C - create members of struct in loop? - c

Question

I am new to C programing and want to write a program that reads a line of integers and then creates a member of a struct for each of them. Here is a simplified example:
Let’s say this is the line: *23 4 12 56 78 *
and the struct looks like this:
struct structure
{
int index;
int number;
};
The first member should look like this:
struct structure member0;
member0.index = 0;
member0.number = 23;
But I want the program to be able to read lines of any length, so I want a loop that, whenever an integer is read, creates a new member using the number read and a counter that sets the name and index to previous index + 1 and I would like to know if and how it is possible to do so.

Answer 1

It can be done
Use fgets() to read the line
Break the line into tokens using strtok()
Convert each token to integer using atoi() or strtol()
Keep some variable say i which you need to increment for each token and should be reset after each fgets() call
Have dynamic or static array of your structure to hold the above information

Answer 2

Use strtol(), you'd want something along this line..
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <errno.h>
#define MAX_SIZE 100
typedef struct _TMember
{
int index;
int number;
} TMember;
int main()
{
TMember arr[MAX_SIZE] = {};
char szNumbers[] = "10 20 30 40 50";
char *pEnd;
long int li;
unsigned short index = 0;
pEnd = szNumbers;
for( ; ; )
{
char *tmp = pEnd;
li = strtol( pEnd, &pEnd, 10 );
if( tmp == pEnd )
{
break;
}
else
{
arr[index].index = index;
arr[index].number = li;
index++;
}
}
for( int i = 0; i < index; i++ )
{
printf( "Member %d, idx = %d, number = %d\n", i, arr[i].index, arr[i].number );
}
return 0;
}