SQL Server 2012: How to find common values in a column - sql-server

Question

SQL Server 2012: How to find common values in a column
Please find below my exact requirement and help me with the Fine tuned query.
Please find below my exact requirement and help me with the Fine tuned query.
Please find below my exact requirement and help me with the Fine tuned query.
Input :
select 1, 'sankar', 'GROUPLG'
union all
select 1, 'sankar', 'GROUPLS'
union all
select 1, 'sankar', 'GROUPNG'
union all
select 1, 'sankar', 'GROUPNS'
union all
select 2, 'Srini', 'HYDRSPMLG'
union all
select 2, 'Srini', 'HYDRSPMLS'
union all
select 3, 'Ravi', 'AADSCLS'
union all
select 4, 'Arun', 'RREDFTLS'
union all
select 4, 'Arun', 'RREDFTNG'
union all
select 5, 'Raja', '1234567'
union all
select 5, 'Raja', 'ABCDESLS'
union all
select 5, 'Raja', 'ABCDESLG'
union all
select 6, 'Dhilip', 'GGGGRASCDW_RV'
Output :
-- 1 Sankar GROUP(LG,LS,NG,NS)
-- 2 Srini HYDRSPM(LG,LS)
-- 3 Ravi AADSCLS
-- 4 Arun RREDFT(LS,NG)
-- 5 Raja 1234567
-- 5 Raja ABCDESLG(LG,LS)
-- 6 dhilip GGGGRASCDW_RV

Answer 1

Using FOR XML PATH('') to concatenate the groups:
SQL Fiddle
SELECT
t.Userid,
t.Username,
Groupname = 'GROUP(' +
STUFF((
SELECT ',' + STUFF(GroupName, 1, 5, '')
FROM tbl
WHERE Userid = t.Userid
FOR XML PATH(''), TYPE).value('.', 'NVARCHAR(MAX)')
, 1, 1, '') + ')'
FROM tbl t
GROUP BY t.Userid, t.Username
DROP TABLE tbl
RESULT:
| Userid | Username | Groupname |
|--------|----------|--------------------|
| 1 | sankar | GROUP(LG,LS,NG,NS) |
| 2 | Srini | GROUP(LG,LS) |
| 3 | Aathi | GROUP(LS) |

Answer 2

Try the below code snippet -
select a.userid,a.username,
CASE WHEN PATINDEX('%,%',a.groupname) > 0 THEN
LEFT(a.groupname,PATINDEX('%,%',a.groupname)-3)+'('+REPLACE(a.groupname,LEFT(a.groupname,PATINDEX('%,%',a.groupname)-3),'')+')'
ELSE a.groupname
END as groupname
from
(select userid,username,
stuff((
select ',' + t.[Groupname]
from #users t
where t.Userid = t1.userid
order by t.[Groupname]
for xml path('')
),1,1,'') as groupname
from #users t1
group by userid,Username) a
Edit: Changed the code as per the requirement. Please re-check now.

Answer 3

Assuming userid + username combination is unique, please try following query. Also considering that you don't need parenthesis around group in case of a single group, I'v updated the below query.
explanation: I've used STUFF function to calculate the grouping of groups with a comma followed by every group code like LS,LG,
Now based on comparison of position of comma using CHARINDEX with length of string using LEN, we attach the logic either adding GROUP() or GROUP to the string
select
userid,
username,
CASE
WHEN CHARINDEX(',',groupname)<LEN(groupname)
THEN 'GROUP('+ SUBSTRING(groupname,1,LEN(groupname)-1) +')'
ELSE 'GROUP'+SUBSTRING(groupname,1,LEN(groupname)-1)
end as groupname
from
(
select
userid,
username,
stuff((
select
replace(groupname,'group','') + ','
from tbl
where
userid=t.userid and username=t.username
for xml path(''),type).value('.','varchar(max)'),1,0,'')
as groupname
from tbl t
group by userid, username
)t
and updated
sql fiddle link http://sqlfiddle.com/#!6/21f65/1
gives this exact output
Userid Username Groupname
1 Sankar GROUP(LG,LS,NG,NS)
2 Srini GROUP(LG,LS)
3 Aathi GROUPLS

Answer 4

Finally i have succeeded by the below query which i have developed. Thanks for you all. If you want You can copy the below query and execute in SSMS.
begin tran
Create table #temp (userid int, username varchar(50), groupname varchar(50))
insert into #temp(userid , username , groupname)
select 1, 'sankar', 'GROUPLG'
union all
select 1, 'sankar', 'GROUPLS'
union all
select 1, 'sankar', 'GROUPNG'
union all
select 1, 'sankar', 'GROUPNS'
union all
select 2, 'Srini', 'HYDRSPMLG'
union all
select 2, 'Srini', 'HYDRSPMLS'
union all
select 3, 'Ravi', 'AADSCLS'
union all
select 4, 'Arun', 'RREDFTLS'
union all
select 4, 'Arun', 'RREDFTNG'
union all
select 5, 'Raja', '1234567'
union all
select 5, 'Raja', 'ABCDESLS'
union all
select 5, 'Raja', 'ABCDESLG'
union all
select 6, 'Dhilip', 'GGGGRASCDW_RV'
union all
select 6, 'Dhilip', 'CDW_RV'
union all
select 6, 'Dhilip', 'GFNG'
union all
select 6, 'Dhilip', 'GFNS'
union all
select 7, 'Satya', '184518451845'
select * from #temp
select tp.userid , tp.username, groupname + CASE WHEN tp.flag = 1 THEN CASE WHEN ct.cnt > 1 then ' (' else '' end +
ISNULL(pt.grouptype1,'')+case when grouptype2 is not null
and grouptype1 is not null then ',' else '' end +
ISNULL(pt.grouptype2,'')+case when grouptype3 is not null
and (grouptype1 is not null
or grouptype2 is not null ) then ',' else '' end +
ISNULL(pt.grouptype3,'')+case when grouptype4 is not null
and (grouptype1 is not null
or grouptype2 is not null
or grouptype3 is not null) then ',' else '' end +
ISNULL(pt.grouptype4,'') + case when ct.cnt > 1 then ')' else '' end
ELSE ''
END as Permission
from (SELECT distinct userid , username, CASE WHEN RIGHT(groupname,2) IN ('LG','LS','NG','NS') THEN Substring(groupname,1,len(groupname)-2)
ELSE groupname END as groupname ,
CASE WHEN RIGHT(groupname,2) IN ('LG','LS','NG','NS') THEN 1
ELSE 0 END as flag from #temp ) tp
--WHERE Substring(groupname,1,len(groupname)-2) IN ('LG','LS','NG','NS')
join (select userid , [LG] as grouptype1 , [LS] as grouptype2 , [NG] as grouptype3 ,
[NS] as grouptype4
FROM (SELECT userid , RIGHT(groupname,2) as grouptype FROM #temp) as Sourcetable
PIVOT (MAX(grouptype)
for grouptype in ([LG],[LS],[NG],[NS])) As Pivottable) pt
ON tp.userid = pt.userid
join (select userid, count(*) as cnt from #temp group by userid ) ct
on ct.userid = tp.userid
DROP TABLE #temp
-- Expected Output
-- 1 Sankar GROUP(LG,LS,NG,NS)
-- 2 Srini HYDRSPM(LG,LS)
-- 3 Ravi AADSCLS
-- 4 Arun RREDFT(LS,NG)
-- 5 Raja 1234567
-- 5 Raja ABCDESLG(LG,LS)
-- 6 dhilip GGGGRASCDW_RV
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