Adding binary numbers in C - c

Question

Im getting the error "invalid operands to binary + (have int* and int*)" and i don't know why It is throwing me this error. how would I go about adding the array elements of the 2 arrays. note both arrays are the same size.
int* complement2_add(int* first_complement2[], int* second_compelment[], int size){
int count = 0,remainder = 0, carryover = 0;
int* cAdd = (int*)malloc(size*sizeof(int));
for(count = size-1; count >= 0; count--){
remainder = first_complement2[count] + second_compelment[count] + carryover;
if(remainder == 1){
cAdd[count] = 1;
carryover = 0;
}
else if(remainder == 2){
cAdd[count] = 0;
carryover = 1;
}
else if(remainder == 3){
cAdd[count] = 1;
carryover = 1;
}
else if(remainder == 0){
cAdd[count] =0;
carryover = 0;
}
}
if(carryover == 1){
cAdd[count] = 1;
}
return cAdd;
}
Then I am calling the function in main like this.
int* add1 = complement_2_add(complement2Array1, complement2Array2, j);
Complement2Array1 and Complement2Array2 are defined the same.
int* complement2Array1 = signed2complement2(signedIntArray1, j);
and signed2complement2 is defined as.
int* signed2complement2(int signed_binary[], int size){
int i = 0;
int* complemt2Array = (int*)malloc(size*sizeof(int));
int flipflag = 0;
for(i = size-1; i>=0;i-- ){
if(flipflag == 0){
complemt2Array[i] = signed_binary[i];
if(signed_binary[i] == 1){
flipflag = 1;
}
}
else{
complemt2Array[i] = signed_binary[i] == 0?1:0;
}
}
return complemt2Array;
}

Answer 1

remainder = first_complement2[count] + second_compelment[count] + carryover;
In this first_complement2[count] , second_compelment[count] both are integer pointers .
As both first_complement and second_complement are array of integer pointers.
You need to dereference them before adding -
remainder = (*first_complement2[count]) + (*second_compelment[count]) + carryover;
EDIT
Didn't you got any warning or error for passing a int * to a function which expects array of integer pointer or int ** ?
int* complement2Array1 = signed2complement2(signedIntArray1, j); // it is an int *
complement2Array1 and complement2array2 has to be of type int ** or to be array of int pointers.
Or simple as #alk Sir suggested use int * instead of int **.

Answer 2

This
int* complement2_add(int* first_complement2[], int* second_compelment[], int size){
if equal to
int* complement2_add(int ** first_complement2, int ** second_compelment, int size){
which from the way you use first_complement2 and second_compelment and the way you call complement2_add() is wrong.
It seems you wanted
int* complement2_add(int * first_complement2, int * second_compelment, int size){
Also add the prototype to it before it is used:
int* complement2_add(int * first_complement2, int * second_compelment, int size);
... somefunc(...)
{
...
int* add1 = complement_2_add(complement2Array1, complement2Array2, j);
...
}
int* complement2_add(int* first_complement2, int* second_compelment, int size)
{
int count = 0,remainder = 0, carryover = 0;
...