AVR 9 bit Usart not working (MPCM) - c

Question

So there is Master and Slave Attiny2313. The Master sends the 9 bits of data(the 9th bit TXB8 is set to 1), but the slave doesn't detect the 9th bit(RXB8 is still 0).
I think if the TXB8 bit is set in the Master the RXB8 bit on the Slave should be set automatically, or not? (In the code i check if RXB8 in UCSRB is set to 1.
And it isn't, that is the problem)
void USART_Init(void)
{
/* Set baud rate */
UBRRH = (unsigned char)(BAUDRATE>>8);
UBRRL = (unsigned char)BAUDRATE;
/* Enable receiver and transmitter */
UCSRB = (1<<RXEN)|(1<<TXEN);
/* Set frame format: 9data, 1stop bit */
UCSRC = (7<<UCSZ0);
}
void USART_Transmit(unsigned int data)
{
/* Wait for empty transmit buffer */
while ( !( UCSRA & (1<<UDRE)) );
/* Copy 9th bit to TXB8 */
UCSRB &= ~(1<<TXB8);
if ( data & 0x0100 )
UCSRB |= (1<<TXB8);
/* Put data into buffer, sends the data */
UDR = data;
//Slave Receive Code
gned int USART_Receive( void )
{
unsigned char status, resh, resl;
/* Wait for data to be received */
while ( !(UCSRA & (1<<RXC)) );
/* Get status and 9th bit, then data from buffer */
status = UCSRA;
resh = UCSRB;
resl = UDR;
return resh; ///test
/* If error, return -1 */
if ( status & ((1<<FE)|(1<<DOR)|(1<<UPE)) )
return -1;
/* Filter the 9th bit, then return */
resh = (resh >> 1) & 0x01;
return ((resh << 8) | resl);
}

Answer 1

I found what was the problem, the USART was initialised like this:
/* Enable receiver and transmitter */
UCSRB = (1<<RXEN)|(1<<TXEN);
/* Set frame format: 9data, 1stop bit */
UCSRC = (7<<UCSZ0);
But the UCSZ2 bit is in the USCRB register and not in UCSRC, so the right code will be:
UCSRB = (1<<RXEN)|(1<<TXEN)|(1<<UCSZ2);
UCSRC = (1<<UCSZ0)|(1<<UCSZ1);