printf for the newlines stick them to one.
printf("What would you like to do?\n 1. Print my name\n 2. Count down from 10\n\n");
//This takes the user's input and puts it in the variable choice
scanf(%d, &choice);
}
Lastly to decide what to do based on the user input you can use either an if then else statement or a switch. I will provide a solution with an if statement and you can figure the one with the switch on your own. Your final code should look like this.
int main(void){
int i, choice;
//prompt the user to make a choice
// You don't need 2 printf for the newlines stick them to one.
printf("What would you like to do?\n 1. Print my name\n 2. Count down from 10\n\n");
//This takes the user's input and puts it in the variable choice
scanf(%d, &choice);
if(choice == 1){
greeting();
}else{
countdown();
}
}
// display greeting and name 4 times
void greeting(){
for(i=1;i<=4;i++)
{
printf("Hi, my name is Bridget\n");
}
}
void countdown() {
// display countdown
for(i=10;i>=0;--i)
{
printf("%d\n", i);
}
printf("Blastoff!");
}
Bear in mind that this code has a lot of flaws (error checking mainly) but I guess your assigment is not about that.
First of all you need to include libraries with function you will need. You do this by
#include <someLibrary.h>
at the beggining of you document. Libraries mostly have .h extension. Always look for them if you try to do something. You consider them to have best performance and functionality as possible (not always true).
What is next you declare your functions. Function has name, arguments which are going into it, body in which they do something and return value (can be float, int, char etc). If function doesnt return anything, they return void (dont have return at the end). You declare functions before main() with only types of arguments. Whole body is after main (it is better looking).
If you declared function with arguments, you have to provide these arguments to function in () brackets. Even if no arguments are needed, you use them like getch() in example below. Note that function become what it return. If you declared some new variables in function they will be visible only in function. On the other hand function will not see any variable from other function (main too). If you want so, declare global variables (not recommended).
#include <stdio.h>
#include <conio.h> //libraries
void function1(int);
float function2(float); //declaration of functions
int main()
{
char decision;
printf("press 'a' to run function1, press 'b' to run function2\n");
decision=getch(); //first see getch()? look in google for functionality and library !
int someInt=10;
float someFloat=11;
if(decision== 'a')
{
function1(someInt);
}
else if(decision == 'b')
{
printf("%f", funcion2(someFloat)); //example that function become what they return
}
else
{
printf("No decision has been made");
}
getch(); //program will wait for any key press
return 0;
}
void function1(int param1)
{
//print your stuff // this function return void, so doesnt have return; statement
}
float function2(float param1)
{
return 2*param1; //this function have to return some float
}
For a small project we need to make a connect four game. Our project is broken up into several parts with each week we are assigned a different part to work on.
This week we have to make up the work on the columns by this I mean we have to use a function is called get_column, and use this to read a valid column number from the user where the next piece will be played.
So we were supplied the following files connect4.h (File used to store functions), week8_object.o (ignore the name its just the current week of sem), and week8.c which is the file I am currently editing.
Note 1: The comment in the code is what the lecturer wrote for us as a note.
When I am compiling I get an error saying undeclared identifier for the if(column_full(board, col)==FALSE) statement (FALSE part). I thought this was declared in the .h file?
