I have a column with several empty spaces :
' '
is there a query catch columns with several long spaces only ( I am not talking about null)
I tried this but didnt work
SELECT *
FROM EX_EMPLOYEE
WHERE rtrim(ltrim(F_NAME)) = ''
Do following instead:
SELECT *
FROM EX_EMPLOYEE
WHERE rtrim(ltrim(F_NAME)) IS NULL
select * from EX_EMPLOYEE where ltrim(rtrim(replace(replace(F_NAME,"char"(your_column_lenght),''),"char"(your_column_lenght),''))) = '';
or if that doesnt work, then
where replace(F_NAME,'\x0a','') = '';
I think this is what you need, pls try it out.
You said "several" spaces. If searching for one or more spaces is close enough to your question, this might work:
select count(*) from mytable where mycolumn like "% %"
(note, this is searching only for spaces, not tabs)
Related
I've tried to use CONCAT function of some fields in a table; in order to get a string that I need to compare onto another field from different table.
However when I use the function it's like it random adds spaces between the fields and then I cannot use this result to compare.
I've tried:
SELECT CONCAT([STC_GL-STC].[ZZGL_Desc_Group_5D],'-',
[STC_GL-STC].[ZZCostCentreGroup],'-',
AS RESULT
FROM [STC_GL-STC];
As an example of result:
'Compras - RM -MATERIA PRIMA -'
(Please note the blank spaces in the second and third (-).
I would need to obtain:
'Compras - RM-MATERIA PRIMA-'
I've checked the values in the fields and there is no blank spaces at the end on fields ZZGL_Desc_Group_5D , ZZCostCentreGroup.
I've also tried:
SELECT CONCAT_WS('-',[ZZGL_Desc_Group_5D],[ZZCostCentreGroup]) AS RESULT
FROM [STC_GL-STC]
With same result.
And finally I tried to remove blank spaces using RTRIM and LTRIM using the following:
SELECT CONCAT(LTRIM(RTRIM([STC_GL-STC].[ZZGL_Desc_Group_5D])),
LTRIM(RTRIM('-')),
LTRIM(RTRIM([STC_GL-STC].[ZZCostCentreGroup]))) AS RESULT
FROM [STC_GL-STC]
ORDER BY RESULT ASC;
And even with LTRIM and RTRIM functions on that field, I still getting the same result.
How to get rid of this behaviour and of the blank spaces? Is there another way to build that string?
Kind Regards and many thanks in advance,
Long time ago I created a udf function to remove white spaces.
It is based on the 'magic' of the XML xs:token data type.
udf
/*
1. All invisible TAB, Carriage Return, and Line Feed characters will be replaced with spaces.
2. Then leading and trailing spaces are removed from the value.
3. Further, contiguous occurrences of more than one space will be replaced with a single space.
*/
CREATE FUNCTION dbo.udf_tokenize(#input VARCHAR(MAX))
RETURNS VARCHAR(MAX)
AS
BEGIN
RETURN (SELECT CAST('<r><![CDATA[' + #input + ']]></r>' AS XML).value('(/r/text())[1] cast as xs:token?','VARCHAR(MAX)'));
END
Test harness
-- DDL and sample data population, start
DECLARE #mockTbl TABLE (ID INT IDENTITY(1,1), col_1 VARCHAR(100), col_2 VARCHAR(100));
INSERT INTO #mockTbl (col_1, col_2)
VALUES (' FL ', ' Miami')
, (' FL ', ' Fort Lauderdale ')
, (' NY ', ' New York ')
, (' NY ', '')
, (' NY ', NULL);
-- DDL and sample data population, end
SELECT *
, col_1n = dbo.udf_tokenize(col_1)
, col_2n = dbo.udf_tokenize(col_2)
, CONCAT_WS('-', dbo.udf_tokenize(col_1), dbo.udf_tokenize(col_2)) AS RESULT
FROM #mockTbl;
I want to check if a ID is present or not in a set of multiple ID.
Example
if id 5 is present in multiple id list like '1,2,3,4,5'
use CHARINDEX to return the index of the searched value.
Declare #MyString varchar(50)
Set #MyString = '1,2,3,4,5'
IF CHARINDEX('5',ContactName) > 0
Begin
Print '5 Exists'
End
Else
Begin
Print '5 Does not exists'
End
select count(*) FROM table where id = '5';
If it returns more than 0 means it's present.
If you are talking about sql this query will work for you, if you get nothing it means searching id is not there in the list else there.
