Linked list basic advice for beginner is needed - c

Question

Teacher said write program with four functions (print size or add, remove and print node). In line 17 error comes (Cannot convert int* into node). I can't find other way to represent this line so please help. Since it's my first experience with linked list, you can expect tons of error.
#include<conio.h>
#include<stdio.h>
#include<stdlib.h>
struct node{ // Declaring the node (2 way)
int n;
struct node *next;
struct node *prev;
};
int *header; //Declaring header and size counter
int size;
int *finder(int number) //Function that return address of selected node
{
int *adr;
int c;
struct node *temp;
temp=header;
c=0;
while(c==number)
{
temp=temp->next;
c=c+1;
}
return adr;
}
void insert(int data,int number) //insert new node after specified node
{
int *adr;
adr=finder(number);
struct node *current;
struct node *previous;
struct node *temp;
temp=(struct node *)malloc(sizeof(struct node));
current=adr;
previous=current->prev;
temp->n=data;
temp->next=current;
temp->prev=current->prev;
previous->next=temp;
current->prev=temp;
size=size+1;
}
void remove(int number) //remove node after selected one
{
int *adr;
adr=finder(number);
struct node *current;
struct node *previous;
struct node *neeext;
current=adr;
previous= current->prev;
neeext= current->next;
previous->next= neeext;
neeext->prev= previous;
}
void print(int number) //print data of node
{
int *adr;
adr=finder(number);
struct node *current;
printf("%d",current->n);
}
int main() //main function
{
int i,j,d;
size=0;
for(i=1;i<5;i=i+0)
{
if(i==1)
{
printf("%d",size);
}
scanf("%d",&j);
if(i==2)
{
scanf("%d",&d);
insert(d,j);
printf("inserted");
}
if(i==3)
{
remove(j);
printf("removed");
}
if(i==4)
{
print(j);
}
if(i==5)
{
return 0;
}
scanf("%d",&i);
printf("\n");
}
}

Answer 1

You should declare your header variable as struct node *header;, not as int*