I want to code a simple bean machine program. The program will accept user input for the number of balls and the number of slots, and will calculate the path of each ball. The number of balls in each slot will be printed as a histogram as well.
I tried my best to keep the code short and sweet, yet the best I have managed is 112 lines long. When I ran my code, I received no errors. However, the output seems to have run into some sort of an infinity loop (The '#' symbol which was used to represent numbers in the histogram keeps on printing forever for some reason unknown to me).
Apparently, there is something wrong with my logic somewhere... or a silly little mistake in syntax(but it would have shown up as error, wouldn't it?)... In a nutshell, I cannot figure out exactly what is the problem. (I attempted to walk through the whole code process from start to finish, but my mind kept getting tangled up somewhere in the middle of the code, nowhere near the end of the code either).
Where exactly does my logic go wrong?(Or have I taken the wrong approach to the whole problem?) I do not wish to know the correct code, so that I am able to learn during the whole process of re-editing my code.
Any help (hopefully no model-code answers though), even as a single comment, is tremendously appreciated! :)
This is my code:
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
#include <conio.h>
#include <stdbool.h>
#include <time.h>
//Pls excuse my extensive use of libraries even though I don't really use them
int intchecker(float x)
{
if (floor(x)==x && ceilf(x)==x)
{
return 0;
}
else {
return 1;
}
}
int main(){
char line[] = " +----+----+----+----+----+----+----+----+----+----+---+";
char numbers[] = " 0 5 10 15 20 25 30 35 40 45 50";
float balls,slots;
int slotarry[9],tlevel,ballnum,column,lcounter=0,slotsduplicate=1,y;//tlevel-number of levels in the triangle
srand(time(NULL));
int r;
printf("==========================================================\nGalton Box Simulation Machine\n==========================================================\n");
printf("Enter the number of balls [5-100]: ");
scanf("%f",&balls);
while (balls>100 || balls<5) {
printf("\nInput is not within the range. Please try again.");
printf("\nEnter the number of balls [5-100]: ");
scanf("%f",&balls);
}
while (intchecker(balls)==1) {
printf("\nInput is not an integer. Please try again.");
printf("\nEnter the number of balls [5-100]: ");
scanf("%f",&balls);
}
printf("Enter the number of slots [2-10] : ");
scanf("%f",&slots);
while (slots>10 || slots<2) {
printf("\nInput is not within the range. Please try again.");
printf("\nEnter the number of slots [2-10] : ");
scanf("%f",&slots);
}
while (intchecker(slots)==1) {
printf("\nHow can there be a fraction of a slot? Please re-enter slot number.");
printf("\nEnter the number of slots [2-10] : ");
scanf("%f",&slots);
}
tlevel=slots-1;
for(ballnum=1,column=0;balls>0;balls--,ballnum++,column++){
if (column%5==0){
printf("\n");
}
if (ballnum<10){
printf("[0%d]",ballnum);
}
else{
printf("[%d]",ballnum);
}
for(;tlevel>0;tlevel--){
r = rand() % 2;
if (r==0){
printf("R");
}
else {
printf("L");
lcounter++;
}
}
slotarry[lcounter]++;
tlevel=slots-1;
lcounter=0;
printf(" ");
}
printf("\n\n%s",numbers);
printf("%s",line);
char line2[] = "\n +----+----+----+----+----+----+----+----+----+----+---+";
for(;slotsduplicate<=slots;slotsduplicate++){
if (slotsduplicate<10){
printf("0%d|",slotsduplicate);
}
else{
printf("%d|",slotsduplicate);
}
y=slotarry[slotsduplicate];
if (y==0){
printf(" 0");
}
else{
for (;y>0;y--){
printf("#");
}
printf(" %d",slotarry[slotsduplicate]);
}
printf("%s",line2);
}
return 0;
}
Note:This is not completely error-free. This is just my first draft. I just wish to find out why there is an infinite loop.
Here's how I found the problem. First of all, I think it is a bit of a code smell to have a for loop without anything in the initial assignment section. Couple that with the fact that it seems to print # forever, and it looks like y has a garbage value at the beginning of the loop to print the #s.
So I ran your code in the debugger and paused it when it started printing loads of hashes. I checked the value of y and sure enough it was some unfeasibly high number.
Then I checked where y comes from and found you get it from slotarray. I printed it in the debugger and found that all the values in it were unfeasibly high or massively negative numbers. Obviously, slotarray wasn't being initialised correctly, so I looked for where it was initialised and bingo!