EDIT- After some googling I have found that people silence that error by having this in the header. Is it correct to have this in coherence with the .h file?:
#include <stdio.h>
#include "connect4.h"
#define FALSE 0
#define TRUE 1
/* get_move
Prompts the user to enter a column, then checks that
- the column is in the valid range (1-COLS)
- that the column is not full (use function column_full to check)
If an invalid column is entered, the user is reprompted until it is valid
Returns the column number between 1 and COLS
*/
int column_full ( int board[COLS][ROWS], int col ) { return TRUE;}
int get_move ( int board[COLS][ROWS] ){
int col;
printf("Please enter a column number:");
scanf("%d",&col);
if(col>=1 && col<=COLS){
if(column_full(board, col)==FALSE){
printf("You have placed a token in the %d column\n",col);
}
else{
printf("That column is full");
}
}
while(col<=0 || col>COLS){
printf("Your token has not been placed");
printf("Please enter a valid column: ");
scanf("%d",&col);
}
return(col);
}
Header file:
#ifndef CONNECT4_H
#define CONNEXT4_H 1
#define ROWS 6
#define COLS 7
// displays the board to the screen
int display_board ( int[COLS][ROWS] ) ;
// sets up the board to an empty state
int setup_board ( int[COLS][ROWS] ) ;
// Returns TRUE if the specified column in the board is completely full
// FALSE otherwise
// col should be between 1 and COLS
int column_full ( int[COLS][ROWS], int col ) ;
// prompts the user to enter a move, and checks that it is valid
// for the supplied board and board size
// Returns the column that the user has entered, once it is valid (1-COLS)
int get_move ( int[COLS][ROWS] ) ;
// adds a token of the given value (1 or 2) to the board at the
// given column (col between 1 and COLS inclusive)
// Returns 0 if successful, -1 otherwise
int add_move ( int b[COLS][ROWS], int col, int colour ) ;
// determines who (if anybody) has won. Returns the player id of the
// winner, otherwise 0
int winner ( int[COLS][ROWS] ) ;
// determines if the board is completely full or not
int board_full ( int[COLS][ROWS] ) ;
#endif
There are few issues in your code:
In get_move() function, the given condition "If an invalid column is entered, the user is reprompted until it is valid" is not been taken care. You might want to use while loop in case of invalid column entered.
column_full() in your code is called without parameters. This function takes two parameters (refer to you .h file). So, don't forget to add them in call.
You have to use return(col) to take care of "Returns the column number between 1 and COLS"
I don't want to write a code for you. It would be helpful for you in long run, if you code yourself.
Now, to answer your question:
It is perfectly fine to have nested if-else statements.
From your original code:
}; /* <<-- problem 1 */
else() {
/* ^^^^ <<-- problem 2 */
printf("That column is full");
}
Remove these and your code will compile. I won't discuss the logic issues.
So in diff notation:
--- connect4.c.orig 2015-09-19 14:34:36.743337010 -0400
+++ connect4.c 2015-09-19 14:34:23.488222720 -0400
## -24,9 +24,9 ##
if(col>=1 && col<=COLS){
if(column_full(board, col)==FALSE){
- printf("You have placed a token in the %d column\n",col);
+ printf("You have placed a token in the %d column\n",col);
}
- else(){
+ else{
printf("That column is full");
}
}
So am trying to learn c by-myself (basically not having any previous experience in any programming language) and now I have some issues with prototyping some of my functions to use in header files.
For the sake of learning I only use the < stdio.h > lib and only use the printf and scanf functions and for now it only prints to console.
I was able to code a working prototype function for my menu that only uses the printf function but the scanf gives me more issues and it just refuses to compile and am having trouble to see where my thinking error is.
my main program:
#include "menu.h"
#include "circlefunctions.h"
#include "input.h"
int main(void){
float diameter;
double straal;
double oppervlakte;
double omtrek;
while(1){
menu();
user_input();
system("cls");
switch(user_input())
{
case 1:
printf(" ----------------------------------------\n");
printf(" Typ de diameter van de cirkel: ");
scanf("%g", &diameter);
printf(" ----------------------------------------\n");
straal = diameter / 2;
oppervlakte = PI * (straal * straal);
omtrek = 2 * PI * straal;
printf(" De straal = %f \n\n", straal );
printf(" De oppervlakte = %f \n\n" , oppervlakte);
printf(" De omtrek = %f \n" , omtrek);
printf(" ----------------------------------------\n");
break;
case 2:
return(0);
case 3:
return(0);
case 9:
return(0);
case 0:
return(0);
}
}
return 0;
}
and the stubborn header:
#include <stdio.h>
void user_input();
void user_input(){
scanf("%d", &user_input);
}
The error that I get while trying to compile is in input.h
the part with; scanf("%d", &user_input);
errorcode: format '%d' expects argument type of 'int ', but argument 2 has type 'void () ()'.
