Create an XSLT that will convert an array into unique sequential elements - arrays

Question

I am trying to create an XSLT that will convert an array into unique sequential elements. I am probably not explaining this correctly so I will show you:
Current XML
<?xml version="1.0" encoding="UTF-8"?>
<DocumentRequests xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<PlanID>20151014_103605</PlanID>
<LetterType>
<Fund>Yes</Fund>
<Adding>Yes</Adding>
<Bau>Yes</Bau>
</LetterType>
<PlanNumbers>
<PlanNumber>A01</PlanNumber>
<PlanNumber>A02</PlanNumber>
<PlanNumber>A03</PlanNumber>
<PlanNumber>A04</PlanNumber>
<PlanNumber>A05</PlanNumber>
<PlanNumber>A06</PlanNumber>
<PlanNumber>456</PlanNumber>
</PlanNumbers>
</DocumentRequests>
Current XSLT
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="3.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:fn="http://www.w3.org/2005/xpath-functions">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="*">
<SourceFeedbackTransformed>
<PlanAdminID><xsl:value-of select="PlanAdminID" /></PlanAdminID>
<xsl:for-each select="LetterType">
<xsl:copy-of select="*" copy-namespaces="no"/>
</xsl:for-each>
<xsl:for-each select="PlanNumbers">
<xsl:copy-of select="*" copy-namespaces="no"/>
</xsl:for-each>
</SourceFeedbackTransformed>
</xsl:template>
</xsl:stylesheet>
Current output
<?xml version="1.0" encoding="UTF-8"?>
<SourceFeedbackTransformed xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:fn="http://www.w3.org/2005/xpath-functions">
<PlanAdminID/>
<Fund>Yes</Fund>
<Adding>Yes</Adding>
<Bau>Yes</Bau>
<PlanNumber>A01</PlanNumber>
<PlanNumber>A02</PlanNumber>
<PlanNumber>A03</PlanNumber>
<PlanNumber>A04</PlanNumber>
<PlanNumber>A05</PlanNumber>
<PlanNumber>A06</PlanNumber>
<PlanNumber>456</PlanNumber>
</SourceFeedbackTransformed>**
Desired Output
<?xml version="1.0" encoding="UTF-8"?>
<SourceFeedbackTransformed xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:fn="http://www.w3.org/2005/xpath-functions">
<PlanAdminID/>
<Fund>Yes</Fund>
<Adding>Yes</Adding>
<Bau>Yes</Bau>
<PlanNumber1>A01</PlanNumber1>
<PlanNumber2>A02</PlanNumber2>
<PlanNumber3>A03</PlanNumber3>
<PlanNumber4>A04</PlanNumber4>
<PlanNumber5>A05</PlanNumber5>
<PlanNumber6>A06</PlanNumber6>
<PlanNumber7>456</PlanNumber7>
</SourceFeedbackTransformed>
As you can see the Array with 7 values has been converted to 7 different elements.
Thank you for your help.
Cheers,

Answer 1

You can get the result you're after quite easily by:
XSLT 2.0
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/DocumentRequests">
<SourceFeedbackTransformed>
<PlanAdminID><xsl:value-of select="PlanID" /></PlanAdminID>
<xsl:copy-of select="LetterType/*" copy-namespaces="no"/>
<xsl:for-each select="PlanNumbers/PlanNumber">
<xsl:element name="PlanNumber{position()}">
<xsl:value-of select="."/>
</xsl:element>
</xsl:for-each>
</SourceFeedbackTransformed>
</xsl:template>
</xsl:stylesheet>
Note:
I have changed your:
<xsl:value-of select="PlanAdminID" />
to:
<xsl:value-of select="PlanID" />
as there is no PlanAdminID element in your input. If you really want to output an empty <PlanAdminID/> element as shown in your requested output, then you could do so directly, without fetching the value of a non-existing node.