Stack variables (of which slotarray is one) must be explicitly initialised in C. I fixed your code with a call to memset.
The whole debugging process I have just outlined took something less than a minute.
ETA As #EOF points out, there is another bug in that slotarray is defined to contain nine slots (indexed 0 - 8) but you allow people to enter 10 slots. This is a buffer overflow bug.
Related
When running my program through cs50's submit50 check, everything works besides validating 4222222222222 as VISA (instead of INVALID) is output. When I print out the count variable before, then sometimes VISA is output. Any solutions would be much appreciated as I cannot seem to properly fix this.
INSTRUCTIONS: Write a program that prompts the user for a credit card number and then reports (via printf) whether it is a valid American Express, MasterCard, or Visa card number, per the definitions of each’s format herein. So that we can automate some tests of your code, we ask that your program’s last line of output be AMEX\n or MASTERCARD\n or VISA\n or INVALID\n, nothing more, nothing less
#include <stdio.h>
#include <cs50.h>
int main(void)
{
//get input from user
long CardNum = get_long("Input credit card number:");
bool nvalid = true;
//count number of digits
int count = 0;
long temp1num = CardNum;
while (temp1num > 0)
{
temp1num = temp1num / 10;
count++;
}
//printf("%i\n", count);
if (!(count == 13 || count == 15 || count == 16))
{
printf("INVALID\n");
}
else
{
.....
The problem arises in the beginning of the code so I only copied that part.
Mastercards always starts with either 5 or 2 and has a length of 16.
Visa cards always start with a 4 and can have a length of 13-16-19.
You are close. Try adding an additional condition for the supported lengths for VISA in your if statement it should solve your problem. Or, why not just check if the card length is either 13 - 19? It seems like it's failing because Visa supports different card lengths.
I have an awesome helper method that determines card types that's extremely handy but it's in C#.
Hello I'm new to c and i'm currently learning with my university curriculum so i need to abide by these rules: We can't use arrays or global variables.
So i've been trying to make a dice game named "big pig". I'm right now creating the function the computer is going to use to play the game called "play_computer()". There is also a function called "computer_strategy_decider()".Computer_strategy_decider() is supposed to pick from yes or no. I just made a rand function that calls either 1 or 2 to make that work. Play_computer() let's you pick two dices and from there it needs to calculate the score. If you pick only one one, then your score doesn't increase and your game is terminated. If you et two ones you get 25 added. If you get any other double value for example a , is added such as (a+a)*2 or 4*a. And lastly if you get two random numbers the computer gets to decide if it wants to continue. That's where the computer_strategy_decider() comes in..
The problem comes with the play_computer() function. Everything seems to be working well when the computer rolls two different values and doesn't continue. It terminates ok. But if it wants to continue it goes in an infinite loop. The infinite loop also has the same dice values.
The same loop happens when doubles are rolled. Something in my code doesn't loop properly. I don't know whether it is something to do with rand() or not. I don't think it's rand() since i use rand() on computer_strategy_decider(). My theory is it's hopefully something small i have missed.
My code was working an hour ago before i added some changes so that's why im frustrated haha.
#include <stdio.h>
#include <math.h>
#include <stdlib.h>
#include <time.h>
int computer_strategy_decider(){
int deci;
srand(time(NULL));
deci=1+ (int) rand() % 2;
return deci;}
int play_computer(round_number,strategy){
int roll_1,roll_2,cntrl_var=0,score_comp=0;
char answ;
printf("\nRound %d-- My Turn:",round_number);printf("\n---------------------------------");
while(cntrl_var==0){
srand(time(NULL));
roll_1 = 1 + (int) rand() % 6;
roll_2 = 1 + (int) rand() % 6;
printf("\nI got --> [Dice 1]: %d [Dice 2]: %d",roll_1,roll_2);
if(roll_1==roll_2 && roll_1!=1){
score_comp=score_comp+roll_1*4;
printf("\nScore: %d",score_comp);printf("\nDoubles! Roll again!");}
else if(roll_1==1 && roll_2==1){
score_comp=score_comp+25;
printf("\nScore: %d",score_comp);printf("\nDoubles! Roll again!");}
else if(roll_1==1 || roll_2==1){
cntrl_var=1;
printf("\nYou got a single one! End of your turn!");}
else{
score_comp=score_comp+roll_1+roll_2;
printf("\nScore: %d",score_comp);
while(cntrl_var==0){
printf("\nDo you want to continue (Y/N)?");
if (strategy==1){
printf("Y");
break;}
else if (strategy==2){
printf("N");
break;}}
if (strategy==1)
cntrl_var=0;
else if (strategy==2)
cntrl_var=1;
else
cntrl_var=0;}}
printf("\nMy Score: %d",score_comp);
return score_comp;}
int main(){
int round_no=1,deci;
deci=computer_strategy_decider();
play_computer(round_no,deci);
}
I put the srand in the while loop and that caused the srand to be called multiple times. So i put the srand above the loop. That fixed it!
