Violating static function in C - c

Question

In one interview I was asked, if in one file A, some static function is defined and in file B you want to use this static function -- how you will use it?
My answers were:
declaring in .h file
But if we declare that in a header file, other files which will include this also have access to this static function.
wrapper concept: Declaring a new function newfun in file A, which will call static function and calling this newfun in file B.
But he was not satisfied with these answers.
Can you please provide me some better solution to violate static.

Answer 1

Perhaps they wanted to hear about function pointers?
You can create a pointer to the function, and call it using that pointer.
One possible scenario where this is reasonable is if you have a callback function that you don't want to be callable by everyone, and you give the pointer as an argument to some register_callback function.
Callback functions were used extensively, for example to let the user of a GUI API provide code for what should happen when a button is pressed. Nowadays, with object-oriented languages, it is more common to subclass a class and define or override methods, such as the Android View class and the method OnClickListener, but C# delegates are very similar to C function pointers.
To illustrate the principle, here is the source code (the file "B" in the original question) for some sort of library, where the main component is the do_stuff function:
#include <stdio.h>
#include "some_library.h"
void (*stored_callback)(void) = NULL;
void register_callback(void (*callback)(void)) {
stored_callback = callback;
}
void do_stuff(void) {
printf("Doing stuff...\n");
printf("Calling callback...\n");
if (stored_callback != NULL)
stored_callback();
}
This header, some_library.h, file shows the API of that library:
extern void register_callback(void (*callback)(void));
extern void do_stuff(void);
And here is how the library is used (the file "A" in the question):
#include <stdio.h>
#include "some_library.h"
static void my_callback(void) {
printf("Inside the callback!\n");
}
int main(void) {
register_callback(my_callback);
do_stuff();
return 0;
}

Answer 2

My interview answer would be "You can't."
(Because the question says "in file B you want to use this static function" and it didn't say you are allowed to modify file A.)

Answer 3

I'm assuming you don't have access to the source of the static function or else you could just remove the static keyword or expose the function via an exported wrapper or global function pointer.
You can still use the static function if you use objcopy to manually change the visibility on the symbol in the object file / library.
Suppose this is the (unaccessible) static function:
//static.c
#include <stdio.h>
static void fun(){
puts("Hello world");
}
Suppose you only have static.o, obtainable with gcc -c static.c.
Now, let's assume you want to link static.o with main.o made from
//main.c
void fun();
void main(){
fun();
};
To be able to link it, you need to turn
$ nm static.o
0000000000000000 t fun
U puts
into
0000000000000000 T fun
U puts
You can do that with:
objcopy --globalize-symbol=fun static.o global.o
Now you can link with global.o instead of static.o.
$ gcc main.o global.o && ./a.out
Hello world

Answer 4

filea.c
#include <stdio.h>
#include "filea.h"
static void hidden(void) { printf("inside hidden function.\n"); }
fxptr unhide(void) { return hidden; }
filea.h
#ifndef FILEA_INCLUDED
#define FILEA_INCLUDED
typedef void(*fxptr)(void);
fxptr unhide(void);
#endif
fileb.c
#include "filea.h"
int main(void) {
unhide()();
return 0;
}