And I also got an error on the switch in the main program that the switch quantity is not an integer. I suspect that this error is related but am not sure. I still have to debug that part but if anyone is willing to point me to the right documentation i would much appreciate it.
And a second question that I have is also related to headers: I have < stdio.h > already included in "menu.h". Would I need to include it again in "input.h"?
(if i understand correctly how the preprocessor works i should not have to include it but I can't find anywhere where this is explained in simple terms unfortunately.)
Edit:
Thank you all for providing valuable information.
#zenith Thank you for your example. I hope you don't mind me asking some more.
I have replaced my code with yours in the "input.h" and it will compile and run now. However the behavior has changed. For some unclear reason i now have to input the choice twice before the program accepts my input. So the 1st input gets ignored after an enter and it will only accept the 2nd input.
Could you perhaps point me in the direction what causes this bug? or perhaps point me to some documentation where this is explained? I don't want to take up to much of you valuable time of-course.
Edit 2
Thanks for the reply and info. I got the bug out and it is working as intended(that was silly of me not to see that).
And to the rest who replied: Ill take your information of-course and also learn from that. Thank you all!
user_input() doesn't return anything, since it's declared void.
But you're trying to use the non-existing return value: switch(user_input()).
This causes undefined behavior.
Additionally, this:
scanf("%d", &user_input);
tries to read an int from stdin and store it in the memory address of the user_input function. Not a good idea. Again, undefined behavior.
What you probably want the function to look like:
int user_input(){
int number; // store user input to this variable
scanf("%d", &number);
return number; // return the user input so that it can be used outside the function
}
If you have header files declared in a previous header file. You will not need to include it again in the subsequent included header files. I tend to not include header files in my local *.h files just for that reason. It avoids circular includes if you declare your includes in the .c files as much as possible.
Your scanf function has as its second argument a function of type void(), void(). Meaning it takes no arguments and returns nothing or "void". I think you want your user_input to be a variable of type 'double' that is filled somewhere, maybe via some user input from the console using a call to 'gets' from stdin.
HTH
I have a few issues with my syntax, it mainly says i have an errror before "struct" on the line "Struct CustomerInfo s; but i dont seem to find the problem.
My program is supposed to ask what the person would like to do first of all, they can store a record for the first option which is then stored in a structure which can be viewed by selecting the 2nd option of the menu, if they select the 3rd then they obviously quit the program.
any help would be appreciated thank you.
#include <stdio.h>
void menu();
int id,first,last;
struct CustomerInfo
{
char FirstName[15]; /* These are the varibles for the customer infomation */
char LastName[20];
int ID;
};
int main()
{ /* program starts */
int selection = 0;
void menu()
{ /* Menu loop function */
do
{ /* menu start */
printf("\n\n - What would you like to do?");
printf("\n1 - Store a customer record");
printf("\n2 - View customer Records");
printf("\n3 - Quit program");
scanf("%i", &selection);
} while (selection > 3);
printf("You have entered an incorrect value"); /* If selection is greater than 3 then end program */
return 0;
}
switch(selection)
{
/* switch statement starts */
case 1:
struct CustomerInfo s;
printf("Please enter the customers details including First name, Lastname and ID.\n\n");
printf("Enter First name: ");
scanf("%s", s.FirstName); /* Option 1: Asks to enter the customers details to store then loops back to program */
printf("Enter Last name: ");
scanf("%s", s.LastName);
printf("Enter Customer ID: ");
scanf("%s", s.ID);
void menu();
break;
case 2:
printf("\nDisplaying Infomation\n");
printf("First name: %s\n",s.Firstname); /* Option 2: Prints the customer details as listed in option 1 */
printf("Last name: %s\n",s.Lastname);
printf("Customer ID: %s\n",s.ID);
void menu();
break;
case 3: /* Option 3: Program ends if option 3 is chosen. */
break;
}
return 0;
Let's start by looking at the structure you created; next we'll try to see if it can be fixed.
