Replacing even numbers with zero - Infinite loop issue in C [closed] - c

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I've did a program for replacing even numbers with 0 and putting them at the end of the array.
Input: 1 2 3 4 5 6
Output: 1 3 5 0 0 0
The constrains are to use only one loop and two variables apart from the array. I've did it with a while loop but for some unknown reason it loops infinitely. Could someone please clarify?
#include<stdio.h>
#include<stdlib.h>
int main(){
int arr[] = {1,2,3,4,5,6};
int i=0,j=5;
while(i<6){
//Loops till the zero is swapped to the end of the array
if(j!=5){
arr[j] = arr[j] + arr[j+1];
arr[j+1] = arr[j] - arr[j+1];
arr[j] = arr[j] - arr[j+1];
j++; continue;
}
//Checks for even number
if(arr[i]%2==0 && arr[i]!=0){
arr[i]==0;
j=i;
continue;
}
printf("%d ",arr[i]);
i++;
}
return 0;
}

Answer 1

What is causing the infinite loop is this line:
arr[i]==0;
This doesn't update the value of arr[i] when i = 1, so arr[1] is always 2, and this produces that i is stuck always with the value 1. Should be an assignment no a comparison expression:
arr[i]=0;
Note: If you enable the warnings when compiling, the line in question should produce one.