SELECT * FROM journal_pulses WHERE mood_credentials in (2,27)
SELECT column FROM table WHERE CHARINDEX(',5,',(',' + column + ',')) > 0
Fiddle
One good solution in this context could be to store the values with leading and trailing comma, as:
',1,2,3,4,5,'
So, even if you store one value, store it as:
',5,'
This will help you look for required value as:
SELECT column FROM table WHERE column like '%,5,%';
Or
SELECT column FROM table WHERE CHARINDEX(',5,',(',' + column + ',')) > 0
Also, using this solution you can uniquely identify different values, given that the string does not contain duplicate values.
So, it is easy to identify 5, 50 and 350 from:
',5,50,150,250,350,450,500,'
I am not sure if you can change how the values can be stored. Please read this answer in light of the context of the question - as a starting point and not as a copy-paste solution.
I have tried something like this
DECLARE #item VARCHAR(50)
SET #ExpressionToSearch = '23,12'
SET #item = '23'
SELECT COUNT(*) from dbo.Split(#ExpressionToSearch,',')
WHERE ',' + (#ExpressionToSearch) + ','
LIKE '%'+#item +'%'
This scenario will return output greater than 0
This is in SQL Server 2005. I have a varchar column and some rows contain trailing space, e.g. abc, def.
I tried removing the trailing space with this command:
update thetable
set thecolumn = rtrim(thecolumn)
But the trailing space remains. I tried to find them using:
select *
from thetable
where thecolumn <> rtrim(thecolumn)
But it returned nothing.
Are there some settings that I am not aware that influences trailing space check?
EDIT:
I know that there is trailing space from SSMS, when I copy paste the value from the grid to the editor, it has trailing space.
Check if the spaces that are not removed have the ASCII code 32.
Try this to replace "hard space" with "soft space":
update thetable set thecolumn = rtrim(replace(thecolumn, char(160), char(32)))
the query was missing equal sign
Are you certain that it is a space (ascii 32) character? You can get odd behavior with other "non-visible" characters. Try running
select ascII(right(theColumn, 1))
from theTable
and see what you get.
Use this Function:
Create Function [dbo].[FullTrim] (#strText varchar(max))
Returns varchar(max) as
Begin
Declare #Ch1 char,#ch2 char
Declare #i int,#LenStr int
Declare #Result varchar(max)
Set #i=1
Set #LenStr=len(#StrText)
Set #Result=''
While #i<=#LenStr
Begin
Set #ch1=SUBSTRING(#StrText,#i,1)
Set #ch2=SUBSTRING(#StrText,#i+1,1)
if ((#ch1=' ' and #ch2=' ') or (len(#Result)=0 and #ch1=' '))
Set #i+=1
Else
Begin
Set #Result+=#Ch1
Set #i+=1
End
End
Return #Result
End
In SQL, CHAR(n) columns are right-padded with spaces to their length.
Also string comparison operators (and most functions too) do not take the trailing spaces into account.
DECLARE #t TABLE (c CHAR(10), vc VARCHAR(10))
INSERT
INTO #t
VALUES ('a ', 'a ')
SELECT LEN(c), LEN(vc), с + vc
FROM #t
--
1 1 "a a"
Please run this query:
SELECT *
FROM thetable
WHERE thecolumn + '|' <> RTRIM(thecolumn) + '|'
and see if it finds something.
It sounds like either:
1) Whatever you are using to view the values is inserting the trailing space (or the appearance thereof- try a fixed-width font like Consolas).
2) The column is CHAR, not VARCHAR. In that case, the column will be padded with spaces up to the length of the column, e.g. inserting 'abc' into char(4) will always result in 'abc '
3) You are somehow not committing the updates, not updating the right column, or other form of user error. The update statement itself looks correct on the face of it.
I had the same issues with RTRIM() AND LTRIM() functions.
In my situation the problem was in LF and CR chars.
Solution
DECLARE #test NVARCHAR(100)
SET #test = 'Declaration status '
SET #test = REPLACE(REPLACE(#test, CHAR(10), ''), CHAR(13), '')
I want to include column in where clause depending on the condition.
e.g
select * From emp
where id=7,
and if(code is not null) then code=8;
how can i do this in sql server
If I understand you correct, you could make use of COALESCE.
COALESCE()
Returns the first nonnull expression
among its arguments.
SQL Statement
SELECT *
FROM emp
WHERE id=7
AND code = COALESCE(#code, code)
If code is a column rather than a variable the query in your question would be rewritten as follows.
SELECT *
FROM emp
WHERE id=7 AND (code IS NULL OR code=8)
You'll probably have to create a query dynamically, as a string, and then use the Execute method to actually execute it. This approach has some potentially optimization issues, but it's commonly done. You might wan to Google T-SQL Dynamic Query, or something like that.
Also use this in case of Null value in #var1.
