Two arrays with different length in a loop - arrays

Question

I have two arrays with different length, and I need to use them in the same loop.
This is the code
#!/bin/bash
data=`date +%Y-%m-%d`
data1=`date -d "1 day" +%Y-%m-%d`
cd /home/test/em_real/
#first array (today and tomorrow)
days="$data $data1"
#second array (00 till 23)
hours="00 01 02 03 04 05 06 07 08 09 10 11 12 13 14 15 16 17 18 19 20 21 22 23"
for value in $hours
do
cp /home/test/em_real/mps_"${days[i++]}"_"$value":00:00 /home/DOMAINS/test_case/
sleep 10
done
Tt fails, doesn't get days.
How can I do it?
#fedorqui If now, inside the bucle, I want to remove the dash (-) of days and do another order, I don't know why it doesn't get the string , the code is the following:
days=("$data" "$data1") #create an array properly
for value in {00..23}; do
for day in "${days[#]}"; do
cp "/path/mps_${day}_${value}:00:00" /another/path/test_case/
d=d01
hourSIMULATION=01
clean= echo ${day} | sed -e 's/-//g'
sed -e 's/<domine>/'$d'/g' -e 's/<data-initial>/'$clean$value'/g' -e 's/<hour-SIMULATION>/'$hourSIMULATION'/g' run_prhours > run_pr
done
done
The string $dayclean is empty when I check inside run_pr, do you know what could be the reason?

Answer 1

You are using days[i++] but no i is defined anywhere. Not sure what you want to do with ${days[i++]} but $days is just a string containing "$data $data1".
You probably want to say days=($data $data1) to create an array.
Also, you can say for hour in {00.23} instead of being explicit on the numbers.
Then, you want to loop through the hours and then through the days. For this, use a nested loop:
days=("$data" "$data1") #create an array properly
for value in {00..23}; do
for day in "${days[#]}"; do
cp "/path/mps_${day}_${value}:00:00" /another/path/test_case/
done
done