Make default statement not exit (C) - c

Question

I am a beginner in C programming and I'm trying to do basic stuff. I'm trying to create a simple menu using a switch statement like this:
int disp(){
int check;
while(check!=1){
int choose;
printf("1 \n");
printf("5quit\n");
scanf("%d", &choose);
switch(choose)
{
case 1:func1();
break;
case 5: check = 1;
break;
default:
printf("wrong input");
}
return 0;
}
}
However, when either default or case 1 happen, I want to make it still loop the menu until a good input is made. For example, if I enter random stuff like "asdf", the program should say "wrong input" and then display the menu again and wait for user input. And if user enters "1", the program will run func1 and then go back to the menu and wait for the user to input a choice.
Currently, when a wrong input happens it just shuts down the program instead of displaying the menu again, and I don't know how to solve that.

Answer 1

Your return 0 statement is inside of your while loop. Move it down one line, outside of the loop.
This is one reason why proper indentation is important.
At this point, entering in non-numeric input results in an infinite loop because scanf isn't reading in anything. To remedy this, you call getchar in a loop after calling scanf to flush the buffer:
int c;
scanf(" %d", &choose);
while ((c=getchar()) != EOF && c != '\n');

Answer 2

This is correct and close to what you want
// Use a proper formatting standard to improve readability
int disp() {
int check = 0; // Initialize the loop variable
while (check != 1) {
int choose;
printf("1 \n");
printf("5quit\n");
scanf("%d\n", &choose); // Ask the scanf to swallow the newline
switch(choose) {
case 1:
func1();
break;
case 5:
check = 1;
break;
default:
printf("wrong input");
}
}
return 0; // Pull the statement out of the loop
}
EDIT: Since you are providing invalid input intentionally, it's better to check the return value of scanf to avoid errors.