I am leaving details out so we can see the big outline:
main {
struct{}
void menu(){
do {
stuff
} while (selection > 3)
printf("you have entered an incorrect value"); // if selection is > 3
}
switch(selection) {
// do something if selection is 1 or 2, exit if 3
}
There is no final closing brace in your code. I am assuming that's a copy-paste error, so I added it. Compiling with -Wall (to get warnings as well as errors reported), I get a number of errors:
sel.c:18: error: nested functions are disabled, use -fnested-functions to re-enable
sel.c: In function ‘menu’:
sel.c:31: warning: ‘return’ with a value, in function returning void
sel.c: In function ‘main’:
sel.c:38: error: expected expression before ‘struct’
sel.c:41: error: ‘s’ undeclared (first use in this function)
sel.c:41: error: (Each undeclared identifier is reported only once
sel.c:41: error: for each function it appears in.)
sel.c:61: warning: control reaches end of non-void function
Let's take those in turn:
sel.c:18: error: nested functions are disabled, use -fnested-functions to re-enable
Putting one function inside another is "nesting". It is rare that you would want to do that - it means that the function is only "visible" when you are inside the other function (a bit like local variables, but for functions). It is not standard C - it is an extension of gcc. It's almost always a bad idea to use non-standard (and thus non-portable) extensions. See http://gcc.gnu.org/onlinedocs/gcc/Nested-Functions.html
sel.c: In function ‘menu’:
sel.c:31: warning: ‘return’ with a value, in function returning void
When we declare a function void, we say that it will not return a value. When you have a statement like return 0; you ARE returning a value. The compiler will ignore that - but it warns that you said one thing, and did another. Just use return; without a parameter, and the warning goes away.
sel.c:38: error: expected expression before ‘struct’
sel.c:41: error: ‘s’ undeclared (first use in this function)
sel.c:41: error: (Each undeclared identifier is reported only once
sel.c:41: error: for each function it appears in.)
This is the trickiest one. You would expect that you were properly declaring a variable s in line 38 - but the compiler complains. The reason for this is explained in the excellent Q&A at
Why can't variables be declared in a switch statement?
As an aside - if you COULD declare a variable like this - what are you doing with it? Your code currently reads in values, and returns. But as soon as you leave the "scope" of the variable (in your case, since you declared s inside the switch, that would be its scope) the variable disappears (the memory that was used for it is marked "free" and will be re-used.)
sel.c:61: warning: control reaches end of non-void function
This says that you have reached the end of a function that expects to return a value, but you don't have a return someValue; type of statement. Again - this only causes a warning, since the default behavior is to return 0 if no value is given, but it's a sign that you said one thing and did another.
So far I've just explained the errors that the compiler gave. Let's look more closely at the code structure. What I think you want to do is something like this:
define customerInfo structure
define menu function
main()
repeat:
call menu, get selection
switch(selection):
case 1: create new record
case 2: display records
case 3: quit program
In order to make this work, we need to make some changes to your program. First - let's move the menu function definition outside of the main function so we have portable code. Second - if we want to be able to create multiple customer records, we need to store them in an array. Really you would want a list so you can extend indefinitely, but let's keep it simple and allow a maximum of 10 records. Then we need to improve the logic of the menu function (if selection is not 1, 2 or 3 you give a message and try again; in your current code the line
printf("You have entered an incorrect value");
doesn't get executed until you have exited the loop that tested for incorrect values… so when you finally get there, the value is valid, not invalid.
