Split Data and transforming them into Columns - sql-server

Question

I have an Input table as under
Id Data
1 Column1: Value1
2 Column2: Value11
3 Column3: Value111
4 Column1: Value2
5 Column2: Value22
6 Column3: Value222
I am looking for an output as under
Column1 Column2 Column3
Value1 Value11 Value111
Value2 Value22 Value222
How can I achieve so? It could have been done easily by using a WHILE LOOP and by a bit of mathematical logic, but I am looking for a more optimized one if possible by only SELECT queries (no LOOPS).
I have tried also by splitting using (':') as delimiter and then transforming ROWS to COLUMNS (PIVOT) but somewhat could not be able to proceed. (That's my thought, peoples may have more better thoughts).
My shot so far
Declare #t table(Id int identity(1,1),Data varchar(1000))
Insert into #t Values
('Column1: Value1'),('Column2: Value11'),('Column3: Value111')
,('Column1: Value2'),('Column2: Value22'),('Column3: Value222')
Select *
FROM #t
SELECT
F1.id,
F1.Data,
O.splitdata
FROM
(
SELECT *,
cast('<X>'+replace(F.Data,':','</X><X>')+'</X>' as XML) as xmlfilter from #t F
)F1
CROSS APPLY
(
SELECT fdata.D.value('.','varchar(50)') as splitdata
FROM f1.xmlfilter.nodes('X') as fdata(D)) O

Answer 1

This will work if you want a pure SQL solution:
Select [Column1], [Column2], [Column3] From (
Select col, val, id = ROW_NUMBER() over(partition by d.col order by d.id)
From (
Select id
, col = LEFT(Data, CHARINDEX(':', Data)-1)
, val = RIGHT(Data, LEN(DATA) - CHARINDEX(':', Data))
From #t
) as d
) as p
pivot(
MAX(val)
FOR col in([Column1], [Column2], [Column3])
) as piv
But it supposes that data for Row 1 are always before data for Row 2. There is no way to distinguish them using your sample.
If the number of column is not fixed, it has to use Dynamic SQL.
SQL Server may not be the best options for this kind of thing.
With Dynamic SQL, the above query would be like this one:
create table #t(Id int identity(1,1),Data varchar(1000))
Insert into #t Values
('Column1: Value1'),('Column2: Value11'),('Column3: Value111')
,('Column1: Value2'),('Column2: Value22'),('Column3: Value222')
Declare #sql nvarchar(max)
Select #sql = '
Select '+left(c, len(c)-1)+' From (
Select col, val, id = ROW_NUMBER() over(partition by d.col order by d.id)
From (
Select id
, col = LEFT(Data, CHARINDEX('':'', Data)-1)
, val = RIGHT(Data, LEN(DATA) - CHARINDEX('':'', Data))
From #t
) as d
) as p
pivot(
MAX(val)
FOR col in('+left(c, len(c)-1)+')
) as piv
'
From (
Select Distinct '['+LEFT(Data, CHARINDEX(':', Data)-1)+'], '
From #t
FOR XML PATH('')
) as d(c)
EXEC sp_executesql #sql
SQL Fiddle

Answer 2

This should work:
Declare #t table(Id int identity(1,1),Data varchar(1000))
Insert into #t Values
('Column1: Value1'),('Column2: Value11'),('Column3: Value111')
,('Column1: Value2'),('Column2: Value22'),('Column3: Value222');
WITH Splitted AS
(
SELECT *
,CAST('<X>'+REPLACE(F.Data,':','</X><X>')+'</X>' AS XML) AS xmlfilter
FROM #t AS F
)
SELECT p.*
FROM
(
SELECT ROW_NUMBER() OVER(PARTITION BY xmlfilter.value('X[1]','varchar(max)') ORDER BY Id) AS Inx
,xmlfilter.value('X[1]','varchar(max)') AS ColName
,xmlfilter.value('X[2]','varchar(max)') AS ColVal
FROM Splitted
) AS tbl
PIVOT
(
MAX(ColVal) FOR ColName IN(Column1,Column2,Column3)
) AS p