I have a library from WiringPi for DHT11 sensor and I need to modify condition which checks if the value read from sensor is good.
Sometimes the library reads bad values which are 255.255,255.255 or 55,255.255 etc.
sample output
There is the condition in the library:
if(counter==255)
break;
But it doesn't work if the value is e.g. 55,255.255
How can I modify this condition the check last 3 digits of output?
If the output is wrong, there are always "255" at the end of value.
I tried to add conditions like
if(counter==255)
break;
else if(counter==255.255)
break;
But it doesn't solve all possible situations and I realy don't know anything about C/C++
Here is the whole library:
#include <wiringPi.h>
#include <stdio.h>
#include <stdlib.h>
#include <stdint.h>
#define MAX_TIME 85
#define DHT11PIN 7
#define ATTEMPTS 5
int dht11_val[5]={0,0,0,0,0};
int dht11_read_val()
{
uint8_t lststate=HIGH;
uint8_t counter=0;
uint8_t j=0,i;
for(i=0;i<5;i++)
dht11_val[i]=0;
pinMode(DHT11PIN,OUTPUT);
digitalWrite(DHT11PIN,LOW);
delay(18);
digitalWrite(DHT11PIN,HIGH);
delayMicroseconds(40);
pinMode(DHT11PIN,INPUT);
for(i=0;i<MAX_TIME;i++)
{
counter=0;
while(digitalRead(DHT11PIN)==lststate){
counter++;
delayMicroseconds(1);
if(counter==255)
break;
}
lststate=digitalRead(DHT11PIN);
if(counter==255)
break;
// top 3 transistions are ignored
if((i>=4)&&(i%2==0)){
dht11_val[j/8]<<=1;
if(counter>16)
dht11_val[j/8]|=1;
j++;
}
}
// verify checksum and print the verified data
if((j>=40)&&(dht11_val[4]==((dht11_val[0]+dht11_val[1]+dht11_val[2]+dht11_val[3])& 0xFF)))
{
printf("%d.%d,%d.%d\n",dht11_val[0],dht11_val[1],dht11_val[2],dht11_val[3]);
return 1;
}
else
return 0;
}
int main(void)
{
int attempts=ATTEMPTS;
if(wiringPiSetup()==-1)
exit(1);
while(attempts)
{
int success = dht11_read_val();
if (success) {
break;
}
attempts--;
delay(500);
}
return 0;
}
No single variable in your code can hold "255.255", that would require a string or a float. You are obviously referring to the output of
printf("%d.%d,%d.%d\n",dht11_val[0],dht11_val[1],dht11_val[2],dht11_val[3]);.
This printf can never produce a three-value output like 55,255.255.
I assume that your output would be 55.255,255.255.
This in turn means that in case of error you will find the "last three digits" in dht11_val[3].
If my assumption is not correct please provide much more detail on the error circumstances.
On the other hand, I suspect that looking for that value is not the solution for your problem either. The function is more complicated. The value of 255 seems the result of an endless loop which is detected by breaking early at counter = 255. So I am pretty sure that checking "the last three digits" is a LESS precise check than what is already implemented.
Hey guys I have created a program in C that tests all numbers between 1 and 10000 to check if they are perfect using a function that determines whether a number is perfect. Once it finds these it prints them to the user, they are 6, 28, 496 and 8128. After this the program then prints out all the factors of each perfect number to the user. This is all fine. Here is my problem.
The final part of my task asks me to:
"Use a "twirly" to indicate that your program is happily working away. A "twirly" is the following characters printed over the top of each other in the following order: '|' '/' '-' '\'. This has the effect of producing a spinning wheel - ie a "twirly". Hint: to do this you can use \r (instead of \n) in printf to give a carriage return only (instead of a carriage return linefeed). (Note: this may not work on some systems - you do not have to do it this way.)"