Before we actually get to writing the "correct" code, there's another thing worth noting. When you read values using scanf, you do things like:
scanf("%s", s.FirstName);
which is correct, since s.FirstName is a pointer to the start of a string. However, you allocated a finite amount of space to your string (namely, 15 characters including the terminating '\0') so if someone enters a long name, your program will crash. "Good defensive coding" demands that you catch this - use for example
scanf("%14s", s.FirstName);
This says "read no more than 14 characters". There are better tricks but at least this is a start. However, you actually make a mistake when you do
scanf("%s", s.ID);
Since ID was defined as an int, and now you are reading a string into… not just its address, but into some location that is pointed to by the value of s.ID . This is very likely to give you a segmentation error (accessing memory that "isn't yours"). You should be doing:
scanf("%d", &s.ID);
"Read an integer into the location of s.ID"
Also - in some places you use FirstName, while in others you use Firstname. Ditto LastName. Capitalization matters - when you fix other compiler errors, these will start to show up.
Since you seem to want to be able to read in more than one customer record, we need an array of records; as I said above, we have to make sure the array is available in the scope of the switch statement, and "survives" that statement (so you can do something with it). Taking all these things together gets us to something like this:
#include <stdio.h>
// define function prototype:
int menu();
struct CustomerInfo
{
char FirstName[15]; /* These are the variables for the customer infomation */
char LastName[20];
int ID;
};
int menu()
{ /* Menu loop function */
int flag = 0;
int selection;
do
{ /* menu start */
if(flag > 0) printf("You have entered an incorrect value"); /* If selection is greater than 3 then end program */
printf("\n\n - What would you like to do?");
printf("\n1 - Store a customer record");
printf("\n2 - View customer Records");
printf("\n3 - Quit program\n>> ");
scanf("%i", &selection);
flag++;
} while (flag < 10 && (selection < 0 ||selection > 3));
return selection;
}
int main(void)
{ /* program starts */
struct CustomerInfo s[10];
int selection;
int customerCount = 0;
while(1) {
int ii; // loop counter we will need later
selection = menu();
switch(selection)
{
case 1:
printf("Please enter the customers details including First name, Lastname and ID.\n\n");
printf("Enter First name: ");
scanf("%s", s[customerCount].FirstName); /* Option 1: Asks to enter the customers details to store then loops back to program */
printf("Enter Last name: ");
scanf("%s", s[customerCount].LastName);
printf("Enter Customer ID: ");
scanf("%d", &s[customerCount].ID);
customerCount++;
break;
case 2:
printf("\nDisplaying Infomation\n");
for(ii = 0; ii < customerCount; ii++) {
printf("First name: %s\n",s[ii].FirstName); /* Option 2: Prints the customer details as listed in option 1 */
printf("Last name: %s\n",s[ii].LastName);
printf("Customer ID: %d\n---\n",s[ii].ID);
}
break;
case 3: /* Option 3: Program ends if option 3 is chosen. */
return 0; // program returns
break;
}
}
}
Test output:
- What would you like to do?
1 - Store a customer record
2 - View customer Records
3 - Quit program
>> 1
Please enter the customers details including First name, Lastname and ID.
Enter First name: John
Enter Last name: Smith
Enter Customer ID: 123
- What would you like to do?
1 - Store a customer record
2 - View customer Records
3 - Quit program
>> 5
You have entered an incorrect value
- What would you like to do?
1 - Store a customer record
2 - View customer Records
3 - Quit program
>> -1
You have entered an incorrect value
- What would you like to do?
1 - Store a customer record
2 - View customer Records
3 - Quit program
>> 1
Please enter the customers details including First name, Lastname and ID.
Enter First name: Harry
Enter Last name: Jones
Enter Customer ID: 654
- What would you like to do?
1 - Store a customer record
2 - View customer Records
3 - Quit program
>> 2
Displaying Infomation
First name: John
Last name: Smith
Customer ID: 123
---
First name: Harry
Last name: Jones
Customer ID: 654
---
- What would you like to do?
1 - Store a customer record
2 - View customer Records
3 - Quit program
>> 3