Select * from ABC where Column1 = isNull(#var1, Column1)
here is the example:
declare #SQL varchar(500)
declare #var1 int
set int = 1
set #SQL = 'Select * from ABC Where 1 = 1'
if(#var1 = 1)
set #SQL + #SQL ' And column1 = ' #var1
exec(#SQL)
You can use COALESCE function.
Well,
I don't know if i understood your question, but i guess that you want to include the value of the code column in the results.
If i'm right it can be done in the select part instead of the where clause. i. e.
Select ..., case when code is not null then 8 else code end as code from emp where id = 7
The other interpretation is that you want to filter rows where code <> 8,that would be
Select * from emp where id = 7 and (code is null OR code = 8)
I am using SQL Server 2005. I have a table with a text column and I have many rows in the table where the value of this column is not null, but it is empty. Trying to compare against '' yields this response:
The data types text and varchar are incompatible in the not equal to operator.
Is there a special function to determine whether the value of a text column is not null but empty?
where datalength(mytextfield)=0
ISNULL(
case textcolum1
WHEN '' THEN NULL
ELSE textcolum1
END
,textcolum2) textcolum1
Actually, you just have to use the LIKE operator.
SELECT * FROM mytable WHERE mytextfield LIKE ''
To get only empty values (and not null values):
SELECT * FROM myTable WHERE myColumn = ''
To get both null and empty values:
SELECT * FROM myTable WHERE myColumn IS NULL OR myColumn = ''
To get only null values:
SELECT * FROM myTable WHERE myColumn IS NULL
To get values other than null and empty:
SELECT * FROM myTable WHERE myColumn <> ''
And remember use LIKE phrases only when necessary because they will degrade performance compared to other types of searches.
SELECT * FROM TABLE
WHERE ISNULL(FIELD, '')=''
Use the IS NULL operator:
Select * from tb_Employee where ename is null
I know this post is ancient but, I found it useful.
It didn't resolve my issue of returning the record with a non empty text field so I thought I would add my solution.
This is the where clause that worked for me.
WHERE xyz LIKE CAST('% %' as text)
Use DATALENGTH method, for example:
SELECT length = DATALENGTH(myField)
FROM myTABLE
Instead of using isnull use a case, because of performance it is better the case.
case when campo is null then '' else campo end
In your issue you need to do this:
case when campo is null then '' else
case when len(campo) = 0 then '' else campo en
end
Code like this:
create table #tabla(
id int,
campo varchar(10)
)
insert into #tabla
values(1,null)
insert into #tabla
values(2,'')
insert into #tabla
values(3,null)
insert into #tabla
values(4,'dato4')
insert into #tabla
values(5,'dato5')
select id, case when campo is null then 'DATA NULL' else
case when len(campo) = 0 then 'DATA EMPTY' else campo end
end
from #tabla
drop table #tabla
I would test against SUBSTRING(textColumn, 0, 1)
Are null and an empty string equivalent? If they are, I would include logic in my application (or maybe a trigger if the app is "out-of-the-box"?) to force the field to be either null or '', but not the other. If you went with '', then you could set the column to NOT NULL as well. Just a data-cleanliness thing.
I wanted to have a predefined text("No Labs Available") to be displayed if the value was null or empty and my friend helped me with this:
StrengthInfo = CASE WHEN ((SELECT COUNT(UnitsOrdered) FROM [Data_Sub_orders].[dbo].[Snappy_Orders_Sub] WHERE IdPatient = #PatientId and IdDrugService = 226)> 0)
THEN cast((S.UnitsOrdered) as varchar(50))
ELSE 'No Labs Available'
END
You have to do both:
SELECT * FROM Table WHERE Text IS NULL or Text LIKE ''
I know there are plenty answers with alternatives to this problem, but I just would like to put together what I found as the best solution by #Eric Z Beard & #Tim Cooper with #Enrique Garcia & #Uli Köhler.
If needed to deal with the fact that space-only could be the same as empty in your use-case scenario, because the query below will return 1, not 0.
SELECT datalength(' ')
Therefore, I would go for something like:
SELECT datalength(RTRIM(LTRIM(ISNULL([TextColumn], ''))))
try this:
select * from mytable where convert(varchar, mycolumn) = ''
i hope help u!
DECLARE #temp as nvarchar(20)
SET #temp = NULL
--SET #temp = ''
--SET #temp = 'Test'
SELECT IIF(ISNULL(#temp,'')='','[Empty]',#temp)
It will do two things:
Null check and string null check
Replace empty value to default value eg NA.
SELECT coalesce(NULLIF(column_name,''),'NA') as 'desired_name') from table;