I have no idea what a twirly is or how to implement one. My tutor said it has something to do with the sleep and delay functions which I also don't know how to use. Can anyone help me with this last stage, it sucks that all my coding is complete but I can't get this "twirly" thing to work.
if you want to simultaneously perform the task of
Testing the numbers and
Display the twirly on screen
while the process goes on then you better look into using threads. using POSIX threads you can initiate the task on a thread and the other thread will display the twirly to the user on terminal.
#include<stdlib.h>
#include<pthread.h>
int Test();
void Display();
int main(){
// create threads each for both tasks test and Display
//call threads
//wait for Test thread to finish
//terminate display thread after Test thread completes
//exit code
}
Refer chapter 12 for threads
beginning linux programming ebook
Given the program upon which the user is "waiting", I believe the problem as stated and the solutions using sleep() or threads are misguided.
To produce all the perfect numbers below 10,000 using C on a modern personal computer takes about 1/10 of a second. So any device to show the computer is "happily working away" would either never be seen or would significanly intefere with the time it takes to get the job done.
But let's make a working twirly for perfect number search anyway. I've left off printing the factors to keep this simple. Since 10,000 is too low to see the twirly in action, I've upped the limit to 100,000:
#include <stdio.h>
#include <string.h>
int main()
{
const char *twirly = "|/-\\";
for (unsigned x = 1; x <= 100000; x++)
{
unsigned sum = 0;
for (unsigned i = 1; i <= x / 2; i++)
{
if (x % i == 0)
{
sum += i;
}
}
if (sum == x)
{
printf("%d\n", x);
}
printf("%c\r", twirly[x / 2500 % strlen(twirly)]);
}
return 0;
}
No need for sleep() or threads, just key it into the complexity of the problem itself and have it update at reasonable intervals.
Now here's the catch, although the above works, the user will never see a fifth perfect number pop out with a 100,000 limit and even with a 100,000,000 limit, which should produce one more, they'll likely give up as this is a bad (slow) algorithm for finding them. But they'll have a twirly to watch.
i as integer
loop i: 1 to 10000
loop j: 1 to i/2
sum as integer
set sum = 0
if i%j == 0
sum+=j
return sum==i
if i%100 == 0
str as character pointer
set *str = "|/-\\"
set length = 4
print str[p] using "%c\r" as format specifier
Increment p and assign its modulo by len to p
i'm trying to create a 'game' in C programming which throws 2 dices for the user, throws 2 dices for the PC, and whoever gets the bigger sum wins,
when i debug it in visual studio i see good results both in the variable values and the console window, but when i run it without debugging the user and the PC both always get the same value for their dices (user gets 2 and 2, and PC gets 2 and 2, for example).
Can anyone solve it? i looked at it for the last 3 hours and i just can't find what's the problem.
#define _CRT_SECURE_NO_WARNINGS
#include <stdlib.h>
#include <stdio.h>
#include <time.h>
int throwDice();
int diceSum();
int main()
{
int res1;
res1=diceSum();
if(res1==0)
printf("It is a tie!\n");
if(res1==1)
printf("You Won!\n");
if(res1==-1)
printf("You Lost\n");
}
int throwDice()
{
int i;
srand((unsigned)time(NULL));
i = (rand()%(6-1)) + 1;
return i;
}
int diceSum()
{
int j,a=0,b,c=0,d=0;
int array[4];
for(j=1;j<=2;j++)
{
array[c]=throwDice();
a=a+array[c];
c++;
}
for(b=1;b<=2;b++)
{
array[c]=throwDice();
d=d+array[c];
c++;
}
printf("You got %d and %d.\nYour opponent got %d and %d.\n",array[0],array[1],array[2],array[3]);
if(a==d)
return 0;
if(a>d)
return 1;
else
return -1;
}
Everytime you call throwDice, you are re-initializing your random number generator with the current time.
The accuracy of time is only 1-second, so in a single run of this program, the time doesn't change, so you get the same results.
You are supposed to call srand ONLY ONCE, near the start of your program.
From the documentation
"Two different initializations with the same seed will generate the same succession of results in subsequent calls to rand."
The random number generator doesn't just pull random numbers out of nowhere. When you seed it you're giving it a good number to start with, and from there it can generate a bunch of random numbers.
The problem is, it will give you a sequence of random numbers, but that sequence will be the same if you give it the same seed twice in a row. That's why it's important that the value you seed it with is relatively random. And hey, the time is pretty random, what are the chances two people will end up running the program at exactly the same time?
What you're doing, is seeding the generator before every call to rand, instead of seeding it at the beginning and letting the random number generator do its job. Since time only returns the time in seconds (see man page), you'll get the same number every time the loop runs until the start of the next second.